1

我想在以下文件中使用 Linux 中的 ed 编辑器在一行中进行多次替换： 

#device     device      mount       FS  fsck    mount   mount
#to mount   to fsck     point       type    pass    at boot options
#
#/dev/dsk/c0d0s2 /dev/rdsk/c0d0s2 /usr      ufs 1   yes -
fd  -   /dev/fd fd  -   no  -
/proc   -   /proc   proc    -   no  -
/dev/dsk/c0d0s3 -   -   swap    -   no  -
/dev/dsk/c0d0s0 /dev/rdsk/c0d0s0    /   ufs 1   no  -
/dev/dsk/c0d0s4 /dev/rdsk/c0d0s4    /usr    ufs 1   no  -
/dev/dsk/c0d0s1 /dev/rdsk/c0d0s1    /var    ufs 1   yes -
/dev/dsk/c0d0s7 /dev/rdsk/c0d0s7    /export ufs 2   yes -
/dev/dsk/c0d0s5 /dev/rdsk/c0d0s5    /usr/informix   ufs 2   yes -
swap    -   /tmp    tmpfs   -   yes -

我想在/dev/ ... 中将所有“c0”与“c1”交换。

这是我放入 ed: 的正则表达式1,\$s/\(\/dev.*\)\(c0\)\(d0s.*\)/\1c1\3/g，结果 

   #device      device      mount       FS  fsck    mount   mount
    #to mount   to fsck     point       type    pass    at boot options
    #
    #/dev/dsk/c0d0s2 /dev/rdsk/c1d0s2 /usr      ufs 1   yes -
    fd  -   /dev/fd fd  -   no  -
    /proc   -   /proc   proc    -   no  -
    /dev/dsk/c1d0s3 -   -   swap    -   no  -
    /dev/dsk/c0d0s0 /dev/rdsk/c1d0s0    /   ufs 1   no  -
    /dev/dsk/c0d0s4 /dev/rdsk/c1d0s4    /usr    ufs 1   no  -
    /dev/dsk/c0d0s1 /dev/rdsk/c1d0s1    /var    ufs 1   yes -
    /dev/dsk/c0d0s7 /dev/rdsk/c1d0s7    /export ufs 2   yes -
    /dev/dsk/c0d0s5 /dev/rdsk/c1d0s5    /usr/informix   ufs 2   yes -
    swap    -   /tmp    tmpfs   -   yes -

但是，这个长正则表达式：
1,\$s/\(\/dev.*\)\(c0\)\(d0s.*\)\(\/dev.*\)\(c0\)\(d0s.*\)/\1c1\3\4c1\6/g导致： 

#device     device      mount       FS  fsck    mount   mount
#to mount   to fsck     point       type    pass    at boot options
#
#/dev/dsk/c1d0s2 /dev/rdsk/c1d0s2 /usr      ufs 1   yes -
fd  -   /dev/fd fd  -   no  -
/proc   -   /proc   proc    -   no  -
/dev/dsk/c0d0s3 -   -   swap    -   no  -
/dev/dsk/c1d0s0 /dev/rdsk/c1d0s0    /   ufs 1   no  -
/dev/dsk/c1d0s4 /dev/rdsk/c1d0s4    /usr    ufs 1   no  -
/dev/dsk/c1d0s1 /dev/rdsk/c1d0s1    /var    ufs 1   yes -
/dev/dsk/c1d0s7 /dev/rdsk/c1d0s7    /export ufs 2   yes -
/dev/dsk/c1d0s5 /dev/rdsk/c1d0s5    /usr/informix   ufs 2   yes -
swap    -   /tmp    tmpfs   -   yes -

将第一个“c0”保留为“c0”，因为搜索字符串未找到它

所以我得到了一个文件，其中一行中有多个搜索结果，但它只替换了一个实例。我知道“全局”标志在文件的第一步运行并标记匹配行。我希望我知道是什么导致了这个问题，但我没有足够的经验知道如何解决它。
为你的帮助干杯

4

1 回答 1

0

您可以使用该g命令搜索带有dev字符串的行，然后使用s(substitute) 命令和g(global) 标志进行全局替换：

g/\/dev/s/c0/c1/g

给你预期的结果：

#device     device      mount       FS  fsck    mount   mount
#to mount   to fsck     point       type    pass    at boot options
#
#/dev/dsk/c1d0s2 /dev/rdsk/c1d0s2 /usr      ufs 1   yes -
fd  -   /dev/fd fd  -   no  -
/proc   -   /proc   proc    -   no  -
/dev/dsk/c1d0s3 -   -   swap    -   no  -
/dev/dsk/c1d0s0 /dev/rdsk/c1d0s0    /   ufs 1   no  -
/dev/dsk/c1d0s4 /dev/rdsk/c1d0s4    /usr    ufs 1   no  -
/dev/dsk/c1d0s1 /dev/rdsk/c1d0s1    /var    ufs 1   yes -
/dev/dsk/c1d0s7 /dev/rdsk/c1d0s7    /export ufs 2   yes -
/dev/dsk/c1d0s5 /dev/rdsk/c1d0s5    /usr/informix   ufs 2   yes -
swap    -   /tmp    tmpfs   -   yes -
于 2017-06-11T16:08:39.413 回答