我的文件夹中有几个文件assets。我需要将它们全部复制到一个文件夹中，例如 /sdcard/folder。我想从一个线程中做到这一点。我该怎么做？
问问题
207057 次
22 回答
356
如果其他人遇到同样的问题，我就是这样做的
private void copyAssets() {
AssetManager assetManager = getAssets();
String[] files = null;
try {
files = assetManager.list("");
} catch (IOException e) {
Log.e("tag", "Failed to get asset file list.", e);
}
if (files != null) for (String filename : files) {
InputStream in = null;
OutputStream out = null;
try {
in = assetManager.open(filename);
File outFile = new File(getExternalFilesDir(null), filename);
out = new FileOutputStream(outFile);
copyFile(in, out);
} catch(IOException e) {
Log.e("tag", "Failed to copy asset file: " + filename, e);
}
finally {
if (in != null) {
try {
in.close();
} catch (IOException e) {
// NOOP
}
}
if (out != null) {
try {
out.close();
} catch (IOException e) {
// NOOP
}
}
}
}
}
private void copyFile(InputStream in, OutputStream out) throws IOException {
byte[] buffer = new byte[1024];
int read;
while((read = in.read(buffer)) != -1){
out.write(buffer, 0, read);
}
}
参考：使用 Java 移动文件
于 2010-12-25T12:43:07.267 回答
66
根据您的解决方案，我做了自己的事情来允许子文件夹。有人可能会觉得这很有帮助：
...
copyFileOrDir("myrootdir");
...
private void copyFileOrDir(String path) {
AssetManager assetManager = this.getAssets();
String assets[] = null;
try {
assets = assetManager.list(path);
if (assets.length == 0) {
copyFile(path);
} else {
String fullPath = "/data/data/" + this.getPackageName() + "/" + path;
File dir = new File(fullPath);
if (!dir.exists())
dir.mkdir();
for (int i = 0; i < assets.length; ++i) {
copyFileOrDir(path + "/" + assets[i]);
}
}
} catch (IOException ex) {
Log.e("tag", "I/O Exception", ex);
}
}
private void copyFile(String filename) {
AssetManager assetManager = this.getAssets();
InputStream in = null;
OutputStream out = null;
try {
in = assetManager.open(filename);
String newFileName = "/data/data/" + this.getPackageName() + "/" + filename;
out = new FileOutputStream(newFileName);
byte[] buffer = new byte[1024];
int read;
while ((read = in.read(buffer)) != -1) {
out.write(buffer, 0, read);
}
in.close();
in = null;
out.flush();
out.close();
out = null;
} catch (Exception e) {
Log.e("tag", e.getMessage());
}
}
于 2011-09-20T13:52:08.703 回答
50
由于一些错误，上述解决方案不起作用：
- 目录创建不起作用
- Android 返回的 assets 还包含三个文件夹：images、sounds 和 webkit
- 添加了处理大文件的方法：将扩展名 .mp3 添加到项目中 assets 文件夹中的文件中，并且在复制过程中目标文件将没有 .mp3 扩展名
这是代码（我留下了 Log 语句，但您现在可以删除它们）：
final static String TARGET_BASE_PATH = "/sdcard/appname/voices/";
private void copyFilesToSdCard() {
copyFileOrDir(""); // copy all files in assets folder in my project
}
private void copyFileOrDir(String path) {
AssetManager assetManager = this.getAssets();
String assets[] = null;
try {
Log.i("tag", "copyFileOrDir() "+path);
assets = assetManager.list(path);
if (assets.length == 0) {
copyFile(path);
} else {
String fullPath = TARGET_BASE_PATH + path;
Log.i("tag", "path="+fullPath);
File dir = new File(fullPath);
if (!dir.exists() && !path.startsWith("images") && !path.startsWith("sounds") && !path.startsWith("webkit"))
if (!dir.mkdirs())
Log.i("tag", "could not create dir "+fullPath);
for (int i = 0; i < assets.length; ++i) {
String p;
if (path.equals(""))
p = "";
else
p = path + "/";
if (!path.startsWith("images") && !path.startsWith("sounds") && !path.startsWith("webkit"))
copyFileOrDir( p + assets[i]);
}
}
} catch (IOException ex) {
Log.e("tag", "I/O Exception", ex);
}
}
private void copyFile(String filename) {
AssetManager assetManager = this.getAssets();
InputStream in = null;
OutputStream out = null;
String newFileName = null;
try {
Log.i("tag", "copyFile() "+filename);
in = assetManager.open(filename);
if (filename.endsWith(".jpg")) // extension was added to avoid compression on APK file
newFileName = TARGET_BASE_PATH + filename.substring(0, filename.length()-4);
else
newFileName = TARGET_BASE_PATH + filename;
out = new FileOutputStream(newFileName);
byte[] buffer = new byte[1024];
int read;
while ((read = in.read(buffer)) != -1) {
out.write(buffer, 0, read);
}
in.close();
in = null;
out.flush();
out.close();
out = null;
} catch (Exception e) {
Log.e("tag", "Exception in copyFile() of "+newFileName);
Log.e("tag", "Exception in copyFile() "+e.toString());
}
}
编辑：更正了一个错位的“；” 这引发了系统性的“无法创建目录”错误。
于 2011-12-03T06:40:32.110 回答
33
我知道这已经得到解答，但我有一种更优雅的方法可以从资产目录复制到 sdcard 上的文件。它不需要“for”循环，而是使用文件流和通道来完成工作。
（注意）如果使用任何类型的压缩文件，APK，PDF，......您可能需要在插入资产之前重命名文件扩展名，然后在将其复制到 SDcard 后重命名）
AssetManager am = context.getAssets();
AssetFileDescriptor afd = null;
try {
afd = am.openFd( "MyFile.dat");
// Create new file to copy into.
File file = new File(Environment.getExternalStorageDirectory() + java.io.File.separator + "NewFile.dat");
file.createNewFile();
copyFdToFile(afd.getFileDescriptor(), file);
} catch (IOException e) {
e.printStackTrace();
}
一种无需循环即可复制文件的方法。
public static void copyFdToFile(FileDescriptor src, File dst) throws IOException {
FileChannel inChannel = new FileInputStream(src).getChannel();
FileChannel outChannel = new FileOutputStream(dst).getChannel();
try {
inChannel.transferTo(0, inChannel.size(), outChannel);
} finally {
if (inChannel != null)
inChannel.close();
if (outChannel != null)
outChannel.close();
}
}
于 2012-06-26T17:38:33.730 回答
10
这将是 Kotlin 中的简洁方式。
fun AssetManager.copyRecursively(assetPath: String, targetFile: File) {
val list = list(assetPath)
if (list.isEmpty()) { // assetPath is file
open(assetPath).use { input ->
FileOutputStream(targetFile.absolutePath).use { output ->
input.copyTo(output)
output.flush()
}
}
} else { // assetPath is folder
targetFile.delete()
targetFile.mkdir()
list.forEach {
copyRecursively("$assetPath/$it", File(targetFile, it))
}
}
}
于 2019-01-15T05:39:05.350 回答
5
试试这个它更简单，这将帮助你：
// Open your local db as the input stream
InputStream myInput = _context.getAssets().open(YOUR FILE NAME);
// Path to the just created empty db
String outFileName =SDCARD PATH + YOUR FILE NAME;
// Open the empty db as the output stream
OutputStream myOutput = new FileOutputStream(outFileName);
// transfer bytes from the inputfile to the outputfile
byte[] buffer = new byte[1024];
int length;
while ((length = myInput.read(buffer)) > 0) {
myOutput.write(buffer, 0, length);
}
// Close the streams
myOutput.flush();
myOutput.close();
myInput.close();
于 2013-01-11T04:38:34.363 回答
4
这是当前 Android 设备的清理版本，功能方法设计，以便您可以将其复制到 AssetsHelper 类，例如；）
/**
*
* Info: prior to Android 2.3, any compressed asset file with an
* uncompressed size of over 1 MB cannot be read from the APK. So this
* should only be used if the device has android 2.3 or later running!
*
* @param c
* @param targetFolder
* e.g. {@link Environment#getExternalStorageDirectory()}
* @throws Exception
*/
@TargetApi(Build.VERSION_CODES.GINGERBREAD)
public static boolean copyAssets(AssetManager assetManager,
File targetFolder) throws Exception {
Log.i(LOG_TAG, "Copying files from assets to folder " + targetFolder);
return copyAssets(assetManager, "", targetFolder);
}
/**
* The files will be copied at the location targetFolder+path so if you
* enter path="abc" and targetfolder="sdcard" the files will be located in
* "sdcard/abc"
*
* @param assetManager
* @param path
* @param targetFolder
* @return
* @throws Exception
*/
public static boolean copyAssets(AssetManager assetManager, String path,
File targetFolder) throws Exception {
Log.i(LOG_TAG, "Copying " + path + " to " + targetFolder);
String sources[] = assetManager.list(path);
if (sources.length == 0) { // its not a folder, so its a file:
copyAssetFileToFolder(assetManager, path, targetFolder);
} else { // its a folder:
if (path.startsWith("images") || path.startsWith("sounds")
|| path.startsWith("webkit")) {
Log.i(LOG_TAG, " > Skipping " + path);
return false;
}
File targetDir = new File(targetFolder, path);
targetDir.mkdirs();
for (String source : sources) {
String fullSourcePath = path.equals("") ? source : (path
+ File.separator + source);
copyAssets(assetManager, fullSourcePath, targetFolder);
}
}
return true;
}
private static void copyAssetFileToFolder(AssetManager assetManager,
String fullAssetPath, File targetBasePath) throws IOException {
InputStream in = assetManager.open(fullAssetPath);
OutputStream out = new FileOutputStream(new File(targetBasePath,
fullAssetPath));
byte[] buffer = new byte[16 * 1024];
int read;
while ((read = in.read(buffer)) != -1) {
out.write(buffer, 0, read);
}
in.close();
out.flush();
out.close();
}
于 2014-12-02T13:16:11.493 回答
4
@DannyA修改了这个SO答案
private void copyAssets(String path, String outPath) {
AssetManager assetManager = this.getAssets();
String assets[];
try {
assets = assetManager.list(path);
if (assets.length == 0) {
copyFile(path, outPath);
} else {
String fullPath = outPath + "/" + path;
File dir = new File(fullPath);
if (!dir.exists())
if (!dir.mkdir()) Log.e(TAG, "No create external directory: " + dir );
for (String asset : assets) {
copyAssets(path + "/" + asset, outPath);
}
}
} catch (IOException ex) {
Log.e(TAG, "I/O Exception", ex);
}
}
private void copyFile(String filename, String outPath) {
AssetManager assetManager = this.getAssets();
InputStream in;
OutputStream out;
try {
in = assetManager.open(filename);
String newFileName = outPath + "/" + filename;
out = new FileOutputStream(newFileName);
byte[] buffer = new byte[1024];
int read;
while ((read = in.read(buffer)) != -1) {
out.write(buffer, 0, read);
}
in.close();
out.flush();
out.close();
} catch (Exception e) {
Log.e(TAG, e.getMessage());
}
}
准备工作
在src/main/assets
添加名称的文件夹中fold
用法
File outDir = new File(Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS).toString());
copyAssets("fold",outDir.toString());
在外部目录中找到折叠资产中的所有文件和目录
于 2016-08-15T10:49:41.130 回答
3
将所有文件和目录从资产复制到您的文件夹！
为了更好地复制使用 apache commons io
public void doCopyAssets() throws IOException {
File externalFilesDir = context.getExternalFilesDir(null);
doCopy("", externalFilesDir.getPath());
}
//这是复制的主要方法
private void doCopy(String dirName, String outPath) throws IOException {
String[] srcFiles = assets.list(dirName);//for directory
for (String srcFileName : srcFiles) {
String outFileName = outPath + File.separator + srcFileName;
String inFileName = dirName + File.separator + srcFileName;
if (dirName.equals("")) {// for first time
inFileName = srcFileName;
}
try {
InputStream inputStream = assets.open(inFileName);
copyAndClose(inputStream, new FileOutputStream(outFileName));
} catch (IOException e) {//if directory fails exception
new File(outFileName).mkdir();
doCopy(inFileName, outFileName);
}
}
}
public static void closeQuietly(AutoCloseable autoCloseable) {
try {
if(autoCloseable != null) {
autoCloseable.close();
}
} catch(IOException ioe) {
//skip
}
}
public static void copyAndClose(InputStream input, OutputStream output) throws IOException {
copy(input, output);
closeQuietly(input);
closeQuietly(output);
}
public static void copy(InputStream input, OutputStream output) throws IOException {
byte[] buffer = new byte[1024];
int n = 0;
while(-1 != (n = input.read(buffer))) {
output.write(buffer, 0, n);
}
}
于 2013-11-02T19:16:21.927 回答
3
使用这个问题的答案中的一些概念，我编写了一个名为AssetCopier使复制/assets/变得简单的类。它在github上可用，可以通过jitpack.io访问：
new AssetCopier(MainActivity.this)
.withFileScanning()
.copy("tocopy", destDir);
有关更多详细信息，请参阅https://github.com/flipagram/android-assetcopier。
于 2017-02-01T01:37:29.527 回答
2
根据 Yoram Cohen 的回答，这是一个支持非静态目标目录的版本。
调用copyFileOrDir(getDataDir(), "")以写入内部应用程序存储文件夹 /data/data/pkg_name/
- 支持子文件夹。
- 支持自定义和非静态目标目录
避免复制“图像”等虚假资产文件夹，例如
private void copyFileOrDir(String TARGET_BASE_PATH, String path) { AssetManager assetManager = this.getAssets(); String assets[] = null; try { Log.i("tag", "copyFileOrDir() "+path); assets = assetManager.list(path); if (assets.length == 0) { copyFile(TARGET_BASE_PATH, path); } else { String fullPath = TARGET_BASE_PATH + "/" + path; Log.i("tag", "path="+fullPath); File dir = new File(fullPath); if (!dir.exists() && !path.startsWith("images") && !path.startsWith("sounds") && !path.startsWith("webkit")) if (!dir.mkdirs()) Log.i("tag", "could not create dir "+fullPath); for (int i = 0; i < assets.length; ++i) { String p; if (path.equals("")) p = ""; else p = path + "/"; if (!path.startsWith("images") && !path.startsWith("sounds") && !path.startsWith("webkit")) copyFileOrDir(TARGET_BASE_PATH, p + assets[i]); } } } catch (IOException ex) { Log.e("tag", "I/O Exception", ex); } } private void copyFile(String TARGET_BASE_PATH, String filename) { AssetManager assetManager = this.getAssets(); InputStream in = null; OutputStream out = null; String newFileName = null; try { Log.i("tag", "copyFile() "+filename); in = assetManager.open(filename); if (filename.endsWith(".jpg")) // extension was added to avoid compression on APK file newFileName = TARGET_BASE_PATH + "/" + filename.substring(0, filename.length()-4); else newFileName = TARGET_BASE_PATH + "/" + filename; out = new FileOutputStream(newFileName); byte[] buffer = new byte[1024]; int read; while ((read = in.read(buffer)) != -1) { out.write(buffer, 0, read); } in.close(); in = null; out.flush(); out.close(); out = null; } catch (Exception e) { Log.e("tag", "Exception in copyFile() of "+newFileName); Log.e("tag", "Exception in copyFile() "+e.toString()); } }
于 2014-03-29T16:24:19.100 回答
2
基本上有两种方法可以做到这一点。
首先，您可以使用AssetManager.open并按照Rohith Nandakumar的描述对输入流进行迭代。
其次，您可以使用AssetManager.openFd，它允许您使用FileChannel （具有 [transferTo]（https://developer.android.com/reference/java/nio/channels/FileChannel.html#transferTo(long , long, java.nio.channels.WritableByteChannel)) 和 [transferFrom]( https://developer.android.com/reference/java/nio/channels/FileChannel.html#transferFrom(java.nio.channels.ReadableByteChannel , long, long)) 方法），因此您不必自己循环输入流。
我将在这里描述 openFd 方法。
压缩
首先，您需要确保文件未压缩存储。打包系统可能会选择压缩任何扩展名未标记为noCompress的文件，并且压缩后的文件无法进行内存映射，因此在这种情况下您将不得不依赖AssetManager.open。
您可以在文件中添加“.mp3”扩展名以阻止其被压缩，但正确的解决方案是修改您的app/build.gradle文件并添加以下行（以禁用 PDF 文件的压缩）
aaptOptions {
noCompress 'pdf'
}
文件打包
请注意，打包器仍然可以将多个文件打包为一个，因此您不能只读取AssetManager提供给您的整个文件。您需要询问AssetFileDescriptor您需要哪些部分。
找到打包文件的正确部分
确保文件未压缩存储后，您可以使用AssetManager.openFd方法获取AssetFileDescriptor，该方法可用于获取包含FileChannel的FileInputStream（与AssetManager.open不同，后者返回InputStream ） 。它还包含起始偏移量 (getStartOffset)和大小 (getLength)，您需要获取文件的正确部分。
执行
下面给出一个示例实现：
private void copyFileFromAssets(String in_filename, File out_file){
Log.d("copyFileFromAssets", "Copying file '"+in_filename+"' to '"+out_file.toString()+"'");
AssetManager assetManager = getApplicationContext().getAssets();
FileChannel in_chan = null, out_chan = null;
try {
AssetFileDescriptor in_afd = assetManager.openFd(in_filename);
FileInputStream in_stream = in_afd.createInputStream();
in_chan = in_stream.getChannel();
Log.d("copyFileFromAssets", "Asset space in file: start = "+in_afd.getStartOffset()+", length = "+in_afd.getLength());
FileOutputStream out_stream = new FileOutputStream(out_file);
out_chan = out_stream.getChannel();
in_chan.transferTo(in_afd.getStartOffset(), in_afd.getLength(), out_chan);
} catch (IOException ioe){
Log.w("copyFileFromAssets", "Failed to copy file '"+in_filename+"' to external storage:"+ioe.toString());
} finally {
try {
if (in_chan != null) {
in_chan.close();
}
if (out_chan != null) {
out_chan.close();
}
} catch (IOException ioe){}
}
}
此答案基于JPM 的答案。
于 2017-04-12T13:01:09.597 回答
2
基于 Rohith Nandakumar 的解决方案，我自己做了一些事情来从资产的子文件夹（即“assets/ MyFolder ”）中复制文件。另外，在尝试再次复制之前，我正在检查文件是否已存在于 sdcard 中。
private void copyAssets() {
AssetManager assetManager = getAssets();
String[] files = null;
try {
files = assetManager.list("MyFolder");
} catch (IOException e) {
Log.e("tag", "Failed to get asset file list.", e);
}
if (files != null) for (String filename : files) {
InputStream in = null;
OutputStream out = null;
try {
in = assetManager.open("MyFolder/"+filename);
File outFile = new File(getExternalFilesDir(null), filename);
if (!(outFile.exists())) {// File does not exist...
out = new FileOutputStream(outFile);
copyFile(in, out);
}
} catch(IOException e) {
Log.e("tag", "Failed to copy asset file: " + filename, e);
}
finally {
if (in != null) {
try {
in.close();
} catch (IOException e) {
// NOOP
}
}
if (out != null) {
try {
out.close();
} catch (IOException e) {
// NOOP
}
}
}
}
}
private void copyFile(InputStream in, OutputStream out) throws IOException {
byte[] buffer = new byte[1024];
int read;
while((read = in.read(buffer)) != -1){
out.write(buffer, 0, read);
}
}
于 2018-08-16T16:05:20.053 回答
2
您可以使用 Kotlin 分几步完成，这里我只复制几个文件而不是从 asstes 复制所有文件到我的应用程序文件目录。
private fun copyRelatedAssets() {
val assets = arrayOf("myhome.html", "support.css", "myscript.js", "style.css")
assets.forEach {
val inputStream = requireContext().assets.open(it)
val nameSplit = it.split(".")
val name = nameSplit[0]
val extension = nameSplit[1]
val path = inputStream.getFilePath(requireContext().filesDir, name, extension)
Log.v(TAG, path)
}
}
这是扩展功能，
fun InputStream.getFilePath(dir: File, name: String, extension: String): String {
val file = File(dir, "$name.$extension")
val outputStream = FileOutputStream(file)
this.copyTo(outputStream, 4096)
return file.absolutePath
}
LOGCAT
/data/user/0/com.***.***/files/myhome.html
/data/user/0/com.***.***/files/support.css
/data/user/0/com.***.***/files/myscript.js
/data/user/0/com.***.***/files/style.css
于 2020-09-09T12:24:02.043 回答
1
嗨，伙计们，我做了这样的事情。用于第 N 深度复制文件夹和要复制的文件。允许您复制所有目录结构以从 Android AssetManager 复制 :)
private void manageAssetFolderToSDcard()
{
try
{
String arg_assetDir = getApplicationContext().getPackageName();
String arg_destinationDir = FRConstants.ANDROID_DATA + arg_assetDir;
File FolderInCache = new File(arg_destinationDir);
if (!FolderInCache.exists())
{
copyDirorfileFromAssetManager(arg_assetDir, arg_destinationDir);
}
} catch (IOException e1)
{
e1.printStackTrace();
}
}
public String copyDirorfileFromAssetManager(String arg_assetDir, String arg_destinationDir) throws IOException
{
File sd_path = Environment.getExternalStorageDirectory();
String dest_dir_path = sd_path + addLeadingSlash(arg_destinationDir);
File dest_dir = new File(dest_dir_path);
createDir(dest_dir);
AssetManager asset_manager = getApplicationContext().getAssets();
String[] files = asset_manager.list(arg_assetDir);
for (int i = 0; i < files.length; i++)
{
String abs_asset_file_path = addTrailingSlash(arg_assetDir) + files[i];
String sub_files[] = asset_manager.list(abs_asset_file_path);
if (sub_files.length == 0)
{
// It is a file
String dest_file_path = addTrailingSlash(dest_dir_path) + files[i];
copyAssetFile(abs_asset_file_path, dest_file_path);
} else
{
// It is a sub directory
copyDirorfileFromAssetManager(abs_asset_file_path, addTrailingSlash(arg_destinationDir) + files[i]);
}
}
return dest_dir_path;
}
public void copyAssetFile(String assetFilePath, String destinationFilePath) throws IOException
{
InputStream in = getApplicationContext().getAssets().open(assetFilePath);
OutputStream out = new FileOutputStream(destinationFilePath);
byte[] buf = new byte[1024];
int len;
while ((len = in.read(buf)) > 0)
out.write(buf, 0, len);
in.close();
out.close();
}
public String addTrailingSlash(String path)
{
if (path.charAt(path.length() - 1) != '/')
{
path += "/";
}
return path;
}
public String addLeadingSlash(String path)
{
if (path.charAt(0) != '/')
{
path = "/" + path;
}
return path;
}
public void createDir(File dir) throws IOException
{
if (dir.exists())
{
if (!dir.isDirectory())
{
throw new IOException("Can't create directory, a file is in the way");
}
} else
{
dir.mkdirs();
if (!dir.isDirectory())
{
throw new IOException("Unable to create directory");
}
}
}
最后创建一个Asynctask：
private class ManageAssetFolders extends AsyncTask<Void, Void, Void>
{
@Override
protected Void doInBackground(Void... arg0)
{
manageAssetFolderToSDcard();
return null;
}
}
从您的活动中调用它：
new ManageAssetFolders().execute();
于 2014-09-23T06:31:18.640 回答
1
import android.app.Activity;
import android.content.Intent;
import android.content.res.AssetManager;
import android.net.Uri;
import android.os.Environment;
import android.os.Bundle;
import android.util.Log;
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
public class MainActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
copyReadAssets();
}
private void copyReadAssets()
{
AssetManager assetManager = getAssets();
InputStream in = null;
OutputStream out = null;
String strDir = Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS)+ File.separator + "Pdfs";
File fileDir = new File(strDir);
fileDir.mkdirs(); // crear la ruta si no existe
File file = new File(fileDir, "example2.pdf");
try
{
in = assetManager.open("example.pdf"); //leer el archivo de assets
out = new BufferedOutputStream(new FileOutputStream(file)); //crear el archivo
copyFile(in, out);
in.close();
in = null;
out.flush();
out.close();
out = null;
} catch (Exception e)
{
Log.e("tag", e.getMessage());
}
Intent intent = new Intent(Intent.ACTION_VIEW);
intent.setDataAndType(Uri.parse("file://" + Environment.getExternalStoragePublicDirectory(Environment.DIRECTORY_DOWNLOADS) + File.separator + "Pdfs" + "/example2.pdf"), "application/pdf");
startActivity(intent);
}
private void copyFile(InputStream in, OutputStream out) throws IOException
{
byte[] buffer = new byte[1024];
int read;
while ((read = in.read(buffer)) != -1)
{
out.write(buffer, 0, read);
}
}
}
更改部分代码，如下所示：
out = new BufferedOutputStream(new FileOutputStream(file));
前面的示例是针对 Pdfs 的，如果是示例 .txt
FileOutputStream fos = new FileOutputStream(file);
于 2015-05-28T21:36:29.877 回答
1
对上述答案稍作修改，以递归方式复制文件夹并适应自定义目标。
public void copyFileOrDir(String path, String destinationDir) {
AssetManager assetManager = this.getAssets();
String assets[] = null;
try {
assets = assetManager.list(path);
if (assets.length == 0) {
copyFile(path,destinationDir);
} else {
String fullPath = destinationDir + "/" + path;
File dir = new File(fullPath);
if (!dir.exists())
dir.mkdir();
for (int i = 0; i < assets.length; ++i) {
copyFileOrDir(path + "/" + assets[i], destinationDir + path + "/" + assets[i]);
}
}
} catch (IOException ex) {
Log.e("tag", "I/O Exception", ex);
}
}
private void copyFile(String filename, String destinationDir) {
AssetManager assetManager = this.getAssets();
String newFileName = destinationDir + "/" + filename;
InputStream in = null;
OutputStream out = null;
try {
in = assetManager.open(filename);
out = new FileOutputStream(newFileName);
byte[] buffer = new byte[1024];
int read;
while ((read = in.read(buffer)) != -1) {
out.write(buffer, 0, read);
}
in.close();
in = null;
out.flush();
out.close();
out = null;
} catch (Exception e) {
Log.e("tag", e.getMessage());
}
new File(newFileName).setExecutable(true, false);
}
于 2016-07-19T16:37:13.893 回答
1
对于那些正在更新到 Kotlin 的人：
按照此步骤避免FileUriExposedExceptions，假设用户已授予WRITE_EXTERNAL_STORAGE权限并且您的文件位于assets/pdfs/mypdf.pdf.
private fun openFile() {
var inputStream: InputStream? = null
var outputStream: OutputStream? = null
try {
val file = File("${activity.getExternalFilesDir(null)}/$PDF_FILE_NAME")
if (!file.exists()) {
inputStream = activity.assets.open("$PDF_ASSETS_PATH/$PDF_FILE_NAME")
outputStream = FileOutputStream(file)
copyFile(inputStream, outputStream)
}
val uri = FileProvider.getUriForFile(
activity,
"${BuildConfig.APPLICATION_ID}.provider.GenericFileProvider",
file
)
val intent = Intent(Intent.ACTION_VIEW).apply {
setDataAndType(uri, "application/pdf")
addFlags(Intent.FLAG_GRANT_READ_URI_PERMISSION)
addFlags(Intent.FLAG_ACTIVITY_NO_HISTORY)
}
activity.startActivity(intent)
} catch (ex: IOException) {
ex.printStackTrace()
} catch (ex: ActivityNotFoundException) {
ex.printStackTrace()
} finally {
inputStream?.close()
outputStream?.flush()
outputStream?.close()
}
}
@Throws(IOException::class)
private fun copyFile(input: InputStream, output: OutputStream) {
val buffer = ByteArray(1024)
var read: Int = input.read(buffer)
while (read != -1) {
output.write(buffer, 0, read)
read = input.read(buffer)
}
}
companion object {
private const val PDF_ASSETS_PATH = "pdfs"
private const val PDF_FILE_NAME = "mypdf.pdf"
}
于 2018-12-31T11:56:13.613 回答
1
那是我的个性化文本提取器类，希望有用。
package lorenzo.morelli.platedetector;
import android.content.Context;
import android.content.res.AssetManager;
import android.graphics.Bitmap;
import com.googlecode.tesseract.android.TessBaseAPI;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
public class TextExtractor {
private final Context context;
private final String dirName;
private final String language;
public TextExtractor(final Context context, final String dirName, final String language) {
this.context = context;
this.dirName = dirName;
this.language = language;
}
public String extractText(final Bitmap bitmap) {
final TessBaseAPI tessBaseApi = new TessBaseAPI();
final String datapath = this.context.getFilesDir()+ "/tesseract/";
checkFile(new File(datapath + this.dirName + "/"), datapath, this.dirName, this.language);
tessBaseApi.init(datapath, this.language);
tessBaseApi.setImage(bitmap);
final String extractedText = tessBaseApi.getUTF8Text();
tessBaseApi.end();
return extractedText;
}
private void checkFile(final File dir, final String datapath, final String dirName, final String language) {
//directory does not exist, but we can successfully create it
if (!dir.exists()&& dir.mkdirs()) {
copyFiles(datapath, dirName, language);
} //The directory exists, but there is no data file in it
if(dir.exists()) {
final String datafilepath = datapath + "/" + dirName + "/" + language + ".traineddata";
final File datafile = new File(datafilepath);
if (!datafile.exists()) {
copyFiles(datapath, dirName, language);
}
}
}
private void copyFiles(final String datapath, final String dirName, final String language) {
try {
//location we want the file to be at
final String filepath = datapath + "/" + dirName + "/" + language + ".traineddata";
//get access to AssetManager
final AssetManager assetManager = this.context.getAssets();
//open byte streams for reading/writing
final InputStream instream = assetManager.open(dirName + "/" + language + ".traineddata");
final OutputStream outstream = new FileOutputStream(filepath);
//copy the file to the location specified by filepath
byte[] buffer = new byte[1024];
int read;
while ((read = instream.read(buffer)) != -1) {
outstream.write(buffer, 0, read);
}
outstream.flush();
outstream.close();
instream.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
要使用它，您需要经过训练的数据文件。您可以从此链接下载 trainddata 文件。
一旦你下载了你想要的训练数据文件，你需要在你的 android 项目中创建一个名为 assets 的 Android 资源目录。在新创建的资产文件夹中，您需要创建一个名为“tessdata”的常规目录，您可以在其中放置您的训练数据文件。最后，您必须在 MainActivity 中初始化“TextExtractor”类。
final TextExtractor textExtractor = new TextExtractor(this, "tessdata", "eng");
第一个参数是上下文，第二个是刚刚创建的目录的名称，最后一个是刚刚下载的训练数据的语言。
要提取文本，您必须调用“extractText”方法：
final String text = textExtractor.extractText(imageWithText);
请注意，extractText 需要一个位图图像才能工作！！您可以使用以下行从您的可绘制文件创建位图图像：
final BitMap image = BitmapFactory.decodeResource(getResources(), R.drawable.test_image);
如果您需要更多支持，我建议您遵循这个有用的指南：https ://github.com/SamVanRoy/Android_OCR_App
于 2020-08-19T13:38:25.003 回答
0
使用AssetManager，它允许读取资产中的文件。然后使用常规 Java IO 将文件写入 sdcard。
谷歌是你的朋友，搜索一个例子。
于 2010-12-15T07:25:14.223 回答
0
这是迄今为止我在互联网上找到的最好的解决方案。我使用了以下链接https://gist.github.com/mhasby/026f02b33fcc4207b302a60645f6e217，
但是我修复了一个错误，然后它就像一个魅力。这是我的代码。您可以轻松使用它，因为它是一个独立的 java 类。
public class CopyAssets {
public static void copyAssets(Context context) {
AssetManager assetManager = context.getAssets();
String[] files = null;
try {
files = assetManager.list("");
} catch (IOException e) {
Log.e("tag", "Failed to get asset file list.", e);
}
if (files != null) for (String filename : files) {
InputStream in = null;
OutputStream out = null;
try {
in = assetManager.open(filename);
out = new FileOutputStream(Environment.getExternalStorageDirectory()+"/www/resources/" + filename);
copyFile(in, out);
} catch(IOException e) {
Log.e("tag", "Failed to copy asset file: " + filename, e);
}
finally {
if (in != null) {
try {
in.close();
in = null;
} catch (IOException e) {
}
}
if (out != null) {
try {
out.flush();
out.close();
out = null;
} catch (IOException e) {
}
}
}
}
}
public static void copyFile(InputStream in, OutputStream out) throws IOException {
byte[] buffer = new byte[1024];
int read;
while((read = in.read(buffer)) != -1){
out.write(buffer, 0, read);
}
}}
如您所见，只需CopyAssets在具有活动的 java 类中创建一个实例。现在这部分很重要，就我在互联网上的测试和研究而言，You cannot use AssetManager if the class has no activity. 它与java类的上下文有关。
现在，这c.copyAssets(getApplicationContext())是一种访问方法的简单方法，其中c是CopyAssets类的实例和实例。根据我的要求，我允许程序将文件asset夹内的所有资源文件复制到/www/resources/我的内部目录中。
您可以根据使用情况轻松找到需要对目录进行更改的部分。如果您需要任何帮助，请随时 ping 我。
于 2018-05-31T10:05:35.070 回答
0
您还可以使用 GuavaByteStream将文件从 assets 文件夹复制到 SD 卡。这是我最终得到的解决方案，它将文件从资产文件夹递归地复制到 SD 卡：
/**
* Copies all assets in an assets directory to the SD file system.
*/
public class CopyAssetsToSDHelper {
public static void copyAssets(String assetDir, String targetDir, Context context)
throws IOException {
AssetManager assets = context.getAssets();
String[] list = assets.list(assetDir);
for (String f : Objects.requireNonNull(list)) {
if (f.indexOf(".") > 1) { // check, if this is a file
File outFile = new File(context.getExternalFilesDir(null),
String.format("%s/%s", targetDir, f));
File parentFile = outFile.getParentFile();
if (!Objects.requireNonNull(parentFile).exists()) {
if (!parentFile.mkdirs()) {
throw new IOException(String.format("Could not create directory %s.",
parentFile));
}
}
try (InputStream fin = assets.open(String.format("%s/%s", assetDir, f));
OutputStream fout = new FileOutputStream(outFile)) {
ByteStreams.copy(fin, fout);
}
} else { // This is a directory
copyAssets(String.format("%s/%s", assetDir, f), String.format("%s/%s", targetDir, f),
context);
}
}
}
}
于 2020-07-10T09:27:00.420 回答