19

有没有办法获取UITouch与手势关联的对象？UIGestureRecognizer似乎没有任何方法。

4

6 回答 6

14

杰是对的……你会想要一个子类。试试这个尺寸，它来自我的一个项目。在 DragGestureRecognizer.h 中：

@interface DragGestureRecognizer : UILongPressGestureRecognizer {

}

- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event;

@end

@protocol DragGestureRecognizerDelegate <UIGestureRecognizerDelegate>
- (void) gestureRecognizer:(UIGestureRecognizer *)gr movedWithTouches:(NSSet*)touches andEvent:(UIEvent *)event;
@end

在 DragGestureRecognizer.m 中：

#import "DragGestureRecognizer.h"


@implementation DragGestureRecognizer

- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event {

    [super touchesMoved:touches withEvent:event];

    if ([self.delegate respondsToSelector:@selector(gestureRecognizer:movedWithTouches:andEvent:)]) {
        [(id)self.delegate gestureRecognizer:self movedWithTouches:touches andEvent:event];
    }

}

@end

当然，你需要实现

- (void) gestureRecognizer:(UIGestureRecognizer *)gr movedWithTouches:(NSSet*)touches andEvent:(UIEvent *)event;

委托中的方法——例如：

DragGestureRecognizer * gr = [[DragGestureRecognizer alloc] initWithTarget:self action:@selector(pressed:)];
gr.minimumPressDuration = 0.15;
gr.delegate = self;
[self.view addGestureRecognizer:gr];
[gr release];



- (void) gestureRecognizer:(UIGestureRecognizer *)gr movedWithTouches:(NSSet*)touches andEvent:(UIEvent *)event{

    UITouch * touch = [touches anyObject];
    self.mTouchPoint = [touch locationInView:self.view];
    self.mFingerCount = [touches count];

}
于 2010-12-16T10:10:02.917 回答
6

如果只是你感兴趣的位置，你不必子类化，你会从 UIGestureRecognizer 中收到点击位置变化的通知。

用目标初始化：

self.longPressGestureRecognizer = [[[UILongPressGestureRecognizer alloc] initWithTarget: self action: @selector(handleGesture:)] autorelease];
[self.tableView addGestureRecognizer: longPressGestureRecognizer];

处理 UIGestureRecognizerStateChanged 以获取位置更改：

- (void)handleGesture: (UIGestureRecognizer *)theGestureRecognizer {
    switch (theGestureRecognizer.state) {
        case UIGestureRecognizerStateBegan:
        case UIGestureRecognizerStateChanged:
        {
            CGPoint location = [theGestureRecognizer locationInView: self.tableView];

            [self infoForLocation: location];

            break;
        }

        case UIGestureRecognizerStateEnded:
        {
            NSLog(@"Ended");

            break;
        }

        default:
            break;
    }
}
于 2012-06-01T12:53:03.783 回答
3

如果您只需要找出手势的位置，您可以在 UIGestureRecognizer 对象上调用 locationInView: 或 locationOfTouch:inView:。但是，如果您想做其他任何事情，则需要子类化。

于 2011-11-16T16:28:38.767 回答
1

如果您正在编写自己的 UIGestureRecognizer ，则可以覆盖触摸对象：

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event

或同等的移动、结束或取消

Apple 文档有很多关于子类化的信息

于 2010-12-15T05:21:30.763 回答
0

这是一种将长按添加到任意 UIView 的方法。

这使您可以在任意数量的 UIView 上运行 longpress。在此示例中，我通过标签限制对 UIView 方法的访问，但您也可以使用 isKindOfClass。

（从我发现你必须为 LongPress 使用 touchesMoved 因为 touchesBegan 在 LongPress 激活之前触发）

子类 - .h

            #import <UIKit/UIKit.h>
            #import <UIKit/UIGestureRecognizerSubclass.h>

            @interface MyLongPressGestureRecognizer : UILongPressGestureRecognizer

            - (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event;

            @property (nonatomic) CGPoint touchPoint;
            @property (strong, nonatomic) UIView* touchView;

            @end

子类 - .m

            #import "MyLongPress.h"

            @implementation MyLongPressGestureRecognizer

            - (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event;
            {
                UITouch * touch = [touches anyObject];
                self.touchPoint = [touch locationInView:self.view];
                self.touchView  = [self.view hitTest:[touch locationInView:self.view] withEvent:event];
            }

            #pragma mark - Setters

            -(void) setTouchPoint:(CGPoint)touchPoint
            {
                _touchPoint =touchPoint;
            }

            -(void) setTouchView:(UIView*)touchView
            {
                _touchView=touchView;
            }
            @end

视图控制器 - .h

                           //nothing special here

视图控制器 - .m

            #import "ViewController.h"
            //LOAD
            #import "MyLongPress.h"

            @interface ViewController ()

            //lOAD
            @property (strong, nonatomic) MyLongPressGestureRecognizer* longPressGesture;

            @end

            @implementation PDViewController

            - (void)viewDidLoad
            {
                [super viewDidLoad];

                //LOAD
                self.longPressGesture =[[MyLongPressGestureRecognizer alloc] initWithTarget:self action:@selector(longPressHandler:)];
                self.longPressGesture.minimumPressDuration = 1.2;
                [[self view] addGestureRecognizer:self.longPressGesture];
            }               

            //LOAD
            -(void) setLongPressGesture:(MyLongPressGestureRecognizer *)longPressGesture {
                _longPressGesture = longPressGesture;
            }

            - (void)longPressHandler:(MyLongPressGestureRecognizer *)recognizer {
                    if (self.longPressGesture.touchView.tag >= 100) /* arbitrary method for limiting tap */
                    {
                        //code goes here
                    }
            }
于 2013-03-27T13:56:01.960 回答
-2

简单快速：

NSArray *touches = [recognizer valueForKey:@"touches"];

识别器在哪里UIGestureRecognizer

于 2014-04-29T17:44:14.433 回答