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我想删除以图形方式显示的文本，这样我就可以编写新文本而不会重叠。我在下面包含了我的代码。再次感谢您的宝贵时间。

from graphics import*
import random

# Function for winning
def youwin():
    txt = Text(Point(250,100), "You are a Winner!")
    txt.setTextColor(color_rgb(0,255,200))
    txt.setSize(30)
    txt.setFace('courier')
    txt.draw(win)

# Function for losing    
def youlose():

txt= Text(Point(250,100), "You are a Loser!")
txt.setTextColor(color_rgb(0,255,0))
txt.setSize(30)
txt.setFace('courier')
txt.draw(win)


# Sets a Window
win = GraphWin("My Window", 800, 600)
win.setBackground('White')

# loops 10 Times and picks out 3 random gif's.
# Then displays each image on the screen in a row.

for x in range(10):

cards = ["1.png","2.png","3.png"]
rand_card1 = random.choice(cards)      
img1 = Image(Point(100, 250), rand_card1)
rand_card2 = random.choice(cards)
img2 = Image(Point(300, 250), rand_card2)
rand_card3 = random.choice(cards)
img3 = Image(Point(500, 250), rand_card3)


img1.draw(win) 
img2.draw(win)
img3.draw(win)

# checks to see if you are a winner

if rand_card1 == rand_card2 and rand_card2 == rand_card3:
    youwin()
else:
    youlose()


# waits for a mouse click.  In the future this will be a button.    
win.getMouse()    
img1.undraw()
img2.undraw()
img3.undraw()



#win.close()#

这是我目前得到的输出：

双文本输出到屏幕

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2 回答 2

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我认为您可能想在绘制新文本之前以某种方式清除绘图区域。一种方法是在旧文本上绘制一个与背景颜色相同的矩形。

于 2017-06-11T01:03:17.690 回答
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我想删除以图形方式显示的文本，以便编写新文本

不。您可以通过 重用文本对象setText()。一个简单的例子：

import time  # just for demonstration
from graphics import *

win = GraphWin("My Window", 800, 600)

txt = Text(Point(250,100), "You are a Loser!")
txt.setSize(30)
txt.draw(win)

time.sleep(3)

txt.setText("You are a Winner!")

time.sleep(3)

如果您希望文本消失一段时间，txt.setText('')直到您再次需要它为止。

于 2017-06-08T17:13:16.280 回答