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我正在尝试使用 lttng 来分析远程系统上的调度。但是，使用 babeltrace 将跟踪显示为文本格式表明所有记录的事件都具有相同的时间戳。因此，TraceCompass 中的可视化失败。

thomas@horrorshow: babeltrace ~/temp/lttng/my-trace/MySystem/my-session-20170608-133943/ | head
[13:41:59.444999936] (+?.?????????) MySystem sched_stat_runtime: { cpu_id = 0 }, { comm = "lttng-sessiond", tid = 1533, runtime = 5016120, vruntime = 451268995605 }
[13:41:59.444999936] (+0.000000000) MySystem sched_waking: { cpu_id = 0 }, { comm = "lttng-consumerd", tid = 1547, prio = 20, target_cpu = 0 }
[13:41:59.444999936] (+0.000000000) MySystem sched_stat_runtime: { cpu_id = 0 }, { comm = "lttng-sessiond", tid = 1533, runtime = 276632, vruntime = 451269272237 }
[13:41:59.444999936] (+0.000000000) MySystem sched_wakeup: { cpu_id = 0 }, { comm = "lttng-consumerd", tid = 1547, prio = 20, target_cpu = 0 }
[13:41:59.444999936] (+0.000000000) MySystem sched_switch: { cpu_id = 0 }, { prev_comm = "lttng-sessiond", prev_tid = 1533, prev_prio = 20, prev_state = 4096, next_comm = "lttng-consumerd", next_tid = 1547, next_prio = 20 }
[13:41:59.444999936] (+0.000000000) MySystem syscall_exit_epoll_wait: { cpu_id = 0 }, { ret = 1, fds_length = 1, overflow = 0, fds = [ [0] = { data_union = { u64 = 0x1C, fd = 28 }, raw_events = 0x1, events = { EPOLLIN = 1, EPOLLPRI = 0, EPOLLOUT = 0, EPOLLERR = 0, padding = 0 } } ] }
[13:41:59.444999936] (+0.000000000) MySystem syscall_entry_ioctl: { cpu_id = 0 }, { fd = 28, cmd = 62981, arg = 1547 }
[13:41:59.444999936] (+0.000000000) MySystem syscall_exit_ioctl: { cpu_id = 0 }, { ret = 0, arg = 1547 }
[13:41:59.444999936] (+0.000000000) MySystem syscall_entry_ioctl: { cpu_id = 0 }, { fd = 28, cmd = 2147808776, arg = 3047156396 }
[13:41:59.444999936] (+0.000000000) MySystem syscall_exit_ioctl: { cpu_id = 0 }, { ret = 0, arg = 3047156396 }

thomas@horrorshow: babeltrace ~/temp/lttng/my-trace/MySystem/my-session-20170608-133943/ | tail
[13:41:59.444999936] (+0.000000000) MySystem sched_wakeup: { cpu_id = 0 }, { comm = "rcu_preempt", tid = 7, prio = 20, target_cpu = 0 }
[13:41:59.444999936] (+0.000000000) MySystem sched_switch: { cpu_id = 0 }, { prev_comm = "lttng", prev_tid = 1698, prev_prio = 20, prev_state = 4096, next_comm = "rcu_preempt", next_tid = 7, next_prio = 20 }
[13:41:59.444999936] (+0.000000000) MySystem sched_stat_runtime: { cpu_id = 0 }, { comm = "rcu_preempt", tid = 7, runtime = 128301, vruntime = 456917982563 }
[13:41:59.444999936] (+0.000000000) MySystem sched_switch: { cpu_id = 0 }, { prev_comm = "rcu_preempt", prev_tid = 7, prev_prio = 20, prev_state = 1, next_comm = "lttng", next_tid = 1698, next_prio = 20 }
[13:41:59.444999936] (+0.000000000) MySystem sched_waking: { cpu_id = 0 }, { comm = "lttng-sessiond", tid = 1533, prio = 20, target_cpu = 0 }
[13:41:59.444999936] (+0.000000000) MySystem sched_stat_runtime: { cpu_id = 0 }, { comm = "lttng", tid = 1698, runtime = 209068, vruntime = 456921063330 }
[13:41:59.444999936] (+0.000000000) MySystem sched_wakeup: { cpu_id = 0 }, { comm = "lttng-sessiond", tid = 1533, prio = 20, target_cpu = 0 }
[13:41:59.444999936] (+0.000000000) MySystem sched_switch: { cpu_id = 0 }, { prev_comm = "lttng", prev_tid = 1698, prev_prio = 20, prev_state = 4096, next_comm = "lttng-sessiond", next_tid = 1533, next_prio = 20 }
[13:41:59.444999936] (+0.000000000) MySystem syscall_exit_recvmsg: { cpu_id = 0 }, { ret = 13156, msg = 3046107868 }
[13:41:59.444999936] (+0.000000000) MySystem syscall_entry_ioctl: { cpu_id = 0 }, { fd = 31, cmd = 63063, arg = 17 }

跟踪运行了几秒钟，大小为 912K。我使用以下命令在嵌入式 Linux 设备上启动跟踪，lttng-relayd用于将数据传输到我的主机系统进行分析：

lttng create my-session --set-url=net://10.0.28.1
lttng enable-channel --kernel --subbuf-size=2621440 channel0
lttng enable-event --kernel --syscall --all --channel channel0
lttng enable-event --kernel --channel channel0 sched* 
lttng start
# Wait a bit
lttng stop

如何修复时间戳？

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1 回答 1

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lttng-dev 邮件列表中的人为我解决了这个问题：我不小心为假测试时钟加载了内核模块，而不是为真实时钟加载了内核模块。

我的错误是我手动运行了 lttng 提供的insmod所有文件。.ko但是，正确的方法是让lttng-sessiond模块自动加载，这将忽略伪造的测试时钟模块。depmod -a自动模块加载对我来说失败了，因为我在安装内核模块后没有运行。

之后depmod -a，一切正常，时间戳正确。

于 2017-06-13T09:42:01.570 回答