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我想用相应的声音突出显示特定的段落/列表。

responsivevoice.js 中是否有任何回调。我将 onend 作为回调函数。但它不起作用。

每当我放置 console 而不是 highlight 时,它只会产生一个而不是三个。

我认为 onend 只在第一个 para 之后调用。但它应该适用于所有 para/ul

请帮帮我。。

我的代码:-

 <!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script src="http://code.responsivevoice.org/develop/1.5.2/responsivevoice.js"></script>

<script>
var currentDataValue =0;
$( document ).ready(function(){
    $("#1").click(function(){
        $("p,ul").each(function( index, element){
           responsiveVoice.speak($(this).text(),$('UK English Female').val(),{
        pitch: .7,
        onend: function() {
          $(this).css( "backgroundColor", "yellow" );

        }
        });

        });
    });
});

$( document ).ready(function(){
    $("#2").click(function(){
         responsiveVoice.pause();
    });
});
$( document ).ready(function(){
    $("#3").click(function(){
         responsiveVoice.resume();
    });
});
$(window).load(function(){
    $("#4").click(function(){
         responsiveVoice.cancel();
    });
});
</script>
</head>
<body>

<h2>This is a heading</h2>
<p>This is a paragraph.</p>
<ul>
<li>this unoder list </li>
</ul>
<p id="test">This is another paragraph.</p>
<button id="1">start</button>
<button id="2">pause</button>
<button id="3">resume</button>
<button id="4">stop</button>
</body>
</html>
4

1 回答 1

1

好吧,这个 ResponsiveVoice 是一个有 bug 的商业库,它为回调设置了单个变量,所以它只调用最后配置的回调,而不是全部。您当然可以修改库,也可以像这样一个一个地调用项目:

$("#1").click(function(){

    var elements = $("p, ul");
    speak = function(i, elements) {
        responsiveVoice.speak($(elements[i]).text(),$('UK English Female').val(),{
            pitch: .7,
            onend: function() {
                $(elements[i]).css("backgroundColor", "yellow");
                if (i < elements.length) {
                    speak(i + 1, elements);
                }
            }
        });
    };
    speak(0, elements);
});

我会像这样简单地使用 Chrome API:

var currentDataValue =0;
$( document ).ready(function(){
    $("#1").click(function(){
    var voice = speechSynthesis.getVoices().filter(function(voice){return voice.name == 'Allison'; })[0];
        $("p,ul").each(function(index, element) {
             u = new SpeechSynthesisUtterance($(this).text());
             u.voice = voice;
             u.onend = (function() {
                  console.log("Here");
                  $(this).css( "background-color", "yellow" );
             }).bind($(this));
             speechSynthesis.speak(u);
        });
    });
});
于 2017-06-18T10:47:26.217 回答