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我正在关注有关使用 gData Youtube API 使用 PHP 进行直接上传的文档。我可以成功上传视频，一切都很好。我无法弄清楚的部分，如果它甚至可能获得一些上传进度状态，如完成百分比或上传的字节数。

这是上传发生的代码片段。

 <?php 
try {
      $newEntry = $yt->insertEntry($myVideoEntry, $uploadUrl, 'Zend_Gdata_YouTube_VideoEntry');
    } catch (Zend_Gdata_App_HttpException $httpException) {
      echo $httpException->getRawResponseBody();
    } catch (Zend_Gdata_App_Exception $e) {
        echo $e->getMessage();
    }
?>

有人知道如何在$progess上传时更新变量或其他内容吗？

4

1 回答 1

5

演示网址：--

http://jquery.malsup.com/form/progress.html

您可以在 url 下面下载 jquery 文件并添加 html 标签

http://ajax.googleapis.com/ajax/libs/jquery/1.7/jquery.js

http://malsup.github.com/jquery.form.js

尝试这个： -

输出视频：-

在此处输入图像描述

这是我的 video.php 文件

<!doctype html>
<head>
<title>File Upload Progress Demo #1</title>
<style>
body { padding: 30px }
form { display: block; margin: 20px auto; background: #eee; border-radius: 10px; padding: 15px }

.progress { position:relative; width:400px; border: 1px solid #ddd; padding: 1px; border-radius: 3px; }
.bar { background-color: #B4F5B4; width:0%; height:20px; border-radius: 3px; }
.percent { position:absolute; display:inline-block; top:3px; left:48%; }
</style>
</head>
<body>
    <h1>File Upload Progress Demo #1</h1>
    <code>&lt;input type="file" name="myfile"></code>
        <form action="video_upload.php" method="post" enctype="multipart/form-data">
        <input type="file" name="uploadedfile"><br>
        <input type="submit" value="Upload File to Server">
    </form>

    <div class="progress">
        <div class="bar"></div >
        <div class="percent">0%</div >
    </div>

    <div id="status"></div>

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7/jquery.js"></script>
<script src="http://malsup.github.com/jquery.form.js"></script>
<script>
(function() {

var bar = $('.bar');
var percent = $('.percent');
var status = $('#status');

$('form').ajaxForm({
    beforeSend: function() {
        status.empty();
        var percentVal = '0%';
        bar.width(percentVal)
        percent.html(percentVal);
    },
    uploadProgress: function(event, position, total, percentComplete) {
        var percentVal = percentComplete + '%';
        bar.width(percentVal)
        percent.html(percentVal);
    },
    complete: function(xhr) {
        bar.width("100%");
        percent.html("100%");
        status.html(xhr.responseText);
    }
}); 

})();       
</script>

</body>
</html>

这是我的 video_upload.php 文件

<?php
// video_upload.php


require_once 'Zend/Loader.php'; // the Zend dir must be in your include_path
Zend_Loader::loadClass('Zend_Gdata_YouTube');
$yt = new Zend_Gdata_YouTube();

// Define the authentication that will be used
Zend_Loader::loadClass('Zend_Gdata_ClientLogin'); 

// Authenticate
$authenticationURL= 'https://www.google.com/accounts/ClientLogin';
$httpClient = 
  Zend_Gdata_ClientLogin::getHttpClient(
              $username = "USERNAME",
              $password = "PASSWORD",
              $service = 'youtube',
              $client = null,
              $source = 'HTML SOURCE CODE SNIPPET',
              $loginToken = null,
              $loginCaptcha = null,
              $authenticationURL);

$applicationId = 'YOUR APPLICATION ID';
$clientId = 'Upload videos to youtube using the youtube API';
$developerKey = 'YOUR DEVELOPER KEY';
$yt = new Zend_Gdata_YouTube($httpClient, $applicationId, $clientId, $developerKey);



// create a new VideoEntry object
$myVideoEntry = new Zend_Gdata_YouTube_VideoEntry();

$myVideoEntry->setVideoTitle($videoTitle);
$myVideoEntry->setVideoDescription($VideoDescription);
// The category must be a valid YouTube category!
$myVideoEntry->setVideoCategory($VideoCategory);

// Set keywords. Please note that this must be a comma-separated string
// and that individual keywords cannot contain whitespace
$myVideoEntry->SetVideoTags($VideoTags);

$tokenHandlerUrl = 'http://gdata.youtube.com/action/GetUploadToken';
$tokenArray = $yt->getFormUploadToken($myVideoEntry, $tokenHandlerUrl);
$tokenValue = $tokenArray['token'];
$postUrl = $tokenArray['url'];


$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $postUrl."?nexturl=http://YOUR_WEBPAGE.com/");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLINFO_HEADER_OUT, true);
curl_setopt($ch, CURLOPT_POST, true);
// same as <input type="file" name="file">
$post = array("file"=>"@".$VideoFile['tmp_name'], "token"=>$tokenValue);
curl_setopt($ch, CURLOPT_POSTFIELDS, $post); 
$response = curl_exec($ch);
$info = curl_getinfo($ch);

echo $info;

?>
于 2012-08-15T13:44:20.423 回答