1

我是 symfony 中单元测试的新手,而且我很烦人,因为我遇到了一个问题,我花了 1 个小时来确定。

希望你们会知道为什么会发生这种情况。

所以我正在测试我的“搜索”方法:

class TadalistTable extends Doctrine_Table
{
  public function search($query, $user_id)
  {
     $q = $this->createQuery('t')
     ->leftJoin('t.Notes n')
     ->where('n.name LIKE ?', '%'.$query.'%')
     ->andWhere('t.user_id = ?', $user_id);
     return $q->execute();
  }
}

它在我的网站上运行良好,但是当我像这样测试它时:

//Create two notes, one called "Test Note" and one called "Test Note2" in the same list

//Start test :
$searchTest = Doctrine_Core::getTable('Tadalist')->search('Test', $user->getId());
$searchNote2 = Doctrine_Core::getTable('Tadalist')->search('noTe2', $user->getId());

$t->is(count($searchTest), 1, 'Searching "Test" returned 1 list');
$t->is(count($searchTest[0]->Notes), 2, 'Searching "Test" returned 2 notes');
$t->is(count($searchNote2), 1, 'Searching "noTe2" returned 1 list');
$t->is(count($searchNote2[0]->Notes), 1, 'Searching "noTe2" returned 1 note');

第二次测试失败:

ok 20 - Searching Test returned 1 list
not ok 21 - Searching Test returned 2 notes
# Failed test (./test/unit/Model/TadalistTest.php at line 90)
# got: 1
# expected: 2
ok 22 - Searching noTe2 returned 1 list
ok 23 - Searching noTe2 returned 1 note

但是,如果我只是更改顺序:

//Create two notes, one called "Test Note" and one called "Test Note2" in the same list

$searchTest = Doctrine_Core::getTable('Tadalist')->search('Test', $user->getId());
$t->is(count($searchTest), 1, 'Searching "Test" returned 1 list');
$t->is(count($searchTest[0]->Notes), 2, 'Searching "Test" returned 2 notes');

$searchNote2 = Doctrine_Core::getTable('Tadalist')->search('noTe2', $user->getId());
$t->is(count($searchNote2), 1, 'Searching "noTe2" returned 1 list');
$t->is(count($searchNote2[0]->Notes), 1, 'Searching "noTe2" returned 1 note');

有用 :

ok 13 - Searching Test returned 1 list
ok 14 - Searching Test returned 2 notes
ok 15 - Searching noTe2 returned 1 list
ok 16 - Searching noTe2 returned 1 note

经过调试,我看到在第一次查询之后,searchTest[0]->Notes 包含了我创建的两个“Note”对象(名为“Test Note”和“Test Note2”),而在第二个之后,它只是包含“Test Note”(“Test Note2”似乎已被第二个查询删除)。

所以我想知道为什么它会这样工作,以及他们是否可以解决它。

你们中有人知道这种奇怪的行为吗?

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1 回答 1

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这是我的假设:在两个查询中,您都获得了相同的Tadalist对象(由相同的主键标识)。Doctrine 可能在两个集合中使用对同一对象的引用。第二个查询覆盖第一个查询返回的 Notes。

注意:这只是一个假设。请验证它是否真的发生。

于 2010-12-12T14:32:58.723 回答