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有没有办法也修改 dbml 以使 Designer.cs 中的方法保持为 IMultipleResults？

我有一个返回 2 组数据的存储过程。当我将程序拖放到dbml、xml和dbml生成的designer.cs时

<Function Name="dbo.MultiResultsTest" Method="MultiResultsTest">
<Parameter Name="iCustomerID" Type="System.Int32" DbType="Int" />
<Parameter Name="iProductID" Type="System.Int32" DbType="Int" />
<ElementType Name="MultiResultsTestResult">
  <Column Name="CustomerID" Type="System.Int32" DbType="Int NOT NULL" CanBeNull="false" />
  <Column Name="Name" Type="System.String" DbType="VarChar(MAX)" CanBeNull="true" />
  <Column Name="Phone" Type="System.String" DbType="VarChar(14)" CanBeNull="true" />
  <Column Name="Email" Type="System.String" DbType="VarChar(MAX)" CanBeNull="true" />
  <Column Name="Address" Type="System.String" DbType="VarChar(MAX)" CanBeNull="true" />
</ElementType>


[global::System.Data.Linq.Mapping.FunctionAttribute(Name="dbo.MultiResultsTest")]
public ISingleResult<MultiResultsTestResult> MultiResultsTest([global::System.Data.Linq.Mapping.ParameterAttribute(DbType="Int")] System.Nullable<int> iCustomerID, [global::System.Data.Linq.Mapping.ParameterAttribute(DbType="Int")] System.Nullable<int> iProductID)
{
    IExecuteResult result = this.ExecuteMethodCall(this, ((MethodInfo)(MethodInfo.GetCurrentMethod())), iCustomerID, iProductID);
    return ((ISingleResult<MultiResultsTestResult>)(result.ReturnValue));
}

为了获得多个结果，我将 Designer.cs 修改为：

[global::System.Data.Linq.Mapping.FunctionAttribute(Name="dbo.MultiResultsTest")]
[ResultType(typeof(Customer))]
[ResultType(typeof(Product))]
public IMultipleResults MultiResultsTest([global::System.Data.Linq.Mapping.ParameterAttribute(DbType="Int")] System.Nullable<int> iCustomerID, [global::System.Data.Linq.Mapping.ParameterAttribute(DbType="Int")] System.Nullable<int> iProductID)
{
    IExecuteResult result = this.ExecuteMethodCall(this, ((MethodInfo)(MethodInfo.GetCurrentMethod())), iCustomerID, iProductID);
    return (IMultipleResults)(result.ReturnValue);
}

这工作正常，但由于 dbml，当我添加更多内容并将方法保存在 Designer.cs 中时，它会恢复为 ISingleResult 之一。

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1 回答 1

1

经过一番搜索和尝试，我发现这种方法有效！

<Function Name="dbo.MultiResultsTest" Method="MultiResultsTest">
<Parameter Name="iCustomerID" Type="System.Int32" DbType="Int" />
<Parameter Name="iProductID" Type="System.Int32" DbType="Int" />
<ElementType Name="CustomerResult">
  <Column Name="CustomerID" Type="System.Int32" DbType="Int NOT NULL" CanBeNull="false" />
  <Column Name="Name" Type="System.String" DbType="VarChar(MAX)" CanBeNull="true" />
  <Column Name="Phone" Type="System.String" DbType="VarChar(14)" CanBeNull="true" />
  <Column Name="Email" Type="System.String" DbType="VarChar(MAX)" CanBeNull="true" />
  <Column Name="Address" Type="System.String" DbType="VarChar(MAX)" CanBeNull="true" />
</ElementType>
<ElementType Name="ProductResult">
  <Column Name="ProductID" Type="System.Int32" DbType="Int NOT NULL" CanBeNull="false" />
  <Column Name="ProductName" Type="System.String" DbType="VarChar(MAX)" CanBeNull="true" />
  <Column Name="Price" Type="System.Decimal" DbType="Decimal(18,2)" CanBeNull="true" />
  <Column Name="ModelNumber" Type="System.String" DbType="VarChar(MAX)" CanBeNull="true" />
</ElementType>

这会在 Designer.cs 中生成以下方法

[global::System.Data.Linq.Mapping.FunctionAttribute(Name="dbo.MultiResultsTest")]
[global::System.Data.Linq.Mapping.ResultTypeAttribute(typeof(CustomerResult))]
[global::System.Data.Linq.Mapping.ResultTypeAttribute(typeof(ProductResult))]
public IMultipleResults MultiResultsTest([global::System.Data.Linq.Mapping.ParameterAttribute(DbType="Int")] System.Nullable<int> iCustomerID, [global::System.Data.Linq.Mapping.ParameterAttribute(DbType="Int")] System.Nullable<int> iProductID)
{
    IExecuteResult result = this.ExecuteMethodCall(this, ((MethodInfo)(MethodInfo.GetCurrentMethod())), iCustomerID, iProductID);
    return ((IMultipleResults)(result.ReturnValue));
}
于 2017-05-24T07:27:45.693 回答