我有三个数据库表
Graduate_survey
id(pk)AI PO1 PO2 PO3
Alumni_survey
id(pk)AI PO1 PO2 PO3
faculty_survey
id(pk)AI PO1 PO2 PO3
在将值插入这些表并通过三个表的联合计算平均值之后,现在我必须将平均值存储在另一个表中
total_survey id(pk)AI PO PO1 PO2 我的代码是
<?php
@include("connection.php");
if($_POST['submit'])
{
$sql= "SELECT t.id
, AVG(t.PO1) AS total_PO1, AVG(t.PO2) AS total_PO2,
AVG(t.PO3) AS total_PO3
FROM ( SELECT Graduate_survey.id
, Graduate_survey.PO1, Graduate_survey.PO2,
Graduate_survey.PO3
FROM Graduate_survey
UNION
SELECT alumni_survey.id
, alumni_survey.PO1, alumni_survey.PO2, alumni_survey.PO3
FROM alumni_survey
UNION
SELECT faculty_survey.id
, faculty_survey.PO1, faculty_survey.PO2, faculty_survey.PO3
FROM faculty_survey
)t
GROUP BY t.id
ORDER BY t.id";
$rData=mysql_query($sql);
$res=mysql_fetch_array($rData);
$sql="insert into total_survey
values('','total_PO1','total_PO2','total_PO3')";
mysql_query($sql);
}
?>
<form method="post">
<p align="center"><input type="submit" name="submit"
value="Click here to calculate the final indirect assesment">
</p>
</form>
选择查询工作正常,但插入查询不工作。问题是我必须在另一个表 total_survey 中插入选择查询显示的数据。如何将获取的数据存储在 MySQL 的另一个表中?