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我们有一个使用 Scalatra ( http://scalatra.org/ ) 作为我们的 Web 框架的 Scala 应用程序。我想知道是否有关于如何使用 Sangria(http://sangria-graphql.org/)和 Scalatra 实现 GraphQL 端点的任何好的(或只是任何)资源?

我是 Scala 的新手,如果有任何帮助,我将不胜感激。

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1 回答 1

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我不知道,但由于 Scalatra 使用 json4s,你会使用桑格利亚汽酒的 json4s marshaller

否则,如果桑格利亚汽酒对您来说更清楚,这里有一个 scala 工作表,其中包含一个非常简单的基于 off play + 桑格利亚汽酒的示例 - 在这种情况下,您只需要交换 json 库。

db 是模拟的(也许你使用 Slick?)和 http 服务器也是模拟的,但这是在函数定义中交换的一个简单案例。

import sangria.ast.Document
import sangria.execution.{ErrorWithResolver, Executor, QueryAnalysisError}
import sangria.macros.derive.{ObjectTypeDescription, ObjectTypeName, deriveObjectType}
import sangria.parser.{QueryParser, SyntaxError}
import sangria.renderer.SchemaRenderer
import sangria.schema.{Argument, Field, IntType, ListType, ObjectType, OptionInputType, Schema, fields}

import scala.concurrent.Await
import scala.concurrent.duration._
import scala.concurrent.ExecutionContext.Implicits.global

import scala.concurrent.Future
import scala.util.{Failure, Success}

// replace with another json lib
// eg https://github.com/sangria-graphql/sangria-json4s-jackson
import play.api.libs.json._
import sangria.marshalling.playJson._


case class User(name: String, age: Int, phone: Option[String])
class FakeDb {

  class UsersTable {
    def getUsers(limit: Int): List[User] = {
      // this would come from the db
      List(
        User("john smith", 23, None),
        User("Anne Schwazenbach", 45, Some("2134556"))
      )
    }
  }

  val usersRepo = new UsersTable

}

object MySchema {

  val limitArg: Argument[Int] = Argument("first", OptionInputType(IntType),
    description = s"Returns the first n elements from the list.",
    defaultValue = 10)

  implicit val UsersType: ObjectType[FakeDb, User] = {
    deriveObjectType[FakeDb, User](
      ObjectTypeName("Users"),
      ObjectTypeDescription("Users in the system")
    )
  }
  private val Query: ObjectType[FakeDb, Unit] = ObjectType[FakeDb, Unit](
    "Query", fields[FakeDb, Unit](
      Field("users", ListType(UsersType),
        arguments = limitArg :: Nil,
        resolve = c => c.ctx.usersRepo.getUsers(c.arg(limitArg))
      )
    ))
  val theSchema: Schema[FakeDb, Unit] = Schema(Query)
}

object HttpServer {

  def get(): String = {
    // Http GET  
    SchemaRenderer.renderSchema(MySchema.theSchema)
  }

  def post(query: String): Future[JsValue] = {
    // Http POST
    val variables = None
    val operation = None

    QueryParser.parse(query) match {
      case Success(q) => executeQuery(q, variables, operation)
      case Failure(error: SyntaxError) => Future.successful(Json.obj("error" -> error.getMessage))
      case Failure(error: Throwable) => Future.successful(Json.obj("error" -> error.getMessage))
    }
  }

  private def executeQuery(queryAst: Document, vars: Option[JsValue], operation: Option[String]): Future[JsValue] = {
    val schema: Schema[FakeDb, Unit] = MySchema.theSchema
    Executor.execute[FakeDb, Unit, JsValue](schema, queryAst, new FakeDb,
      operationName = operation,
      variables=vars.getOrElse(Json.obj()))
      .map((d: JsValue) => d)
      .recover {
        case error: QueryAnalysisError ⇒ Json.obj("error" -> error.getMessage)
        case error: ErrorWithResolver ⇒ Json.obj("error" -> error.getMessage)
      }
  }
}

HttpServer.get()

val myquery = """
  {
    users {
     name
    }
  }
  """

val res: JsValue = Await.result(HttpServer.post(myquery), 10.seconds)
于 2017-05-23T14:23:10.133 回答