7

经过几个小时的谷歌搜索和测试,似乎我应该能够找到这个问题的明显答案。

我希望能够在 caredate 工厂中设置 caredate.user_id => provider.user_id。

测试错误:

ActiveRecord::RecordInvalid:验证失败:用户必须与提供者用户相同

我有一个 ActiveRecord 验证,它在通过浏览器测试时有效:

class Caredate < ActiveRecord::Base //works fine when testing via browser
  belongs_to :user
  belongs_to :provider

  validates_presence_of :user_id
  validates_presence_of :provider_id
  validate :user_must_be_same_as_provider_user

  def user_must_be_same_as_provider_user
    errors.add(:user_id, "must be same as provider user") unless self.user_id == self.provider.user_id
  end

end

//factories.rb
Factory.define :user do |f| 
  f.password "test1234"
  f.sequence(:email) { |n| "foo#{n}@example.com" }
end

Factory.define :caredate do |f| 
  f.association :provider
  **f.user_id { Provider.find_by_id(provider_id).user_id }  //FAILS HERE**
end

Factory.define :provider do |f| 
  f.association :user
end

如果之前已经回答过,我深表歉意;我尝试了几种不同的选择,但无法正常工作。

更新:这通过了验证,所以我越来越近了。我可以用随机数破解。

Factory.define :caredate do |f| 
  f.association :user, :id => 779
  f.association :provider, :user_id => 779
end
4

2 回答 2

8
Factory.define :caredate do |f|
  provider = Factory.create(:provider)
  f.provider provider
  f.user provider.user
end
于 2010-12-11T02:04:24.277 回答
0

尝试将 user_id 设置为after_createor after_build

Factory.define :caredate do |f|
  f.after_create { |caredate| caredate.user_id = caredate.provider.user_id }
end
于 2010-12-10T19:11:13.207 回答