0

这是我的第一个查询何时$_POST设置：

<?php
    if (isset($_POST['bags']))
{
    $bagS=$_POST['bags'];
        $id=$_POST["id"];
        $_SESSION['id']=$id;
        $cats = explode(" ", $bagS);
        $cats = preg_split('/,/', $bagS, -1, PREG_SPLIT_NO_EMPTY);
        foreach($cats as $key => $cat )
        {
        $cat  = mysqli_real_escape_string($con,$cats[$key]);
        $cat = trim($cat);
 if($cat !=NULL)
             {
                 $stmt = $con->prepare('UPDATE wallet SET `Status`="Hold" where `Id`=? AND `bags`="'.$cat.'" ');
                 $stmt->bind_param("s", $_POST["id"]);
                 $stmt->execute();

  }
  }
}

之后，如果用户端没有任何反应，则设置脚本超时以更新下一个查询。

<script type="text/javascript">
          setTimeout(function() { window.location.href = "index.php?on_timeout=1"; }, 60 * 500);
</script>

然后脚本在超时时返回查询字符串并执行更新查询并重定向到其他页面：

if(isset($_GET['on_timeout'])) {

   echo  $bagS=$_SESSION['bags'];
   echo $id=$_SESSION['id'];
        $cats = explode(" ", $bagS);
        $cats = preg_split('/,/', $bagS, -1, PREG_SPLIT_NO_EMPTY);
        foreach($cats as $key => $cat )
        {
        $cat  = mysql_real_escape_string($cats[$key]);
        $cat = trim($cat);
 if($cat !=NULL)
             {
                  $stmt = $con->prepare('UPDATE wallet SET `Status`=" " where `Id`=? AND `bags`="'.$cat.'" AND `Status`="Hold" ');
                 $stmt->bind_param("s", $_SESSION['id']);
                 $stmt->execute();
                 echo "<script type='text/javascript'>location.href = 'cards.php';</script>";

  }
  }
}

 ?>

现在我想在用户关闭浏览器或在 的帮助下返回浏览器时执行相同的查询window.onbeforeunload，所以请告诉我如何在此事件中设置更新代码。

<script>
var areYouReallySure = false;
    function areYouSure() {
    if(allowPrompt){
        if (!areYouReallySure && true) {
            areYouReallySure = true;
            var confMessage = "are you sure to do this";
            return confMessage;
        }
    }else{
        allowPrompt = true;
    }
}

var allowPrompt = true;
window.onbeforeunload = areYouSure;

</script>
4

1 回答 1

0

您可以在离开页面之前调用您的代码

function myfoo(){
         // Write your logic here
           $.ajax({
            url: "Pageurl_that_having_your_update_code",
            dataType: 'json',
            data: {
                on_timeout: 1
            },
            success: function (r) {}
});
    }

卸载前：

 window.onbeforeunload = function(){
  myfoo();
  return 'Are you sure you want to leave?';
};

或 jQuery

$(window).bind('beforeunload', function(){
  myfoo();
  return 'Are you sure you want to leave?';
});
于 2017-05-20T06:28:34.213 回答