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在 BigQuery 中，我创建了一个具有以下架构的表

id                  INTEGER NULLABLE    
visits              INTEGER NULLABLE    
dimensions          RECORD  REPEATED    
dimensions.value    STRING  
dimensions.key      STRING

如何通过对设备和状态值进行分组来获得总和（访问）？

示例数据：

{"id": 1, visits: 100, "dimensions": [{"key":"device","value":"mobile"}, {"key":"state","value":"CA"}]}
{"id": 1, visits: 500, "dimensions": [{"key":"device","value":"desktop"}, {"key":"state","value":"CA"}]}
{"id": 1, visits: 200, "dimensions": [{"key":"device","value":"mobile"}, {"key":"state","value":"NY"}]}
{"id": 2, visits: 100, "dimensions": [{"key":"device","value":"mobile"}, {"key":"state","value":"CA"}]}
{"id": 2, visits: 500, "dimensions": [{"key":"device","value":"desktop"}, {"key":"state","value":"CA"}]}
{"id": 2, visits: 200, "dimensions": [{"key":"device","value":"mobile"}, {"key":"state","value":"NY"}]}
{"id": 2, visits: 780, "dimensions": [{"key":"device","value":"desktop"}, {"key":"state","value":"NY"}]}

我想要输出中的 id、device、state、sum(visits)。

我可以通过使用带有以下查询的单个维度来创建一个组，但不知道如何为多个维度执行此操作。

SELECT id,d.value, sum(visits) FROM dataset.tabe_name,UNNEST(dimensions) as d where d.key = "device" group by id, d.value LIMIT 1000

当事先不知道键值时，是否可以编写通用查询？

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1 回答 1

14

以下是 BigQuery 标准 SQL

#standardSQL
SELECT 
  id,
  (SELECT value FROM UNNEST(dimensions) WHERE key = "device") AS device,
  (SELECT value FROM UNNEST(dimensions) WHERE key = "state") AS state,
  SUM(visits) AS visits
FROM `dataset.tabe_name`  
GROUP BY id, device, state
LIMIT 1000

您可以使用示例中的虚拟数据尝试/播放它，如下所示 

#standardSQL
WITH data AS (
  SELECT 1 AS id, 100 AS visits, ARRAY<STRUCT<key STRING, value STRING>>[("device", "mobile"), ("state", "CA")] AS dimensions UNION ALL
  SELECT 1, 100, [STRUCT<key STRING, value STRING>("device", "mobile"), ("state", "CA")] UNION ALL
  SELECT 1, 500, [STRUCT<key STRING, value STRING>("device", "desktop"), ("state", "CA")] UNION ALL
  SELECT 1, 200, [STRUCT<key STRING, value STRING>("device", "mobile"), ("state", "NY")] UNION ALL
  SELECT 2, 100, [STRUCT<key STRING, value STRING>("device", "mobile"), ("state", "CA")] UNION ALL
  SELECT 2, 500, [STRUCT<key STRING, value STRING>("device", "desktop"), ("state", "CA")] UNION ALL
  SELECT 2, 200, [STRUCT<key STRING, value STRING>("device", "mobile"), ("state", "NY")] UNION ALL
  SELECT 2, 780, [STRUCT<key STRING, value STRING>("device", "desktop"), ("state", "NY")] 
)
SELECT 
  id,
  (SELECT value FROM UNNEST(dimensions) WHERE key = "device") AS device,
  (SELECT value FROM UNNEST(dimensions) WHERE key = "state") AS state,
  SUM(visits) AS visits
FROM data  
GROUP BY id, device, state
-- ORDER BY id, device, state
于 2017-05-18T13:14:13.500 回答