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以下问题让我很头疼。

我已经将我的 MySQL 服务器设置为使用“Query Chaching”。

set global query_cache_size = 10000000;

似乎我的查询缓存有效,因为

SHOW STATUS LIKE 'Qcache%';  

如下

+-------------------------+----------+    
|    Variable_name        | Value    |           
+-------------------------+----------+     
| Qcache_free_blocks      | 1        |
| Qcache_free_memory      | 47223976 |
| Qcache_hits             | 6709     |                                       
| Qcache_inserts          | 2314     |                                    
| Qcache_lowmem_prunes    | 0        |                                  
| Qcache_not_cached       | 365      |                                  
| Qcache_queries_in_cache | 441      |                                   
| Qcache_total_blocks     | 960      |                                     
+-------------------------+----------+ 

但是,尽管如此(复杂查询,内部选择等)不会被缓存。

检索此查询的数据总是至少需要 0.8 秒。如何让 mysql将此查询的结果存储在它的缓存中

我尝试删除内部选择,但这并没有什么不同。

SELECT p.id
   AS
   project_id,
   p.code
   AS project_code,
   p.title
   AS project_title,
   p.start_date
   AS project_start_date,
   p.end_date
   AS project_end_date,
   p.modf
   AS project_modf,
   ( p.budget * (SELECT 1 / r.VALUE
                 FROM   exchange_rates r
                 WHERE  r.class_currency_id = p.class_budget_currency_id) )
   AS
   project_budget,
   (SELECT z.txt
    FROM   sys_labels z
    WHERE  z.id = ps.value_label_id
           AND z.lng = 'en')
   AS project_status,
   (SELECT z.txt
    FROM   sys_labels z
    WHERE  z.id = ps.data_label_id
           AND z.lng = 'en')
   AS project_color,
   GROUP_CONCAT(DISTINCT pt.class_topic_id)
   AS projects_thematic_area_ids,
   u.id
   AS project_owner_id
FROM   projects AS p
   LEFT JOIN projects_thematic_areas AS pt
     ON pt.project_id = p.id
   LEFT JOIN sys_users AS u
     ON u.id = p.owner_uid
   LEFT JOIN class_data s
     ON s.id = p.class_status_id
   LEFT JOIN class_data AS ps
     ON ps.id = s.id
   LEFT JOIN sys_labels AS prdz1
     ON prdz1.id = prd.value_label_id
        AND prdz1.lng = 'en'
   LEFT JOIN sys_labels AS prdz2
     ON prdz2.id = prd.data_label_id
        AND prdz2.lng = 'en'
   LEFT JOIN projects_locations AS pl
     ON pl.project_id = p.id
   LEFT JOIN class_data AS l
     ON l.id = pl.class_location_id
   LEFT JOIN class_data AS r
     ON r._lft <= l._lft
        AND r._rgt >= l._rgt
        AND r._level = 1
        AND r.class_id = 5
   LEFT JOIN class_data AS c
     ON c._lft <= l._lft
        AND c._rgt >= l._rgt
        AND c._level = 2
        AND c.class_id = 10
   LEFT JOIN projects_donors AS pd
     ON pd.project_id = p.id
   LEFT JOIN institutions AS i
     ON pd.inst_id = i.id
   LEFT JOIN class_data AS ic
     ON ic.id = i.class_country_id
   LEFT JOIN projects_deliverables AS d
     ON d.project_id = p.id
WHERE  1 = 1
   AND p.is_del = "f"
   AND p.is_active = "t"
GROUP  BY p.id
ORDER  BY p.modf DESC,
      p.code DESC 

任何帮助apprechiated....

问候

J。

4

3 回答 3

1

除了以前的答案:如果任何选定的表中有更改,即使查询在其中,也不会使用查询缓存。

但是,当您没有从中选择任何东西时,为什么要加入所有这些表?此外,如果您可以加入,您可能不应该再选择任何东西。

像这样的东西会选择完全相同的:

SELECT
   p.id AS project_id,
   p.code AS project_code,
   p.title AS project_title,
   p.start_date AS project_start_date,
   p.end_date AS project_end_date,
   p.modf AS project_modf,
   p.budget * (1 / r.VALUE) AS project_budget,
   z1.txt AS project_status,
   z2.txt AS project_color,
   GROUP_CONCAT(DISTINCT pt.class_topic_id) AS projects_thematic_area_ids,
   u.id AS project_owner_id
FROM
   projects AS p
   LEFT JOIN projects_thematic_areas AS pt ON pt.project_id = p.id
   LEFT JOIN sys_users AS u ON u.id = p.owner_uid
   LEFT JOIN exchange_rates AS r ON r.class_currency_id = p.class_budget_currency_id
   LEFT JOIN class_data s ON s.id = p.class_status_id
   LEFT JOIN class_data AS ps ON ps.id = s.id
   LEFT JOIN sys_labels AS z1 ON z1.id = ps.value_label_id AND z1.lng = 'en'
   LEFT JOIN sys_labels AS z2 ON z2.id = ps.data_label_id AND z2.lng = 'en'
WHERE
   1
   AND p.is_del = "f"
   AND p.is_active = "t"
GROUP  BY
   p.id
ORDER  BY
   p.modf DESC,
   p.code DESC 

当然,您在所有外键(字段和组字段)上都有(组合)索引。考虑为布尔值使用 tinyint 或 enum 字段。您可能还需要考虑不选择该 GROUP_CONCAT,这样您就可以丢失 GROUP BY。如果您确定关系存在,也许使用 INNER JOIN 而不是 LEFT JOIN。

于 2010-12-09T16:19:09.367 回答
0

你可以试试SELECT SQL_CACHE ... FROM ...

于 2010-12-09T16:06:04.533 回答
0

您可以尝试一些基本的事情:

  • 阅读查询缓存文档以确保您了解基础知识并正确设置它。
  • 理想情况下隔离您的 MySQL 数据库服务器,以便它只运行您给它的命令。如果您不能这样做,请尝试在另一台机器上设置和运行测试。
  • 运行一个简单的查询并查看Qcache_hitsCom_select状态变量以确定查询缓存是否被命中。
  • 尝试您的复杂查询并监控相同的值。如果您的查询没有命中缓存,那么尝试它的较小部分,直到找出导致它没有被缓存的原因。如果它正在被缓存,则问题可能是由于查询中的任何表在查询之间更新,这将使缓存副本无效。
于 2010-12-09T17:14:05.007 回答