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我已经成功创建了一个 GMF 编辑器,它根据我的 EMF 模型绘制模型。我想做的是迭代我的模型的 EClasses。这可以在运行时通过我的插件代码实现,而无需读取 gmf 编辑器的 xml 文件创建?是否有来自 EMF 的 API?

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1 回答 1

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当您从 genmodel 文件生成测试代码时,然后在 XYZ.test 插件中有我正在搜索的此类代码。它遍历模型的 xmi 文件

// Create a resource set to hold the resources.
    //
    ResourceSet resourceSet = new ResourceSetImpl();

    // Register the appropriate resource factory to handle all file extensions.
    //
    resourceSet.getResourceFactoryRegistry().getExtensionToFactoryMap().put
        (Resource.Factory.Registry.DEFAULT_EXTENSION, 
         new XMIResourceFactoryImpl());

    // Register the package to ensure it is available during loading.
    //
    resourceSet.getPackageRegistry().put
        (XYZmetamodelPackage.eNS_URI, 
         XYZmetamodelPackage.eINSTANCE);

    // If there are no arguments, emit an appropriate usage message.
    //
    if (args.length == 0) {
        System.out.println("Enter a list of file paths or URIs that have content like this:");
        try {
            Resource resource = resourceSet.createResource(URI.createURI("http:///My.metamodel"));
            ModelObject root = atagmetamodelFactory.eINSTANCE.createModelObject();
            resource.getContents().add(root);
            resource.save(System.out, null);
        }
        catch (IOException exception) {
            exception.printStackTrace();
        }
    }
    else {
        // Iterate over all the arguments.
        //
        for (int i = 0; i < args.length; ++i) {
            // Construct the URI for the instance file.
            // The argument is treated as a file path only if it denotes an existing file.
            // Otherwise, it's directly treated as a URL.
            //
            File file = new File(args[i]);
            URI uri = file.isFile() ? URI.createFileURI(file.getAbsolutePath()): URI.createURI(args[i]);

            try {
                // Demand load resource for this file.
                //
                Resource resource = resourceSet.getResource(uri, true);
                System.out.println("Loaded " + uri);

                // Validate the contents of the loaded resource.
                //
                for (EObject eObject : resource.getContents()) {
                    Diagnostic diagnostic = Diagnostician.INSTANCE.validate(eObject);
                    if (diagnostic.getSeverity() != Diagnostic.OK) {
                        printDiagnostic(diagnostic, "");
                    }
                }
            }
            catch (RuntimeException exception) {
                System.out.println("Problem loading " + uri);
                exception.printStackTrace();
            }
        }
    }
}
于 2010-12-10T11:40:08.097 回答