sql - 删除名称以某个字符串开头的所有表

Question

如何删除名称以给定字符串开头的所有表？

我认为这可以通过一些动态 SQL 和INFORMATION_SCHEMA表来完成。

score 167 · Accepted Answer

如果数据库中有多个所有者，您可能需要修改查询以包含所有者。

DECLARE @cmd varchar(4000)
DECLARE cmds CURSOR FOR
SELECT 'drop table [' + Table_Name + ']'
FROM INFORMATION_SCHEMA.TABLES
WHERE Table_Name LIKE 'prefix%'

OPEN cmds
WHILE 1 = 1
BEGIN
    FETCH cmds INTO @cmd
    IF @@fetch_status != 0 BREAK
    EXEC(@cmd)
END
CLOSE cmds;
DEALLOCATE cmds

这比使用生成脚本加运行的两步方法更干净。但是脚本生成的一个优点是它使您有机会在实际运行之前查看将要运行的全部内容。

我知道如果我要针对生产数据库执行此操作，我会尽可能小心。

编辑代码示例已修复。

score 130 · Accepted Answer

SELECT 'DROP TABLE "' + TABLE_NAME + '"' 
FROM INFORMATION_SCHEMA.TABLES 
WHERE TABLE_NAME LIKE '[prefix]%'

这将生成一个脚本。

添加子句以在删除之前检查表的存在：

SELECT 'IF OBJECT_ID(''' +TABLE_NAME + ''') IS NOT NULL BEGIN DROP TABLE [' + TABLE_NAME + '] END;' 
FROM INFORMATION_SCHEMA.TABLES 
WHERE TABLE_NAME LIKE '[prefix]%'

score 18 · Accepted Answer

这将使您按外键顺序获取表，并避免删除一些由 SQL Server 创建的表。该t.Ordinal值会将表分割成依赖层。

WITH TablesCTE(SchemaName, TableName, TableID, Ordinal) AS
(
    SELECT OBJECT_SCHEMA_NAME(so.object_id) AS SchemaName,
        OBJECT_NAME(so.object_id) AS TableName,
        so.object_id AS TableID,
        0 AS Ordinal
    FROM sys.objects AS so
    WHERE so.type = 'U'
        AND so.is_ms_Shipped = 0
        AND OBJECT_NAME(so.object_id)
        LIKE 'MyPrefix%'

    UNION ALL
    SELECT OBJECT_SCHEMA_NAME(so.object_id) AS SchemaName,
        OBJECT_NAME(so.object_id) AS TableName,
        so.object_id AS TableID,
        tt.Ordinal + 1 AS Ordinal
    FROM sys.objects AS so
        INNER JOIN sys.foreign_keys AS f
            ON f.parent_object_id = so.object_id
                AND f.parent_object_id != f.referenced_object_id
        INNER JOIN TablesCTE AS tt
            ON f.referenced_object_id = tt.TableID
    WHERE so.type = 'U'
        AND so.is_ms_Shipped = 0
        AND OBJECT_NAME(so.object_id)
        LIKE 'MyPrefix%'
)
SELECT DISTINCT t.Ordinal, t.SchemaName, t.TableName, t.TableID
FROM TablesCTE AS t
    INNER JOIN
    (
        SELECT
            itt.SchemaName AS SchemaName,
            itt.TableName AS TableName,
            itt.TableID AS TableID,
            Max(itt.Ordinal) AS Ordinal
        FROM TablesCTE AS itt
        GROUP BY itt.SchemaName, itt.TableName, itt.TableID
    ) AS tt
        ON t.TableID = tt.TableID
            AND t.Ordinal = tt.Ordinal
ORDER BY t.Ordinal DESC, t.TableName ASC

score 8 · Accepted Answer

在 Oracle XE 上这有效：

SELECT 'DROP TABLE "' || TABLE_NAME || '";'
FROM USER_TABLES
WHERE TABLE_NAME LIKE 'YOURTABLEPREFIX%'

或者，如果您想删除约束并释放空间，请使用以下命令：

SELECT 'DROP TABLE "' || TABLE_NAME || '" cascade constraints PURGE;'
FROM USER_TABLES
WHERE TABLE_NAME LIKE 'YOURTABLEPREFIX%'

这将产生一堆DROP TABLE cascade constraints PURGE语句......

为了VIEWS使用这个：

SELECT 'DROP VIEW "' || VIEW_NAME || '";'
FROM USER_VIEWS
WHERE VIEW_NAME LIKE 'YOURVIEWPREFIX%'

score 7 · Accepted Answer

这是我的解决方案：

SELECT CONCAT('DROP TABLE `', TABLE_NAME,'`;') 
FROM INFORMATION_SCHEMA.TABLES 
WHERE TABLE_NAME LIKE 'TABLE_PREFIX_GOES_HERE%';

当然，您需要TABLE_PREFIX_GOES_HERE用您的前缀替换。

score 6 · Accepted Answer

EXEC sp_MSforeachtable 'if PARSENAME("?",1) like ''%CertainString%'' DROP TABLE ?'

编辑：

sp_MSforeachtable 未记录，因此不适合生产，因为它的行为可能因 MS_SQL 版本而异。

score 5 · Accepted Answer

当我在寻找 mysql 语句以删除所有基于 @Xenph Yan 的 WordPress 表时，我看到了这篇文章，这就是我最终所做的：

SELECT CONCAT(  'DROP TABLE `', TABLE_NAME,  '`;' ) AS query
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME LIKE  'wp_%'

这将为您提供所有以 wp_ 开头的表的删除查询集

score 4 · Accepted Answer

CREATE PROCEDURE usp_GenerateDROP
    @Pattern AS varchar(255)
    ,@PrintQuery AS bit
    ,@ExecQuery AS bit
AS
BEGIN
    DECLARE @sql AS varchar(max)

    SELECT @sql = COALESCE(@sql, '') + 'DROP TABLE [' + TABLE_NAME + ']' + CHAR(13) + CHAR(10)
    FROM INFORMATION_SCHEMA.TABLES
    WHERE TABLE_NAME LIKE @Pattern

    IF @PrintQuery = 1 PRINT @sql
    IF @ExecQuery = 1 EXEC (@sql)
END

score 2 · Accepted Answer

Xenph Yan的回答比我的要干净得多，但这里还是我的。

DECLARE @startStr AS Varchar (20)
SET @startStr = 'tableName'

DECLARE @startStrLen AS int
SELECT @startStrLen = LEN(@startStr)

SELECT 'DROP TABLE ' + name FROM sysobjects
WHERE type = 'U' AND LEFT(name, @startStrLen) = @startStr

只需更改tableName为您要搜索的字符。

score 2 · Accepted Answer

这对我有用。

DECLARE @sql NVARCHAR(MAX) = N'';

SELECT @sql += '
DROP TABLE ' 
    + QUOTENAME(s.name)
    + '.' + QUOTENAME(t.name) + ';'
    FROM sys.tables AS t
    INNER JOIN sys.schemas AS s
    ON t.[schema_id] = s.[schema_id] 
    WHERE t.name LIKE 'something%';

PRINT @sql;
-- EXEC sp_executesql @sql;

score 0 · Accepted Answer

select 'DROP TABLE ' + name from sysobjects
where type = 'U' and sysobjects.name like '%test%'

-- test 是表名

score 0 · Accepted Answer

SELECT 'if object_id(''' + TABLE_NAME + ''') is not null begin drop table "' + TABLE_NAME + '" end;' 
FROM INFORMATION_SCHEMA.TABLES 
WHERE TABLE_NAME LIKE '[prefix]%'

score 0 · Accepted Answer

我不得不对 Xenph Yan 的回答做一点推导，我怀疑是因为我的表不在默认模式中。

SELECT 'DROP TABLE Databasename.schema.' + TABLE_NAME 
FROM INFORMATION_SCHEMA.TABLES 
WHERE TABLE_NAME LIKE 'strmatch%'

score 0 · Accepted Answer

如果是临时表，您可能想尝试

SELECT 'DROP TABLE "' + t.name + '"' 
FROM tempdb.sys.tables t
WHERE t.name LIKE '[prefix]%'

score 0 · Accepted Answer

我想发布我的解决方案建议，该解决方案基于通配符（例如“table_20210114”）删除（不仅仅是生成和选择删除命令）超过特定天数的所有表。

DECLARE 
    @drop_command NVARCHAR(MAX) = '',
    @system_time date,
    @table_date nvarchar(8),
    @older_than int = 7
    
Set @system_time = (select getdate() - @older_than)
Set @table_date = (SELECT CONVERT(char(8), @system_time, 112))

SELECT @drop_command += N'DROP TABLE ' + QUOTENAME(SCHEMA_NAME(schema_id)) + '.' + QUOTENAME([Name]) + ';'
FROM <your_database_name>.sys.tables
WHERE [Name] LIKE 'table_%' AND RIGHT([Name],8) < @table_date

SELECT @drop_command
 
EXEC sp_executesql @drop_command

sql - 删除名称以某个字符串开头的所有表

15 回答 15

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