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我正在使用 CakePHP 3.4

我有两个模型skills，skill_categories它们的关联就像

skill_categories->hasMany('skills');
skills->belongsTo('SkillCategories', 'joinType' => 'INNER')

并且skills与userswhere有关联

skills->belongsTo('users')
users->hasMany('Skills')

我必须从表分组中选择所有关联skills的用户，这将产生类似的结果skillsskills.skill_category_id

Skill Category 1
|-- Skill 11
|-- Skill 12
|-- Skill 13
Skill Category 2
|-- Skill 21
|-- Skill 22

或喜欢

'skill_categories' => [
        'title' => 'Skill Category 1',
        'id' => 1,
        'skills' => [
            0 => [
               'title' => 'Skill 11',
               'id' => 4,
             ],
            1 => [
                'title' => 'Skill 12',
                'id' => 6,
            ]
        ],
]

我正在做的是：方法1

$user_skills = $this->Skills->find()
        ->select(['Skills.skill_category_id', 'Skills.title', 'Skills.measure', 'SkillCategories.title', 'Skills.id'])
        ->where(['Skills.user_id' => $user->id, 'Skills.deleted' => false, 'Skills.status' => 0])
        ->contain(['SkillCategories'])
        ->group(['Skills.skill_category_id']);

        foreach($user_skills as $s)debug($s);

但这会引发错误

错误：SQLSTATE[42000]：语法错误或访问冲突：1055 SELECT 列表的表达式 #2 不在 GROUP BY 子句中，并且包含在功能上不依赖于 GROUP BY 子句中的列的非聚合列“profPlus_db_new.Skills.title”；这与 sql_mode=only_full_group_by 不兼容

方法二

$user_skills = $this->SkillCategories->find()
        ->where(['Skills.user_id' => $user->id, 'Skills.deleted' => false, 'Skills.status' => 0])
        ->contain(['Skills'])
        ->group(['SkillCategories.id']);

        foreach($user_skills as $s)debug($s);

但这给出了错误

错误：SQLSTATE [42S22]：找不到列：1054 'where 子句'中的未知列'Skills.user_id'

编辑 2

技能图式

CREATE TABLE IF NOT EXISTS `skills` (
  `id` CHAR(36) NOT NULL,
  `user_id` CHAR(36) NOT NULL,
  `skill_category_id` CHAR(36) NOT NULL,
  `title` VARCHAR(250) NOT NULL,
  `measure` INT NOT NULL DEFAULT 0,
  `status` INT NULL DEFAULT 0,
  `deleted` TINYINT(1) NULL DEFAULT 0,
  `created` TIMESTAMP NULL DEFAULT CURRENT_TIMESTAMP,
  `modified` DATETIME NULL,
  PRIMARY KEY (`id`)
  )

技能类别架构

CREATE TABLE IF NOT EXISTS `skill_categories` (
  `id` CHAR(36) NOT NULL,
  `title` VARCHAR(200) NOT NULL,
  `status` INT NULL DEFAULT 0,
  `deleted` TINYINT(1) NULL DEFAULT 0,
  `created` TIMESTAMP NULL DEFAULT CURRENT_TIMESTAMP,
  `modified` DATETIME NULL,
  PRIMARY KEY (`id`))

控制器代码

$user_skills = $this->SkillCategories->find()
   ->contain([
       'Skills' => function($q) use($user) {
           return $q
           ->select(['id', 'skill_category_id', 'title', 'measure', 'user_id', 'deleted', 'status'])
           ->where(['user_id' => $user->id, 'deleted' => false, 'status' => 0]);
    }])
    ->group(['SkillCategories.id']);

    foreach($user_skills as $s)debug($s);

调试输出

object(App\Model\Entity\SkillCategory) {

'id' => '581cd4ac-28a7-4016-b535-b34a27d47c0d',
'title' => 'Programming',
'status' => (int) 0,
'deleted' => false,
'skills' => [
    (int) 0 => object(App\Model\Entity\Skill) {

        'id' => '36f16f7f-b484-4fd8-bfc5-4408ce97ff23',
        'skill_category_id' => '581cd4ac-28a7-4016-b535-b34a27d47c0d',
        'title' => 'PHP',
        'measure' => (int) 92,
        'user_id' => '824fbcef-cba8-419e-8215-547bd5d128ad',
        'deleted' => false,
        'status' => (int) 0,
        '[repository]' => 'Skills'

    },
    (int) 1 => object(App\Model\Entity\Skill) {

        'id' => '4927e7c1-826a-405d-adbe-e8c084c2b9ef',
        'skill_category_id' => '581cd4ac-28a7-4016-b535-b34a27d47c0d',
        'title' => 'CakePHP',
        'measure' => (int) 90,
        'user_id' => '824fbcef-cba8-419e-8215-547bd5d128ad',
        'deleted' => false,
        'status' => (int) 0,
        '[repository]' => 'Skills'
    }
],
'[repository]' => 'SkillCategories'

}

object(App\Model\Entity\SkillCategory) {

'id' => 'd55a2a95-05a0-410e-9a55-1a1509f76b8c',
'title' => 'Office',
'status' => (int) 0,
'deleted' => false,
'skills' => [],
'[repository]' => 'SkillCategories'

}

注意：查看标题为Office的第二个对象与用户没有skills关联

4

1 回答 1

1

您可以将条件传递到包含！:D

$user_skills = $this->SkillCategories->find()
    ->contain(['Skills' => function($q) use($user) {
        return $q
        ->select(['id', 'user_id', 'deleted', 'status', 'skill_category_id'])
        ->where(['user_id' => $user->id, 'deleted' => false, 'status' => 0]);
    }])
    ->group(['SkillCategories.id']);
于 2017-05-10T16:17:53.253 回答