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我的目标是将一个图像放在另一个图像上并将生成的图像保存为 jpeg 文件。第一个是新的，它有 450x300 尺寸和白色背景。第二个是从文件加载的，它的可见部分作为图层添加到第一个。

我已将以下 python 脚本添加到/usr/lib/gimp/2.0/plug-ins文件夹

#!/usr/bin/python
import os

from gimpfu import *
import gimpfu

import logging
def scale(timg, tdrawable, imageName):
    logger = logging.getLogger()
    logger.info('got logo file {0}'.format(imageName))

    newImage = pdb.gimp_image_new(450, 300, RGB)

    newLayer = pdb.gimp_layer_new(newImage, 450, 300, 0, "background", 100.0, NORMAL_MODE)

    pdb.gimp_context_set_background((255, 255, 255))
    pdb.gimp_drawable_fill(newLayer, gimpfu.BACKGROUND_FILL)
    logger.info('Created new background image {0}')
    newImage.add_layer(newLayer, 0)

    timg = pdb.gimp_file_load(imageName, imageName)

    tdraw = pdb.gimp_layer_new_from_visible(timg, newImage, 'logo')      
    newImage.add_layer(tdraw, 1)
    finalLayer = pdb.gimp_image_merge_down(newImage,tdraw,1)
    fileNameNoExt = os.path.splitext(imageName)[0]
    pdb.file_jpeg_save(newImage, finalLayer, fileNameNoExt + '.jpg', fileNameNoExt + '.jpg', 1.0, 0.0, 1, 1, '', 0, 0, 0, 0)

通过运行它

gimp --no-interface -b '(python-fu-my RUN-NONINTERACTIVE 0 0 "logo.png")' -b '(gimp-quit 0)'

返回

(gimp:4224): GLib-CRITICAL **: g_error_new_literal: assertion 'domain != 0' failed Traceback (last last 最近调用): File "/usr/lib/gimp/2.0/python/gimpfu.py", line 821 ，在 _run return apply(func, params[1:]) 文件“/usr/lib/gimp/2.0/plug-ins/my.py”，第 31 行，按比例 finalLayer = pdb.gimp_image_merge_down(newImage,tdraw,1 ）RuntimeError：执行错误批处理命令遇到执行错误：错误：（：1）python-fu-my的程序执行失败

怎么了？如何正确地做到这一点并了解问题的根本原因。

编辑。遵循 xenoid 的建议： 1) 使用gimp_image_merge_down导致logo.jpeg的白色背景为 450、300 大小

def my(timg, tdrawable, imageName):
    logger = logging.getLogger()
    logger.info('got logo file {0}'.format(imageName))

    newImage = pdb.gimp_image_new(450, 300, RGB)

    newLayer = pdb.gimp_layer_new(newImage, 450, 300, 0, "background", 100.0, NORMAL_MODE)

    pdb.gimp_context_set_background((255, 255, 255))
    # pdb.gimp_context_set_foreground((255, 255, 255))
    pdb.gimp_drawable_fill(newLayer, gimpfu.BACKGROUND_FILL)
    logger.info('Created new background image {0}')
    newImage.add_layer(newLayer, 0)

    logger.info('loading logo {0}'.format(imageName))
    logo = pdb.gimp_file_load(imageName, imageName)
    # logoDrawable = pdb.gimp_image_get_active_layer(logo)

    #
    visibleLayer = pdb.gimp_layer_new_from_visible(logo, newImage, 'logo')
    newImage.add_layer(visibleLayer, 1)
    mergedL = pdb.gimp_image_merge_down(newImage, newLayer, 0)

    fileNameNoExt = os.path.splitext(imageName)[0]
    pdb.file_jpeg_save(newImage, mergedL, fileNameNoExt + '.jpg', fileNameNoExt + '.jpg', 1.0, 0.0, 1, 1, '', 0, 0, 0, 0)

2) 使用newImage.add_layer(visibleLayer, 0)会导致原始png图像作为输入以jpg格式存储

def scale(logo, tdrawable, imageName):
    logger = logging.getLogger()
    logger.info('got logo file {0}'.format(imageName))

    newImage = pdb.gimp_image_new(450, 300, RGB)

    newLayer = pdb.gimp_layer_new(newImage, 450, 300, 0, "background", 100.0, NORMAL_MODE)

    pdb.gimp_context_set_background((255, 255, 255))
    # pdb.gimp_context_set_foreground((255, 255, 255))
    pdb.gimp_drawable_fill(newLayer, gimpfu.BACKGROUND_FILL)
    logger.info('Created new background image {0}')
    newImage.add_layer(newLayer, 0)

    logger.info('loading logo {0}'.format(imageName))
    logo = pdb.gimp_file_load(imageName, imageName)
    # logoDrawable = pdb.gimp_image_get_active_layer(logo)

    #
    visibleLayer = pdb.gimp_layer_new_from_visible(logo, newImage, 'logo')
    newImage.add_layer(visibleLayer, 0)
    # mergedL = pdb.gimp_image_merge_down(newImage, newLayer, 0)

    fileNameNoExt = os.path.splitext(imageName)[0]
    pdb.file_jpeg_save(newImage, visibleLayer, fileNameNoExt + '.jpg', fileNameNoExt + '.jpg', 1.0, 0.0, 1, 1, '', 0, 0, 0, 0)
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1 回答 1

1

这个：

tdraw = pdb.gimp_layer_new_from_visible(timg, newImage, 'logo')      
newImage.add_layer(tdraw, 1)

不将图层添加为顶部，而是在现有的顶部添加。如果它是第二层，那么它将成为最底层。在那种情况下merge_down，没有什么可以合并的。

于 2017-05-05T23:18:44.610 回答