0

我有一个合作伙伴在大学的一个小项目中完成的 SQL 查询（这是我们第一次使用 SQL），但是我们得到了ora-00907错误，我们俩都不知道为什么。

我检查了括号，它们似乎没问题，所以问题一定是另一个问题。

select
    persona.nombre,
    anyo,
    t2.total
from persona join
(
    select
        t1.idPersona,
        count(produccion.anyo) as total,
        anyo 
        from
        (
            select *
            from produccion
            join pelicula
                on produccion.id = pelicula.id
        ) as pel
        join
        (
            select *
            from participa
            where idPapel = 8
        ) as t1
           on t1.idProduccion = pel.id
    )
    group by t1.idPersona
) as t2
    on persona.id = t2.idPersona
where t2.total > 2
order by t2.total desc;
4

3 回答 3

0

您有很多嵌套视图，这使您的查询很难调试。你有很多括号，需要匹配。

无论如何，这是错误的：select t1.idPersona, count(produccion.anyo) as total, anyo。您需要包含anyo在 GROUP BY 子句中，这可能会更改您想要的结果集。

select persona.nombre, 
       t2.anyo,
       t2.total
from persona join
        (select t1.idPersona, 
                count(produccion.anyo) as total, 
                anyo 
         from (select *
               from produccion 
                    join pelicula 
                    on produccion.id=pelicula.id) pel
               join
               (select *
                from participa
                where idPapel=8) t1
               on t1.idProduccion=pel.id
         group by t1.idPersona, t1.anyo) t2
     on persona.id=t2.idPersona
where t2.total>2
order by t2.total desc;
于 2017-05-01T11:40:47.013 回答
0

您正在选择 * 并在产生问题的一列上进行分组。要么只选择分组条件下的相应列，要么删除分组依据。

select *
               from (produccion join pelicula on produccion.id=pelicula.id) as pel
               join
               (select *
                from participa
                where idPapel=8) as t1
               on t1.idProduccion=pel.id)
         group by t1.idPersona

上面的代码部分不允许使用 group by。

如果 group by 非常需要，我建议您稍后在最后使用它。另一种选择是使用分析功能并在您已经拥有的查询的上层嵌套中过滤掉其余不需要的记录。

于 2017-05-01T11:40:56.530 回答
0

我认为您的查询可以像这样简化/更正：

select  persona.nombre,
        anyo,
        t2.total
from    persona 
join    (
           select     par.idPersona,
                      count(produccion.anyo) as total,
                      anyo 
           from       produccion
           join       pelicula
                  on  produccion.id = pelicula.id        
           left join  participa par          
                  on  par.idProduccion = pelicula.id -- or produccion.id, 
                                                     -- this was also an error in the original query,
                                                     -- since the subquery selected both
                  and par.idPapel = 8    
           group by   t1.idPersona
           ,          anyo    -- Was missing, but it also doesn't make sense, as this is what you count, so you'll just get 1's here. What do you want with this?
       ) as t2
    on persona.id = t2.idPersona
where  t2.total > 2
order by t2.total desc;
于 2017-05-01T11:43:17.110 回答