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I am trying to get public key from known private key for DNSSEC algorithm 13 (ECDSAP256SHA256). I used this example: https://stackoverflow.com/a/17062076/3090865

Which modified for my key looks this:

// using figures on: https://en.bitcoin.it/wiki/Technical_background_of_version_1_Bitcoin_addresses
// gcc -Wall ecdsapubkey.c -o ecdsapubkey -lcrypto
#include <stdio.h>
#include <stdlib.h>
#include <openssl/ec.h>
#include <openssl/obj_mac.h>
#include <openssl/bn.h>

int main()
{
     EC_KEY *eckey = NULL;
     EC_POINT *pub_key = NULL;
     const EC_GROUP *group = NULL;
     BIGNUM start;
     BIGNUM *res;
     BN_CTX *ctx;

     BN_init(&start);
     ctx = BN_CTX_new(); // ctx is an optional buffer to save time from allocating and deallocating memory whenever required

     res = &start;
     BN_hex2bn(&res,"589c51d2b528a99c1d19702f865284ec09e3e080606ddc3f56f0906268fd25e3");
     eckey = EC_KEY_new_by_curve_name(NID_secp256k1);
     group = EC_KEY_get0_group(eckey);
     pub_key = EC_POINT_new(group);

     EC_KEY_set_private_key(eckey, res);

     /* pub_key is a new uninitialized `EC_POINT*`.  priv_key res is a `BIGNUM*`. */
     if (!EC_POINT_mul(group, pub_key, res, NULL, NULL, ctx))
       printf("Error at EC_POINT_mul.\n");

     EC_KEY_set_public_key(eckey, pub_key);

     char *cc = EC_POINT_point2hex(group, pub_key, 4, ctx);

     printf("%s", cc);

     BN_CTX_free(ctx);

     free(cc);

     return 0;
}

Trying:

$ gcc -lcrypto t.c
$ ./a.out | perl -e 'print pack "H*", <>' | base64
BDdZbz79hEKFi9bIlExzZEqPQVhNqcjJqaWSWnoBTYn21XEL7y4YQXnB8N4JWAy33inTD1CyEI20
TusbH6MSxyc=

This is what I have inside DNS server (PowerDNS):

Private-key-format: v1.2
Algorithm: 13 (ECDSAP256SHA256)
PrivateKey: WJxR0rUoqZwdGXAvhlKE7Anj4IBgbdw/VvCQYmj9JeM=

Getting DNSKEY record:

$ dig @127.0.0.1 +short example.com DNSKEY
257 3 13 JELaKnxPV49rnxShsHbS8MX9rfJZcpRKgqCHUn1WYyDLcXGDYYEQ8soL I9OLVJFN5Gn/4TjXF6g0T1IEBsuFew==

And it absolutely doesn't match the key I got with OpenSSL. Why?

4

1 回答 1

1

我没有考虑到的主要事情是这个密钥有不同的长度：从 openssl 返回的密钥是 65 字节长的二进制格式，而来自 DNS 服务器的密钥是 64 字节长。如果我在十六进制编辑器中查看两个键的二进制表示，我可以看到它们仅在第一个字节上有所不同。一些更详细的解释可以在这里找到：https ://stackoverflow.com/a/43742420/3090865

所以，这段C代码可能会被改写成这样（还有一点就是使用了不正确的曲线，应该是NID_X9_62_prime256v1）：

#include <stdio.h>
#include <stdlib.h>
#include <openssl/ec.h>
#include <openssl/obj_mac.h>
#include <openssl/bn.h>

int main()
{
     EC_KEY *eckey = NULL;
     EC_POINT *pub_key = NULL;
     const EC_GROUP *group = NULL;
     BIGNUM start;
     BIGNUM *res;
     BN_CTX *ctx;

     BN_init(&start);
     ctx = BN_CTX_new(); // ctx is an optional buffer to save time from allocating and deallocating memory whenever required

     res = &start;
     BN_hex2bn(&res,"589c51d2b528a99c1d19702f865284ec09e3e080606ddc3f56f0906268fd25e3");
     eckey = EC_KEY_new_by_curve_name(NID_X9_62_prime256v1);
     group = EC_KEY_get0_group(eckey);
     pub_key = EC_POINT_new(group);

     EC_KEY_set_private_key(eckey, res);

     /* pub_key is a new uninitialized `EC_POINT*`.  priv_key res is a `BIGNUM*`. */
     if (!EC_POINT_mul(group, pub_key, res, NULL, NULL, ctx))
       printf("Error at EC_POINT_mul.\n");

     EC_KEY_set_public_key(eckey, pub_key);

     char *cc = EC_POINT_point2hex(group, pub_key, 4, ctx);

     printf("%s", cc+2);

     BN_CTX_free(ctx);

     free(cc);

     return 0;
}

现在它匹配：

$ ./a.out | perl -e 'print pack "H*", <>' | base64
JELaKnxPV49rnxShsHbS8MX9rfJZcpRKgqCHUn1WYyDLcXGDYYEQ8soLI9OLVJFN5Gn/4TjXF6g0
T1IEBsuFew==
于 2017-05-02T16:39:34.433 回答