json - 如何将此 JSON 解析为记录类型？

Question

我有一些数据将在运行时获取：

/* {id: 1, name: 'brad', age: 27, address: { city: 'city1', state: 'state1' } } */
let data = "{\"id\":1,\"name\":\"brad\",\"age\":27,\"address\":{\"city\":\"city1\",\"state\":\"state1\"}}";

使用 ReasonML 和 BuckleScript，我怎样才能以下列形式获取这些数据：

type address = {
  city: string,
  state: string
};

type person = {
  id: int,
  name: string,
  age: option int,
  address: option address
};

我想出的解决方案是 100 行长。

Answer 1

使用bs-json：

let parseAddress json =>
  Json.Decode.{
    city: json |> field "city" string,
    state: json |> field "state" string
  };

let parsePerson json =>
  Json.Decode.{
    id: json |> field "id" int,
    name: json |> field "name" string,
    age: json |> optional (field "age" int),
    address: json |> optional (field "address" parseAddress)
  };