我需要一个带有选项的结构的逗号分隔输出。例如,如果我有这个结构:
MyStruct
{
boost::optional<std::string> one;
boost::optional<int> two;
boost::optional<float> three;
};
类似的输出:{ "string", 1, 3.0 } or { "string" } or { 1, 3.0 }等等。
现在,我有这样的代码:
struct MyStruct
{
boost::optional<std::string> one;
boost::optional<int> two;
boost::optional<float> three;
};
BOOST_FUSION_ADAPT_STRUCT
(MyStruct,
one,
two,
three)
template<typename Iterator>
struct MyKarmaGrammar : boost::spirit::karma::grammar<Iterator, MyStruct()>
{
MyKarmaGrammar() : MyKarmaGrammar::base_type(request_)
{
using namespace std::literals::string_literals;
namespace karma = boost::spirit::karma;
using karma::int_;
using karma::double_;
using karma::string;
using karma::lit;
using karma::_r1;
key_ = '"' << string(_r1) << '"';
str_prop_ = key_(_r1) << ':'
<< string
;
int_prop_ = key_(_r1) << ':'
<< int_
;
dbl_prop_ = key_(_r1) << ':'
<< double_
;
//REQUEST
request_ = '{'
<< -str_prop_("one"s) <<
-int_prop_("two"s) <<
-dbl_prop_("three"s)
<< '}'
;
}
private:
//GENERAL RULES
boost::spirit::karma::rule<Iterator, void(std::string)> key_;
boost::spirit::karma::rule<Iterator, double(std::string)> dbl_prop_;
boost::spirit::karma::rule<Iterator, int(std::string)> int_prop_;
boost::spirit::karma::rule<Iterator, std::string(std::string)> str_prop_;
//REQUEST
boost::spirit::karma::rule<Iterator, MyStruct()> request_;
};
int main()
{
using namespace std::literals::string_literals;
MyStruct request = {std::string("one"), 2, 3.1};
std::string generated;
std::back_insert_iterator<std::string> sink(generated);
MyKarmaGrammar<std::back_insert_iterator<std::string>> serializer;
boost::spirit::karma::generate(sink, serializer, request);
std::cout << generated << std::endl;
}
这可行,但我需要一个逗号分隔的输出。我尝试使用如下语法:
request_ = '{'
<< (str_prop_("one"s) |
int_prop_("two"s) |
dbl_prop_("three"s)) % ','
<< '}'
;
但我收到此编译错误:
/usr/include/boost/spirit/home/support/container.hpp:194:52: error: no type named ‘const_iterator’ in ‘struct MyStruct’
typedef typename Container::const_iterator type;
谢谢!