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我正在尝试解决变量x。我想我的D变量有问题。该D变量应该将每个输入w的 . 例如，D = w[0]+w[1]+w[2]如果有 3 个输入或D = w[0]+w[1]有 2 个输入。对于实际值，goal_grade=90.0、=20、4exam_weight个额外类别、w[1]=10、p[1]=100、w[2]=20、p[2]=95.98、w[3]=30、p[3]=95.47 和w[4]=20、p[4]=96.47...x应该等于大约 62，但我得到一些巨大的数字。

<html>

<head>
  <script type='text/javascript'>
    var w = [];
    var p = [];
    var C = 0;
    var D = 0;

    function addFields() {
      // Number of inputs to create
      var number = document.getElementById("category_weight").value;
      // Container <div> where dynamic content will be placed
      var container = document.getElementById("container");
      // Clear previous contents of the container
      while (container.hasChildNodes()) {
        container.removeChild(container.lastChild);
      }
      for (i = 0; i < number; i++) {
        // create a row element to contain each pair
        var row = document.createElement("div");
        row.id = 'row' + i

        row.appendChild(document.createTextNode("Category " + (i + 1) + " weight: "));
        var weight_input = document.createElement("input");
        weight_input.type = "number";
        weight_input.name = "weight";
        row.appendChild(weight_input);

        row.appendChild(document.createTextNode("Category " + (i + 1) + " percentage: "));
        var percentage_input = document.createElement("input");
        percentage_input.type = "number";
        percentage_input.name = "percentage";
        row.appendChild(percentage_input);

        // append inputs to row instead of container, then append each row to container
        container.appendChild(row);
      }
    }

    function weighted() {

      var container = document.getElementById("container");
      var rows = container.children;
      for (var i = 0; i < rows.length; i++) {
        var row = rows[i];
        w[i] = row.children[0].value; // or row.querySelectorAll('[name=weight]').value;
        p[i] = row.children[1].value;

      }

      for (var i = 0; i < rows.length; i++) {
        // You can do as much calculation here with w[i] & p[i]
        C += w[i] * p[i];
        D += w[i];

      }
      console.log(C);
      console.log(D);

      var x = "";
      var A = parseFloat(document.getElementById("goal_grade").value);
      var B = parseFloat(document.getElementById("exam_weight").value);


      x = (A * (D + B) - C) / B;

      if (x <= 0) {
        x = 0;
      }

      document.getElementById("result").innerHTML = x;

    }
  </script>
</head>

<body>
  <span>What final percentage in the class are you trying to reach or stay         above?</span>
  <input type="number" id="goal_grade" name="goal_grade" />

  <br>
  <br>

  <span>What percent is the final exam weighted?</span>
  <input type="number" id="exam_weight" name="exam_weight" />

  <br>
  <br>

  <span>How many extra weighted categories are there?</span>
  <input type="number" id="category_weight" name="category_weight" value=""> <br />
  <button type="button" onclick="addFields()">Submit </button>
  <div id="container"></div>

  <br>
  <br>

  <input type="button" value="Calculate" onclick="weighted()" />

  <br>
  <br>

  <span>You will need to get <p id="result" name="r1"> </p> points out of the ... <p id="totpoints" name="tot_points"> </p> points possible on the final"
</span>

</body>

</html>

4

1 回答 1

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只是改变

    C += w[i] * p[i];
    D += w[i];

和

    C += parseFloat(w[i] * p[i]);
    D += parseFloat(w[i]);

你很好。

于 2017-04-24T22:46:50.453 回答