php - mysql_real_escape_string() 没有转义任何东西

Question

1. 我需要在我的 INSERT 和 SELECT FROM 语句中使用真正的转义吗？

2. 为什么我在以下示例中使用的语法不起作用（这只是我尝试过的众多方法之一）？

   //insert user input for word 1
   $sql = "INSERT INTO test (Word1, Word2, Word3, Word4, Word5)
   VALUES('$Word1','$Word2','$Word3','$Word4','$Word5')",
   mysql_real_escape_string($Word1),
   mysql_real_escape_string($Word2),
   mysql_real_escape_string($Word3),
   mysql_real_escape_string($Word4),
   mysql_real_escape_string($Word5);
   if(!mysql_query($sql,$con))
   {
     die('Error: ' . mysql_error());
   }
   

Answer 1

看起来您正在尝试使用sprintf()，要正确执行此操作，您需要稍微重新格式化代码：

$sql = sprintf("INSERT INTO test (Word1, Word2, Word3, Word4, Word5)
VALUES('%s','%s','%s','%s','%s')",
mysql_real_escape_string($Word1),
mysql_real_escape_string($Word2),
mysql_real_escape_string($Word3),
mysql_real_escape_string($Word4),
mysql_real_escape_string($Word5)
);

Answer 2

我强烈建议您完全避免转义，并直接使用mysqli::prepare转到准备好的语句，也许通过PDO。它最终更简单，更安全：

$dsn = 'mysql:dbname=test;host=127.0.0.1';
$user = 'dbuser';
$password = 'dbpass';

$dbh = new PDO($dsn, $user, $password);

$sql =
    'INSERT INTO mytable ' .
    '(Word1, Word2, Word3, Word4, Word5)' .
    'VALUES(?, ?, ?, ?, ?)';

$stmt = $dbh->prepare($sql);

$words = array('word1', 'word2', 'word3', 'word4', 'word5');
$stmt->execute($words);

$words = array('word6', 'word7', 'word8', 'word9', 'word10');
$stmt->execute($words);