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我找到了一种让用户通过我的应用程序拨打电话的方法。但是，我希望用户能够选择从中拨打电话的应用程序（电话、Viber、Skype），类似于社交共享功能，但用于电话。

我现在用这个直接拨号： 

public static func callNumber(phoneNumber: String) {  
let cleanPhoneNumber = phoneNumber.trimmingCharacters(in: CharacterSet(charactersIn: "01234567890").inverted)
        if let phoneCallURL = URL(string: "tel://\(cleanPhoneNumber)")  {
            if UIDevice.current.model.range(of: "iPad") != nil {
                print("Your device doesn't support this feature.")
            } else {
                let application: UIApplication = UIApplication.shared
                if (application.canOpenURL(phoneCallURL)) {
                    let mobileNetworkCode = CTTelephonyNetworkInfo().subscriberCellularProvider?.mobileNetworkCode
                    if( mobileNetworkCode == nil) {
                        print(" No sim present Or No cellular coverage or phone is on airplane mode.")
                    }
                    else {
                        application.openURL(phoneCallURL);
                    }
                }
            }
        }
    }

有没有办法让它像社交分享一样快速工作。谢谢您的帮助。

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1 回答 1

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有一个叫做 URL shemes (URI) 的东西。https://useyourloaf.com/blog/querying-url-schemes-with-canopenurl/

func open(scheme: String) {
  if let url = URL(string: scheme) {
    UIApplication.shared.open(url, options: [:], completionHandler: {
      (success) in
      print("Open \(scheme): \(success)")
    })
  }
}

open(scheme: "skype:<params>")
open(scheme: "viber:<params>")

Skype：https
: //msdn.microsoft.com/en-us/library/office/dn745885.aspx Viber：https ://developers.viber.com/tools/deep-links/index.html

于 2017-04-23T11:39:30.010 回答