2

我在 mongo 集合中有一个名为 (CustomerInformation) 的文档，其结构如下。

        {     "_id" : ObjectId("58f5e68c8205281d68bbb290"), 
            "_class" : "com.test.dataservices.entity.CustomerInformation", 
            "organizationInformation" : {
                "_id" : "123", 
                "companyName" : "Test1", 
                "ibanNumber" : "12345e", 
                "address" : "estates", 
                "contractInformation" : {
                    "duration" : NumberInt(0), 
                    "contractType" : "Gold", 
                    "totalUsers" : NumberInt(0)
                }, 
                "users" : [
                    {

                        "firstName" : "testuser1", 
                        "emailAddress" : "testuser1@test.com", 
                        "password" : "test1@123", 
                        "userAccessType" : "admin"
                    }, 
                    {

                        "firstName" : "testuser2", 
                        "emailAddress" : "testuser2@test.com", 
                        "password" : "test2@123", 
                        "userAccessType" : "user"
                    }
                ]
            }
        }

现在我只想检索具有匹配电子邮件地址和密码的用户信息。我正在尝试如下。

Criteria elementMatchCriteria = Criteria.where("organizationInformation.users").
    elemMatch(Criteria.where("emailaddress").is("testuser1@test.com").and("password").is(test1@123));

    BasicQuery query = new BasicQuery(elementMatchCriteria.getCriteriaObject());

  CustomerInformation customer =mongoOperations.findOne(query, CustomerInformation.class);

我正在获取包含所有用户数组的完整文档，我只想检索匹配的用户信息 emailAddress 和密码。我的查询或数据模型有什么问题？有什么建议么？谢谢！

4

2 回答 2

2

使用位置投影。

Criteria elementMatchCriteria = Criteria.where("organizationInformation.users").elemMatch(Criteria.where("emailAddress").is("testuser1@test.com").and("password").is("test1@123"));
Query query = Query.query(elementMatchCriteria);
query.fields().position("organizationInformation.users", 1);
CustomerInformation customer =mongoOperations.findOne(query, CustomerInformation.class);
于 2017-04-18T11:59:38.223 回答
0

您可以使用带有 $unwind 的聚合查询来实现这一点

db.collection.aggregate([
    {
        $unwind:"$organizationInformation.users"
    },
    {
        $match:{
            "organizationInformation.users.emailAddress":"testuser1@test.com",
            "organizationInformation.users.password":"test1@123"
        }
    },
    {
        $project:{
            "organizationInformation.users":1
        }
    }
 ])

结果是：

{
    "_id" : ObjectId("58f5e68c8205281d68bbb290"),
    "organizationInformation" : {
        "users" : {
            "firstName" : "testuser1",
            "emailAddress" : "testuser1@test.com",
            "password" : "test1@123",
            "userAccessType" : "admin"
        }
    }
}

或者

db.collection.aggregate([
    {
        $unwind:"$organizationInformation.users"
    },
    {
        $match:{
            "organizationInformation.users.emailAddress":"testuser1@test.com",
            "organizationInformation.users.password":"test1@123"
        }
    },
    {
        $project:{
            user: "$organizationInformation.users"
        }
    }
])

结果是：

{
    "_id" : ObjectId("58f5e68c8205281d68bbb290"),
    "user" : {
        "firstName" : "testuser1",
        "emailAddress" : "testuser1@test.com",
        "password" : "test1@123",
        "userAccessType" : "admin"
    }
}
于 2017-04-18T11:32:59.237 回答