php - pg_query 抛出错误

Question

我正在尝试从 postgresql 数据库中获取数据，但出现错误： pg_last_error() 期望参数 1 是资源，/path/to/query.php 中给出的对象所以数据是作为对象而不是资源。任何想法如何解决这一问题？

SQL 使用以下代码：

foreach ($conn->query($sql1) as $row) 
{
print $row["Site_ID"] . " ";
print $row["Site_name_1"] . "<br /> ";

}

但是当我改用 pg_query 时，问题就出现了。
这是我的代码：

<?php include 'header.php'; ?> 
<div class='container'> 
<?php include 'menu.php'; ?>
<?php include 'PDO_connect.php'; ?>

<?php

$sql1='SELECT "Site_ID", "Site_name_1" FROM "Sites" ORDER BY "Sites"."Site_ID" ASC'; 

$result1 = pg_query($conn,$sql1);
if(!$result1) {
    echo "There is an error!";
    echo pg_last_error($conn);
}
?>

我的连接信息

<?php
try {
$dbuser = 'usr';
$dbpass = 'pwd';
$host = "localhost";
$dbname="db";

$conn = new PDO('pgsql:host=localhost;dbname=db', $dbuser, $dbpass);
}catch (PDOException $e) {
echo "Error : " . $e->getMessage() . "<br/>";
die();
}
?>

Answer 1

正如评论中所说，我混合了 PDO 和 pg_connect，这解决了我的问题：

<?php
$servername = "localhost"; 
$username = "usr"; 
$password = "pwd";
$database = "db";
?>

<?php
    $conn = pg_connect("host=localhost dbname=$database user=$username password=$password")or die("Can't connect to database".pg_last_error());
?>