javascript - 如何在保持执行顺序的同时减少异步等待中 await 关键字的使用

Question

async function foo() {
  await this.getAsync();
  await this.getAsyncTwo();
  await this.getAsyncThree();
  await this.getAsyncFour();
}

看看 foo 如何有多个等待调用，有没有办法在保持执行顺序的同时简化它？

我希望有可能写出类似的东西

async function foo() {
  await 
   this.getAsync(), 
   this.getAsyncTwo(), 
   this.getAsyncThree(), 
   this.getAsyncFour();
}

或者

async function foo() {
  await 
   this.getAsync() 
   .this.getAsyncTwo() 
   .this.getAsyncThree()
   .this.getAsyncFour();
}

score 3 · Accepted Answer

这将保证您希望的顺序执行顺序。

async function foo() {
  const functions = [this.getAsync, this.getAsyncTwo, ...];

  for (let func of functions) { 
    await func();
  }
}

score 1 · Accepted Answer

You can await on a Promise.all()

await Promise.all([this.getAsync(), this.getAsyncTwo(), /* etc */])

2 回答 2