php - 来自 while 循环的输入数组，为每个输入传递 $_POST

Question

<form role="form" autocomplete="off" action="includes/functions/fisa-init.php" method="POST">
<?php
   connectDB();
   $query = mysqli_query($mysqli, "SELECT * FROM `optionale`") or die(mysqli_error($mysqli));
   while($row = mysqli_fetch_array($query))
   { 
?>
   <span><?php echo $row['denumire']; ?></span>
   <input type="text" name="nrBucati[]">
   <input type="hidden" value="<?php echo $row['cod']; ?>" name="codProdus[]">
<?php } ?>
</form>

在 while 循环中，我得到一个数组 forinput name="nrBucati[]"和input name="codProdus[]"。

我有一个查询：

$stmt3 = $mysqli->prepare("
            UPDATE 
            `stocuri` 
            SET 
            `cantitate` = `cantitate` - ?
            WHERE `cod` = ?
            ");


    $stmt3->bind_param("is", $bucata, $cod);

    // set parameters and execute
    foreach( $_POST['nrBucati'] as $bucata ) {
    return $bucata; 
    }

    foreach( $_POST['codProdus'] as $cod ) {
    return $cod;
    }

    if (!$stmt3->execute()) 
        {
            echo "Execuția a întâmpinat o eroare: (" . $stmt3->errno . ") " . $stmt3->error;
        }
    $stmt3->close();

我无法设法通过$_POST. 详述于：

While 循环 - 许多其他输入中只有一个输入通过 POST 发送值

如何通过 POST从数组nrBucati[]和HTML 中获取每个输入值？codProdus[]

Answer 1

运行 a并在循环foreach内准备数据：foreach

// Get posted data and execute
foreach( $_POST['nrBucati'] as $key=>$bucata ) {
    $cod = $_POST['codProdus'][$key]; // For object change this to $_POST['codProdus']->$key;

    $stmt3= $mysqli->prepare("UPDATE `stocuri` SET `cantitate` = `cantitate` - ? 
                              WHERE `cod` = ? ");
    $stmt3->bind_param("is", $bucata, $cod);

    if (!$stmt3->execute()){

        echo "Execuția a întâmpinat o eroare: (" . $stmt3->errno . ") " . $stmt3->error;
    }

    $stmt3->close();

}

Answer 2

这样的事情可以正确分配/配对您的两个参数，然后从循环中执行您的查询调用。

foreach( $_POST['nrBucati'] as $id => $bucata ) {
    $cod = $_POST['codProdus'][$id];

    if (!$stmt3->execute()) 
        {
            echo "Execuția a întâmpinat o eroare: (" . $stmt3->errno . ") " . $stmt3->error;
        }
}