我想使用数据库中的池温度数据创建一个注释图表。您可以在 sqlfiddle或rextester上查看数据库结构,但为了节省您的点击,这是我正在使用的结构:
DROP TABLE IF EXISTS `temperatures`;
DROP TABLE IF EXISTS `pools`;
CREATE TABLE `pools` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`name` varchar(255) COLLATE utf8mb4_unicode_ci NOT NULL,
`created_at` timestamp NULL DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci;
CREATE TABLE `temperatures` (
`id` int(10) unsigned NOT NULL AUTO_INCREMENT,
`pool_id` int(10) unsigned NOT NULL,
`temperature` double(8,1) NOT NULL,
`created_at` timestamp NULL DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `temperatures_pool_id_foreign` (`pool_id`),
CONSTRAINT `temperatures_pool_id_foreign` FOREIGN KEY (`pool_id`) REFERENCES `pools` (`id`) ON DELETE CASCADE
) ENGINE=InnoDB AUTO_INCREMENT=3173 DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_unicode_ci;
INSERT INTO `pools` (`id`, `name`, `created_at`)
VALUES
(1,'Pool #1','2017-04-08 22:48:03'),
(2,'Pool #2','2017-04-08 22:48:03'),
(3,'Pool #3','2017-04-08 22:48:03');
INSERT INTO `temperatures` (`id`, `pool_id`, `temperature`, `created_at`)
VALUES
(31,1,100.1,'2017-04-09 02:44:56'),
(32,2,104.2,'2017-04-09 02:44:56'),
(33,3,97.0,'2017-04-09 02:44:56'),
(34,1,100.1,'2017-04-09 03:00:04'),
(35,2,98.4,'2017-04-09 03:00:04'),
(36,3,96.6,'2017-04-09 03:00:04'),
(37,1,100.1,'2017-04-09 03:37:13'),
(38,2,101.8,'2017-04-09 03:37:13'),
(39,3,96.4,'2017-04-09 03:37:13'),
(40,1,100.1,'2017-04-09 04:00:04'),
(41,2,101.8,'2017-04-09 04:00:04'),
(42,3,96.5,'2017-04-09 04:00:04'),
(43,1,100.1,'2017-04-09 05:00:04'),
(44,2,101.8,'2017-04-09 05:00:04');
好的,基本上,我创建了一个控制器,它将返回格式正确的 JSON 以用于 ajax 和 google.visualization.DataTable(),如下所示:
var jsonData = $.ajax({
url: "/data/pool-temperature-timeline",
dataType: "json",
async: false
}).responseText;
data = new google.visualization.DataTable(jsonData);
chart.draw(data, options);
当然,查看文档,注释图表期望事情遵循这种格式:
var data = new google.visualization.DataTable();
data.addColumn('date', 'Date');
data.addColumn('number', 'Kepler-22b mission');
data.addColumn('string', 'Kepler title');
data.addColumn('string', 'Kepler text');
data.addColumn('number', 'Gliese 163 mission');
data.addColumn('string', 'Gliese title');
data.addColumn('string', 'Gliese text');
data.addRows([
[new Date(2314, 2, 15), 12400, undefined, undefined,
10645, undefined, undefined],
[new Date(2314, 2, 16), 24045, 'Lalibertines', 'First encounter',
12374, undefined, undefined],
[new Date(2314, 2, 17), 35022, 'Lalibertines', 'They are very tall',
15766, 'Gallantors', 'First Encounter'],
[new Date(2314, 2, 18), 12284, 'Lalibertines', 'Attack on our crew!',
34334, 'Gallantors', 'Statement of shared principles'],
[new Date(2314, 2, 19), 8476, 'Lalibertines', 'Heavy casualties',
66467, 'Gallantors', 'Mysteries revealed'],
[new Date(2314, 2, 20), 0, 'Lalibertines', 'All crew lost',
79463, 'Gallantors', 'Omniscience achieved']
]);
var chart = new google.visualization.AnnotationChart(document.getElementById('chart_div'));
对了,就是这样设置,现在问题来了。组织数据的最佳方法是什么,以便 1.) 池 1、2 和 3 始终有相同日期时间的温度数据(我担心给定时间戳的数据集可能不完整)?我应该使用一些聪明的查询从 SQL 层开始组织它吗?或者我是否通过使用一堆 foreach 循环在控制器中组织它?这是我正在努力的目标:
$dataTable->addRow(['created_at',
'temperature1', 'title1', 'text1',
'temperature2', 'title2', 'text2',
'temperature2', 'title2', 'text2',
]);
我可以看到聪明的查询将是避免在控制器中执行一堆逻辑和 foreach 循环的好方法。也许如果数据按列组织,例如:
created_at, pool_1_temperature, pool_2_temperature, pool_3_temperature
------------------------------------------------
2017-04-09 02:44:56, 100.1, 104.2, 97.0
2017-04-09 03:00:04, 100.1, 98.4, 96.6
2017-04-09 03:37:13, 100.1, 101.8, 96.4
然后我可以很容易地完成它并创建 DataTable。我不确定如何在 MySQL 中执行此操作,或者即使这是一个好主意。
感谢您抽出宝贵的时间,并提前感谢您的帮助。我希望我足够清楚。
PS。我想到目前为止我遇到的最接近的事情是 Mysql query to dynamic convert rows to columns。我要再玩这个了……