1

我想将混合 cpabe_BSW07 加密的密文存储在文件中，但是在对密文进行腌制时发现错误：

引发 TypeError，“无法腌制 %s 个对象”% base.__name__
TypeError：无法腌制元素对象

from charm.toolbox.pairinggroup import PairingGroup
from charm.schemes.abenc.abenc_bsw07 import CPabe_BSW07
from charm.adapters.abenc_adapt_hybrid import HybridABEnc
import pickle


if __name__ == "__main__":
  groupObj = PairingGroup('SS512')
  cpabe = CPabe_BSW07(groupObj)
  hyb_abe = HybridABEnc(cpabe, groupObj)
  (pk, mk) = hyb_abe.setup()
  access_policy = '((four or three) and (two or one))'
  sk = hyb_abe.keygen(pk, mk, ['ONE', 'TWO', 'THREE'])

  sourcefile = open("source.dat", 'rb')
  plaintext = sourcefile.read()
  sourcefile.close()

  encryptedfile = open("encrypted.dat", 'wb')
  ciphertext = hyb_abe.encrypt(pk, plaintext, access_policy)
  pickle.dump(ciphertext, encryptedfile)
  encryptedfile.close()
4

2 回答 2

2

哈哈哈，我现在知道怎么解决了：

from charm.toolbox.pairinggroup import PairingGroup
from charm.schemes.abenc.abenc_bsw07 import CPabe_BSW07
from charm.adapters.abenc_adapt_hybrid import HybridABEnc
import pickle

if __name__ == "__main__":
  groupObj = PairingGroup('SS512')
  cpabe = CPabe_BSW07(groupObj)
  hyb_abe = HybridABEnc(cpabe, groupObj)
  (pk, mk) = hyb_abe.setup()
  access_policy = '((four or three) and (two or one))'
  sk = hyb_abe.keygen(pk, mk, ['ONE', 'TWO', 'THREE'])

  sourcefile = open("source.dat", 'rb')
  plaintext = sourcefile.read()
  sourcefile.close()

  encryptedfile = open("encrypted.dat", 'wb')
  ciphertext = hyb_abe.encrypt(pk, plaintext, access_policy)
  ciphertext["c1"]["C"] = groupObj.serialize(ciphertext["c1"]["C"])
  for key in ciphertext["c1"]["Cy"] :
      ciphertext["c1"]["Cy"][key] = groupObj.serialize(ciphertext["c1"]["Cy"][key])
  ciphertext["c1"]["C_tilde"] = groupObj.serialize(ciphertext["c1"]["C_tilde"])
  for key in ciphertext["c1"]["Cyp"] :
    ciphertext["c1"]["Cyp"][key] = groupObj.serialize(ciphertext["c1"]["Cyp"][key])
  pickle.dump(ciphertext, encryptedfile)
  encryptedfile.close()

  encryptedfile = open("encrypted.dat", 'rb')
  ciphertext2 = pickle.load(encryptedfile)
  ciphertext2["c1"]["C"] = groupObj.deserialize(ciphertext2["c1"]["C"])
  for key in ciphertext2["c1"]["Cy"]:
    ciphertext2["c1"]["Cy"][key] = groupObj.deserialize(ciphertext2["c1"]["Cy"][key])
  ciphertext2["c1"]["C_tilde"] = groupObj.deserialize(ciphertext2["c1"]["C_tilde"])
  for key in ciphertext2["c1"]["Cyp"]:
    ciphertext2["c1"]["Cyp"][key] = groupObj.deserialize(ciphertext2["c1"]["Cyp"][key])
  print hyb_abe.decrypt(pk, sk, ciphertext2) == plaintext
  encryptedfile.close()
于 2017-04-06T12:01:40.373 回答
1

我在尝试使用 json、pickle、simplejson 序列化 Charm crypto 生成的 dict 时遇到了同样的问题，并通过使用charm.core.engine.util .objectToBytes|bytesToObject 方法解决了它。

from charm.core.engine.util import objectToBytes, bytesToObject
<...>
emsg = objectToBytes(cipher_text,group)
msg = bytesToObject(fin.read(),group)
于 2018-03-22T08:56:37.593 回答