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我正在尝试创建一个 observable（此处为 fixedObservable），它将由多个动态创建的 observable 随时间提供。每当进行订阅时，订阅者都应该从 fixedObservable 获取最新值。虽然我已经实现了，但我想知道是否有任何简单的解决方案。你可以在这里找到代码https://jsfiddle.net/dzm2t3pa/8/。

谢谢 

var resultdiv = document.getElementById('result');

function print(message) {
  var paraEl = document.createElement('p');
  paraEl.innerHTML = message;
  resultdiv.appendChild(paraEl);
}
var startTime = new Date();

var fixedObservable = new Rx.Subject();
var subscription;

function subscribe() {
  subscription = fixedObservable.subscribe(function(value) {
    print('subscriber 1:' + value + ' :after ' + (new Date() - startTime) / 1000 + ' secs');
  });
}

function unsubscribe() {
  subscription.unsubscribe();
}
// Subscribe to the fixedObservable(i.e Subject) initiallly
subscribe()

//Unsubscribe and resubscribe after 11 sec here to see what
// happens in that period.
//Observation: The values generated in that period are not received as needed.
setTimeout(unsubscribe, 11000);
setTimeout(subscribe, 22000);

//just a simple check with multiple subscribers later.All the
//subscribers get the latest value. 
/*setTimeout(function(){
  fixedObservable.subscribe(function(value){
   	print('subscriber 2:'+value+' :after '+(new Date()-startTime)/1000+' secs');
   });
},30000);*/
//setTimeout(function(){},)

//Initial Observables which feed the data to fixedObservable
var dynamicObservable1 = Rx.Observable.interval(4000);
var dynamicObservable2 = Rx.Observable.interval(5000);
var counter1 = 0;
//subscribe to dynamic observable and pass the data to fixedObservable
dynamicObservable1.subscribe(function(value) {
  counter1 += 1;
  fixedObservable.next(counter1 + 'th value from 1');
});
var counter2 = 0;
dynamicObservable2.subscribe(function(value) {
  counter2 += 1;
  fixedObservable.next(counter2 + 'th value from 2');
});

//create a dynamicObservable after 5secs to feed the data and 
// then destroy it after 2.5 sec i.e at 7.5 sec from start.
//Observation: 2 value from this stream is received and then stops
setTimeout(function() {
  var counter3 = 0;
  var dynamicObservable3 = Rx.Observable.interval(1000);
  var subs = dynamicObservable3.subscribe(function(value) {
    counter3 += 1;
    fixedObservable.next(counter3 + 'th value from 3');
  });
  setTimeout(function() {
    subs.unsubscribe()
  }, 2500)
}, 5000);

setTimeout(function() {
  unsubscribe();
}, 50000)
<script src="https://cdnjs.cloudflare.com/ajax/libs/rxjs/5.0.1/Rx.min.js"></script>
<div id="result">

</div>

4

1 回答 1

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使用合并，我猜不需要主题。这样的事情适合你吗？

const dyn1 = Rx.Observable.interval(300)
                      .timeInterval()
                      .map(interval => {return {value:interval.value, origin:'dyn1'}});
const dyn2 = Rx.Observable.interval(601)
                          .timeInterval()
                          .map(interval => {return {value:interval.value, origin:'dyn2'}});

const m = Rx.Observable.merge(dyn1, dyn2);
m.subscribe(v => console.log(v.value + " from " + v.origin));
于 2017-03-31T07:57:53.227 回答