I googled "Runnable" and found out
that it is an interface. Am I
implementing the interface by
declaring the run method between curly
brackets ? Can this be done for any
interface in java ?
Yes!
This code is instantiating an object which implements Runnable. Because we can't actually construct an interface, any code which attempts to do so must provide implementations for the interface's methods in curly brackets. We don't really get to see what class Java is creating to implement Runnable (these are abstract terms).
If you were to do the following:
Runnable runnable = new Runnable()
{
public void run()
{
System.out.println("I'm running");
}
};
runnable.run();
you would see "I'm running" as your output.