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我的 app.service 文件的 [Service] 部分如下：-

[Service]
Type=forking
Restart=no
IgnoreSIGPIPE=no
GuessMainPID=no
ExecStart=/opt/app/appl_init.d start
ExecStop=/opt/app/appl_init.d stop
TimeoutSec=infinity

之后我安装了应用程序，文件被正确复制到/usr/lib/systemd/system/app.service.

我已经运行了systemctl daemon-reload，但它似乎对启动时间没有影响！它在我运行时失败systemctl start app或systemctl reload app.service出现以下错误：-

Job for app.service failed because a fatal signal was delivered to the control process. See "systemctl status app.service" and "journalctl -xe" for details

的输出systemctl status app是： -

● app.service - ApplicationTest
   Loaded: loaded (/opt/app/appl_init.d; enabled; vendor preset: disabled)
   Active: failed (Result: signal) since Tue 2017-03-21 01:55:22 EDT; 1min 4s ago
     Docs: man:app(8)
  Process: 4126 ExecStart=/opt/app/appl_init.d start (code=killed, signal=KILL)

Mar 21 01:55:22 centosvm systemd[1]: Starting ApplicationTest...
Mar 21 01:55:22 centosvm systemd[1]: app.service start operation timed out. Terminating.
Mar 21 01:55:22 centosvm systemd[1]: app.service stop-final-sigterm timed out. Killing.
Mar 21 01:55:22 centosvm systemd[1]: app.service: control process exited, code=killed status=9
Mar 21 01:55:22 centosvm systemd[1]: Failed to start ApplicationTest.
Mar 21 01:55:22 centosvm systemd[1]: Unit app.service entered failed state.
Mar 21 01:55:22 centosvm systemd[1]: app.service failed.

我注意到的另一件奇怪的事情是，当我跑步时systemctl show app.service -p TimeoutSec，我没有得到任何结果；它是空白的？

我试过做一个systemctl reboot，但仍然没有骰子。

当然，当我将值更改为其他任何值时TimeoutSec=5min，它都可以正常工作。但我真的需要这个应用程序来占用无穷大。

我哪里错了？

4

1 回答 1

6

TimeoutSec=0解决了这个问题。

显然，如果您使用的 systemd 版本早于 229，则需要使用 0 而不是 infinity 来禁用超时。

于 2018-01-09T12:19:25.913 回答