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我想在“ instanceData ”下的\“标签\”之后获取所有键值对，并在“属性”下制作它们的键值对。

我有这个...

{
  "id": "/subscriptions/1234abcd-ab12-12ab-12ab-abcdfghi1234/Daily_BRSDT_20161214_0000",
  "name": "Daily_BRSDT_20161214_0000",
  "type": "Microsoft.Commerce/UsageAggregate",
  "properties": {
    "subscriptionId": "1234abcd-ab12-12ab-12ab-abcdfghi1234",
    "usageStartTime": "2017-03-08T00:00:00+00:00",
    "usageEndTime": "2017-03-09T00:00:00+00:00",
    "meterName": "Standard IO - File Read Operation Units (in 10,000s)",
    "meterCategory": "Data Management",
    "unit": "10,000s",
    "instanceData": "{\"Microsoft.Resources\":{\"resourceUri\":\"/subscriptions/1234abcd-ab12-12ab-12ab-abcdfghi1234/resourceGroups/default-resource-group67/providers/Microsoft.Storage/storageAccounts/defaultstorage67\",\"location\":\"ussouthcentral\",\"tags\":{\"ProjectName\":\"default Portal\",\"billTo\":\"Technology\",\"component\":\"Persistant Storage\",\"department\":\"Technology\",\"displayName\":\"default Portal Storage Account\",\"enviornment\":\"default\",\"function\":\"Reporting\",\"matterNumber\":\"999999\",\"primaryowner\":\"john@internet.com\",\"productLine\":\"Information Components\",\"secondaryowner\":\"mary@internet.com\",\"version\":\"1.0.0.0\"}}}",
    "meterId": "12345ab-259d-4206-a6ae-12345678abcd",
    "infoFields": {},
    "quantity": 0.0004
  }
}

我要这个...

{
  "id": "/subscriptions/1234abcd-ab12-12ab-12ab-abcdfghi1234/Daily_BRSDT_20161214_0000",
  "name": "Daily_BRSDT_20161214_0000",
  "type": "Microsoft.Commerce/UsageAggregate",
  "properties": {
    "subscriptionId": "1234abcd-ab12-12ab-12ab-abcdfghi1234",
    "usageStartTime": "2017-03-08T00:00:00+00:00",
    "usageEndTime": "2017-03-09T00:00:00+00:00",
    "meterName": "Standard IO - File Read Operation Units (in 10,000s)",
    "meterCategory": "Data Management",
    "unit": "10,000s",
    "instanceData": "{\"Microsoft.Resources\":{\"resourceUri\":\"/subscriptions/1234abcd-ab12-12ab-12ab-abcdfghi1234/resourceGroups/default-resource-group67/providers/Microsoft.Storage/storageAccounts/defaultstorage67\",\"location\":\"ussouthcentral\"}}",
    "ProjectName":"default Portal",
    "billTo":"Technology",
    "component":"Persistant Storage",
    "department":"Technology",
    "displayName":"default Portal Storage Account",
    "enviornment":"default",
    "function":"Reporting",
    "matterNumber":"999999",
    "primaryowner":"john@internet.com",
    "productLine":"Information Components",
    "secondaryowner":"mary@internet.com",
    "version":"1.0.0.0",
    "meterId": "12345ab-259d-4206-a6ae-12345678abcd",
    "infoFields": {},
    "quantity": 0.0004
  }
}

有没有一种简单的方法来转换它？我试图用 RegEx 来做这件事，但没有运气。

4

1 回答 1

1

我建议看这样的东西：

如何在 ASP.NET 中将 JSON 反序列化为简单的 Dictionary<string,string>？

将 List<KeyValuePair<string, string>> 序列化为 JSON

实际上，您将需要删除要解析的一个键，然后将其重新添加到您的 JSON 对象中。

Json.NET - Newtonsoft 的工具非常适合使用 JSON。 http://www.newtonsoft.com/json

最简单的方法：

  1. 将整个 JSON 字符串转换为 Dictionary 或List<KeyValuePair<string,string>>.
  2. 获取要拆分的 instanceData 位，然后将其解析为另一个 C# 对象。
  3. 使用某种逻辑将两个对象合并在一起，以确保没有重复的键。
  4. 将您的对象序列化回 JSON

这是一种简单的方法，虽然不是最有效的方法。

于 2017-03-13T18:59:23.240 回答