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我在控制器中有这段代码，它接受一个类作为参数

public ActionResult Index(PaginationModel paginationViewModel = null)
{
    //do some logic here
    return View(viewModel);
}

这就是模型的样子

public class PaginationModel
{
    protected const int DisplayPageRange = 2;

    //Pagination Related Properties
    public int CurrentPage { get; set; }
    public int TotalPages { get; set; }
    public int TotalItems { get; set; }
    public string PageName { get; set; }
    public int ItemsPerPage { get; set; }
    public int DefaultItemsPerPage { get; set; }
    public string PagingText { get; set; }

    //Filters
    public string Search { get; set; }
    public string Category { get; set; }
    public string Star { get; set; }
    public string Director { get; set; }
    public string Writer { get; set; }
}

我在视图中调用动作

<a href="/?Category=@genre">@genre</a>

一切似乎都很好，但我想格式化 URL，所以它看起来像

Movie/Index/Horror/1   //Horror is the category and 1 is the current page number

目前，它正在显示

Movie/Index?Category=Horror&Page=1

我可以使用单独的参数而不是在动作中使用类来做到这一点

public ActionResult Index(string category, int pagenum, etc etc)
{

}

但是有没有办法在 RouteConfig 中使用类作为参数来做到这一点？

编辑：

我的 RouteConfig 是

public static void RegisterRoutes(RouteCollection routes)
{
    routes.IgnoreRoute("{resource}.axd/{*pathInfo}");

    routes.MapRoute(
        name: "MovieSearch",
        url: "Movie/Index/{Category}",
        defaults: new { controller = "Movie", action = "Index", id = UrlParameter.Optional }
    );

    routes.MapRoute(
        name: "AdminSearch",
        url: "{controller}/{action}/{key}",
        defaults: new {controller = "Admin", action = "Search", id = UrlParameter.Optional}
    );

    routes.MapRoute(
        name: "Default",
        url: "{controller}/{action}/{id}",
        defaults: new { controller = "Movie", action = "Index", id = UrlParameter.Optional }
    );
}
4

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