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我想知道如何将一个bimap实际上太大（1.8 亿到 30 亿个条目）的二进制文件写入二进制文件，然后读取以执行一些操作。为了创建一个bimap我有以下代码，我在其中创建了两个流来写入和读取二进制数据。我还将元素插入到bimap.

#include <string>
#include <iostream>
#include <utility>
#include <fstream>
#include <boost/bimap.hpp>
#include <boost/bimap/unordered_set_of.hpp>
#include <boost/bimap/unordered_multiset_of.hpp>

namespace bimaps = boost::bimaps;
typedef boost::bimap<bimaps::unordered_set_of<unsigned long long int>,
        bimaps::unordered_multiset_of<unsigned long long int > > bimap_reference;
typedef bimap_reference::value_type position;
bimap_reference numbers;

int main()
{
    std::ofstream outfile ("bmap",std::ofstream::binary);
    std::ifstream infile ("bmap",std::ifstream::binary);

    numbers.insert(position(123456, 100000));
    numbers.insert(position(234567, 80000));
    numbers.insert(position(345678, 100000));
    numbers.insert(position(456789, 80000));

    //want to write the file

    //want to read the file


    // So that I can perform the following operation
    using ritr = bimap_reference::right_const_iterator;
    std::pair<ritr, ritr> range = numbers.right.equal_range(80000);
    auto itr = range.first;
    std::cout<<"first: "<<itr->first<<std::endl;
    if(itr != numbers.right.end() && itr->second ==80000){
        for (itr = range.first; itr != range.second; ++itr)
        {
            std::cout<<"numbers:"<<itr->second<<"<->"<<itr->first<<std::endl;
        }
    }
    else {
        std::cout<<"Not found:"<<std::endl;
    }
    return 0;
}

我想写bimap，然后再读一遍以执行一些操作。怎么做。

4

1 回答 1

1

为了处理bimap二进制文件的写入/读取，boost 序列化非常有用。你需要包括

#include <boost/archive/binary_oarchive.hpp>
#include <boost/archive/binary_iarchive.hpp>

作为头文件。然后，您需要有用于写入和读取的文件流，以及用于写入和读取的文件boost::archive::binary_oarchive流boost::archive::binary_iarchive。还要确保使用-lboost_serialization. 完整的代码如下。

#include <string>
#include <iostream>
#include <utility>
#include <fstream>
#include <boost/bimap.hpp>
#include <boost/bimap/unordered_set_of.hpp>
#include <boost/bimap/unordered_multiset_of.hpp>
#include <boost/archive/binary_oarchive.hpp>
#include <boost/archive/binary_iarchive.hpp>



namespace bimaps = boost::bimaps;
typedef boost::bimap<bimaps::unordered_set_of<unsigned long long int>,
        bimaps::unordered_multiset_of<unsigned long long int > > bimap_reference;
typedef bimap_reference::value_type position;
bimap_reference numbers;

int main()
{

    // insert elements into bimap and write to a binary file
    {
        numbers.insert(position(123456, 100000));
        numbers.insert(position(234567, 80000));
        numbers.insert(position(345678, 100000));
        numbers.insert(position(456789, 80000));

        std::ofstream ofs("data");
        boost::archive::binary_oarchive oa(ofs);
        oa << const_cast<const bimap_reference&>(numbers);
        const bimap_reference::left_iterator left_iter = numbers.left.find(123456);
        oa << left_iter;
        const bimap_reference::right_iterator right_iter = numbers.right.find(100000);
        oa << right_iter;
    }

    // load the bimap back to memory
    {
        std::ifstream ifs("data", std::ios::binary);
        boost::archive::binary_iarchive ia(ifs);
        ia >> numbers;
        assert( numbers.size() == 4 ); // to throw an error
        bimap_reference::left_iterator left_iter;
        ia >> left_iter;
        assert( left_iter->first == 123456 );
        bimap_reference::right_iterator right_iter;
        ia >> right_iter;
        assert( right_iter->first == 100000 );
    }

    // then perform the following operation
    using ritr = bimap_reference::right_const_iterator;
    std::pair<ritr, ritr> range = numbers.right.equal_range(80000);
    auto itr = range.first;
    std::cout<<"first: "<<itr->first<< " <-> " << itr->second<<std::endl;
    if(itr != numbers.right.end() && itr->first ==80000){
        for (itr = range.first; itr != range.second; ++itr)
        {
            std::cout<<"numbers:"<<itr->second<<"<->"<<itr->first<<std::endl;
        }
    }
    else {
        std::cout<<"Not found:"<<std::endl;
    }
    return 0;
}
于 2017-03-13T09:49:48.797 回答