2

您好，我在表中有以下数据：

ID-----startDate----endDate
5549 2008-05-01 4712-12-31
5567 2008-04-17 2008-04-30 1
5567 2008-05-01 2008-07-31 1
5567 2008- 09-01 4712-12-31 2
5569 2008-05-01 2008-08-31
5569 2008-09-01 4712-12-31
5589 2008-04-18 2008-04-30
5589 2008-05-01 4712- 12-31
5667 2008-05-01 4712-12-31
5828 2008-06-03 4712-12-31
5867 2008-06-03 4712-12-31
6167 2008-11-01 4712-12-31
6207 2008- 07-01 4712-12-31
6228 2008-07-01 4712-12-31
6267 2008-07-14 4712-12-31

我正在寻找将每个 id 返回的连续时间间隔分组的方法：

ID，最小值（开始日期），最大值（结束日期），

在粗体 ID 5567 的结果中得到类似的结果

5567 2008-04-17 2008-07-31
5567 2008-09-01 4712-12-31

PL/SQL 也是这里的一个选项 :)

谢谢，

4

6 回答 6

5

我认为这将满足您的需要：（请注意，重叠范围可能会混淆；不知道它们是否可能在您的数据集中）

select id, min(start_date) period_start, max(end_date) period_end
from
(
select 
    id, start_date, end_date,
    max(contig) over (partition by id order by end_date) contiguous_group
from
(
select 
    id, start_date, end_date,
    case 
        when lag(end_date) over (partition by id order by end_date) != start_date-1 or row_number() over (partition by id order by end_date)=1 
            then row_number() over (partition by id order by end_date) else null end contig
from t2
)
)
group by id, contiguous_group
order by id, period_start
/

这是我使用的测试数据 - 基于您的数据，还有几个额外的条目：

create table t2 (id number, start_date date, end_date date);

insert into t2(id, start_date, end_date)values(5549, to_date('2008-05-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5567, to_date('2008-04-17', 'yyyy-mm-dd'), to_date('2008-04-30', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5567, to_date('2008-05-01', 'yyyy-mm-dd'), to_date('2008-07-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5567, to_date('2008-08-01', 'yyyy-mm-dd'), to_date('2008-08-14', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5567, to_date('2009-09-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5567, to_date('2008-11-17', 'yyyy-mm-dd'), to_date('2008-12-13', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5567, to_date('2008-12-14', 'yyyy-mm-dd'), to_date('2008-12-24', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5569, to_date('2008-05-01', 'yyyy-mm-dd'), to_date('2008-08-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5569, to_date('2008-09-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5589, to_date('2008-04-18', 'yyyy-mm-dd'), to_date('2008-04-30', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5589, to_date('2008-05-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5667, to_date('2008-05-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5828, to_date('2008-06-03', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(5867, to_date('2008-06-03', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(6167, to_date('2008-11-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(6207, to_date('2008-07-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(6228, to_date('2008-07-01', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));
insert into t2(id, start_date, end_date)values(6267, to_date('2008-07-14', 'yyyy-mm-dd'), to_date('4712-12-31', 'yyyy-mm-dd'));

commit;
于 2009-01-09T11:04:34.170 回答
1

你可以用这样的分析函数来做到这一点：

with d as
( select id, start_date, end_date
  ,      case when start_date = prev_end+1 
              then 'cont' else 'new' end start_status
  ,      case when end_date = next_start-1
              then 'cont' else 'new' end end_stat
  from
  (
  select id, start_date, end_date
  ,      lag(end_date) over (partition by id order by start_date) prev_end
  ,      lead(start_date) over (partition by id order by start_date) next_start
  from t1
  order by id, start_date
  )
)
select starts.id, starts.start_date, ends.end_date
from
( select id, start_date, row_number() over (order by id, start_date) rn
  from   d
  where  start_status='new'
) starts,
( select id, end_date, row_number() over (order by id, start_date) rn
  from   d
  where  end_status='new'
) ends
where starts.rn = ends.rn

我用你的数据得到这个结果：

        ID START_DATE END_DATE
---------- ---------- ----------
      5549 2008-05-01 4712-12-31
      5567 2008-04-17 2008-07-31
      5567 2008-09-01 4712-12-31
      5569 2008-05-01 4712-12-31
      5589 2008-04-18 4712-12-31
      5667 2008-05-01 4712-12-31
      5828 2008-06-03 4712-12-31
      5867 2008-06-03 4712-12-31
      6167 2008-11-01 4712-12-31
      6207 2008-07-01 4712-12-31
      6228 2008-07-01 4712-12-31
      6267 2008-07-14 4712-12-31

12 rows selected.

这个怎么运作：

  1. WITH子句生成数据的视图D，其中每一行都分配了一个“开始状态”和一个“结束状态”，每一个都是'new'或'cont'来表示它是否与上一行/下一行连续或不。
  2. 内联视图“开始”和“结束”分别仅拉出具有“新”开始状态/结束状态的行，并使用行号将它们结合起来。
  3. “主查询”然后从这 2 个视图中选择并加入行号列。
于 2009-01-09T11:05:29.097 回答
0

您将必须编写如下所示的 PL/SQL 块示例逻辑；

Create or Replace someproc
Declare
    Cursore someCur AS
    Select * from someTable
    Order by ID,StartDate

    IDVar as Varchar(10)
    MinDate as DATE
    MaxDate as DATE

Begin
    Open someCur
    Fetch ID,StartDate,EndDate into IDVar,MinDate,MaxDate
    While SomeCur%NOTFOUND
    LOOP
        Fetch ID,StartDate,EndDate into TempID,TempStartDate,TempEndDate
        if IDVar <> TempID then
            -- output into your required structure values: IDVar,MinDate,MaxDate
            IDVar = TempID
            MinDate = TempStartDate
            MaxDate = TempEndDate
            Exit Loop
        ELSE IF
            MaxDate+1 >= TempStartDate THEN
            MaxDate = TempEndDate
        END IF
    End LOOP
于 2009-01-09T09:18:55.647 回答
0

我不在要测试的实例附近，但是您尝试过吗？

SELECT
 ID, 
 startDate,
 endDate
FROM
 myTable
WHERE
 (ID, startDate) in 
 (SELECT
   ID, 
   min(startDate) 
  FROM
   myTable
  GROUP BY
   ID
  )

  or 

 (ID, endDate) in 
 (SELECT
   ID, 
   max(endDate) 
  FROM
   myTable
  GROUP BY
   ID
  )

这应该为您提供所有最早startDate的 s，以及每个 ID 的最新endDates。连续与否。

于 2009-01-09T15:28:32.227 回答
0 
WITH
  laik_test AS -- sample data
(select 1001 id, date'2012-01-03' start_date, date'2012-06-29' end_date from dual union
 select 1001 id, date'2012-03-03' start_date, date'2012-08-29' end_date from dual union
 select 1002 id, date'2012-06-03' start_date, date'2012-11-29' end_date from dual union
 select 1001 id, date'2012-09-03' start_date, date'2013-02-20' end_date from dual union
 select 1001 id, date'2013-02-08' start_date, date'2013-04-29' end_date from dual union
 select 1002 id, date'2012-11-03' start_date, date'2012-12-29' end_date from dual union
 select 1002 id, date'2012-12-23' start_date, date'2013-09-29' end_date from dual union
 select 1002 id, date'2013-08-03' start_date, date'2015-06-29' end_date from dual union
 select 1001 id, date'2013-04-13' start_date, date'2013-09-29' end_date from dual union
 select 1001 id, date'2013-07-03' start_date, date'2014-06-29' end_date from dual union
 select 1003 id, date'2012-12-23' start_date, date'2013-09-29' end_date from dual union
 select 1001 id, date'2013-07-03' start_date, date'2014-06-29' end_date from dual union
 select 1003 id, date'2012-12-23' start_date, date'2013-09-29' end_date from dual union
 select 1003 id, date'2013-09-30' start_date, date'2014-06-29' end_date from dual union
 select 1003 id, date'2013-12-30' start_date, date'2014-03-11' end_date from dual union
 select 1003 id, date'2014-06-29' start_date, date'2015-09-29' end_date from dual )
, matrica AS
(  select id, start_date, end_date
        , lead(start_date) over (partition by id order by start_date, end_date) start_date_next
        , lag(end_date) over (partition by id order by start_date, end_date) end_date_prev
  from laik_test m
 where not exists (select * 
                     from laik_test n
                    where m.id = n.id
                      and m.start_date > n.start_date and m.end_date < n.end_date))
, matrica2 AS
(select id, end_date
  from matrica m
 where start_date_next is null OR start_date_next > end_date + 1)
, matrica3 AS
(select id, start_date
  from matrica m
 where end_date_prev is null OR end_date_prev < start_date - 1)
, matrica4 AS
(select m2.id, m3.start_date, m2.end_date
  from matrica2 m2, matrica3 m3
 where m2.id=m3.id and m3.start_date < m2.end_date)
select id, start_date, end_date
  from matrica4 m
 where not exists (select * from matrica4 n
                    where m.id = n.id
                      and (   (n.start_date = m.start_date and m.end_date > n.end_date)
                           OR (n.end_date = m.end_date and m.start_date < n.start_date)
                          ));

结果是：

ID   | start_date | end_date
1001 | 2012-01-03 | 2012-08-29
1001 | 2012-09-03 | 2014-06-29
1002 | 2012-06-03 | 2015-06-29
1003 | 2012-12-23 | 2015-09-29
于 2013-07-15T13:24:32.080 回答
-1

我一直在尝试为重叠范围做一些事情，但对这些数据有些困难：

     INSERT INTO zzz_scrap_dates (id,effdate,termdate)

SELECT id,effdate,termdate from (
SELECT '1'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '1'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2010-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '1'id ,To_Date('2005-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '1'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '1'id ,To_Date('1999-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
union
SELECT '2'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '2'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2010-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '2'id ,To_Date('2005-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '2'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '2'id ,To_Date('1999-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
union
SELECT '3'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '3'id ,To_Date('1998-01-01','YYYY-MM-DD')effdate,To_Date('1999-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '3'id ,To_Date('1005-01-01','YYYY-MM-DD')effdate,To_Date('1197-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '3'id ,To_Date('2000-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
UNION
SELECT '3'id ,To_Date('1197-01-01','YYYY-MM-DD')effdate,To_Date('2020-01-31','YYYY-MM-DD')termdate FROM dual
于 2010-07-09T10:06:37.763 回答