1

当我尝试使用 mkdocs2pandoc 生成 .pd 时,出现以下错误

Traceback (most recent call last):
  File "/usr/bin/mkdocs2pandoc", line 11, in <module>
    load_entry_point('mkdocs-pandoc==0.2.6', 'console_scripts', 'mkdocs2pandoc')()
  File "/usr/lib/python2.7/site-packages/mkdocs_pandoc/cli/mkdocs2pandoc.py", line 80, in main
    for line in pconv.convert():
  File "/usr/lib/python2.7/site-packages/mkdocs_pandoc/pandoc_converter.py", line 165, in convert
    lines = mkdocs_pandoc.filters.tables.TableFilter().run(lines)
  File "/usr/lib/python2.7/site-packages/mkdocs_pandoc/filters/tables.py", line 177, in run
    ret.extend(self.convert_table(block))
  File "/usr/lib/python2.7/site-packages/mkdocs_pandoc/filters/tables.py", line 91, in convert_table
    for i in range(0, len(self._split_row(lines_orig[0], has_border))):
TypeError: _split_row() takes exactly 2 arguments (3 given)

我刚刚开始了新的虚拟环境,并且只安装了 mkdocs-pandoc

pip install mkdocs-pandoc
4

1 回答 1

2

问题是由于 Markdown 2.6.8(当前最新)与 mkdocs-pandoc 包一起安装,我查看了其中的 _split_row() 方法,看起来它改变了签名,所以临时修复是安装 Marckdown 2.6 .7,并等到 mkdocs-pandoc 更新。

于 2017-03-10T11:22:09.947 回答