1

我有一种情况，员工有 time-in 和 time-out 但他们被保存到一个类型为[in =1 ,out = 2]的列中，我需要获取单个员工时间（in-out）用 Time-In、Time-Out 标题分隔的单行。

这是我拥有的表格示例，

CREATE TABLE #Employee
(
empid int,
name varchar(20),
age int
)
CREATE TABLE #TIMEINOUT
(
    id int,
    empid int,
    timeinout datetime,
    [type] tinyint
)

INSERT INTO #Employee values(1,'Benny',35)
INSERT INTO #Employee values(2,'Algo',32)


INSERT INTO #TIMEINOUT VALUES(1,1,'2017-03-08 06:00:00 AM',1) -- (Type 1 = IN , 2 = Out)
INSERT INTO #TIMEINOUT VALUES(2,1,'2017-03-08 05:00:00 PM',2) -- (Type 1 = IN , 2 = Out)
INSERT INTO #TIMEINOUT VALUES(3,2,'2017-03-08 07:00:00 AM',1) -- (Type 1 = IN , 2 = Out)
INSERT INTO #TIMEINOUT VALUES(4,2,'2017-03-08 09:00:00 PM',2) -- (Type 1 = IN , 2 = Out)



SELECT * FROM #Employee INNER JOIN #TIMEINOUT ON #Employee.empid = #TIMEINOUT.empid

Select #Employee.empid,#Employee.name,#Employee.age,GETDATE() as TimeIN,GETDATE() as TimeOUT from #Employee

DROP TABLE #Employee
DROP TABLE #TIMEINOUT

任何人都可以帮助简化查询吗？

4

3 回答 3

1

也许是这样的？单独的列Timein和TimeOut

;with cte as (
SELECT e.empid,e.name,e.age,t.timeinout as TimeIn FROM #Employee e INNER  JOIN #TIMEINOUT t ON e.empid = t.empid
 where t.type=1
 )
 select t.empid,t.name,t.age,t.timein as TimeIn,t2.timeinout as Timeout from cte t

 inner join (
select * from #timeinout
where type=2
)t2
 on t.empid=t2.empid
于 2017-03-08T07:18:27.827 回答
1

看看这个：

select a.empid,a.timeinout,b.timeinout from 
(select *,CONVERT(VARCHAR(10),timeinout,110) as this_in from TIMEINOUT where type = 1) as a
inner join
(select *,CONVERT(VARCHAR(10),timeinout,110) as this_out from TIMEINOUT where type = 2) as b
on a.empid = b.empid where a.this_in = b.this_out
于 2017-03-08T07:29:22.343 回答
0

我就是这样做的

SELECT  #Employee.empid ,
    #Employee.name ,
    #TIMEINOUT.timeinout [TimeIN],
    X.timeinout [TimeOUT]
FROM    #Employee
    INNER JOIN #TIMEINOUT ON #TIMEINOUT.empid = #Employee.empid
    LEFT JOIN ( SELECT  #TIMEINOUT.empid ,
                        #TIMEINOUT.timeinout
                FROM    #TIMEINOUT
                WHERE   type = 2
              ) X ON X.empid = #Employee.empid
                     AND CONVERT(VARCHAR(10), #TIMEINOUT.timeinout, 111)   = CONVERT(VARCHAR(10), X.timeinout, 111)
WHERE   #TIMEINOUT.type = 1
于 2017-03-08T15:18:33.033 回答