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是否可以使用 postgresql 在上一行和下一行创建中间行?

我有结果

rownumber   from    to  with
1   1,303   2,88    A
2   2,88    5,65    A
3   5,65    8,659   A
4   8,659   10,342  A
5   10,33   24,188  B
6   10,342  26,253  C
7   26,253  26,38   A
8   26,38   30,442  A
9   30,442  35,672  A

我需要这个

rownumber   from    to  with
1   1,303   2,88    A
2   2,88    5,65    A
3   5,65    8,659   A
4   8,659   10,33   A
    10,33   10,342  A
5   10,342  24,188  B

6   24,188  26,253  C
7   26,253  26,38   A
8   26,38   30,442  A
9   30,442  35,672  A
4

1 回答 1

1

如果我理解正确,最简单的方法是:

WITH x AS (
   SELECT DISTINCT sfrom FROM stages
   UNION SELECT sto FROM stages
), y AS (
   SELECT sfrom, row_number() OVER (ORDER BY sfrom) AS i FROM x
)
SELECT y2.i,
       y2.sfrom,
       y.sfrom as sto,
       coalesce(x2.swith, x.swith) as xwith
FROM y JOIN y AS y2 ON (y.i = y2.i + 1)
LEFT JOIN stages AS x ON (x.sfrom = y2.sfrom)
LEFT JOIN stages AS x2 ON (x2.sto = y.sfrom)
ORDER BY 1
;
于 2017-03-07T22:49:38.403 回答