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我有一个新问题。我有短代码js:
SenAffet += String.fromCharCode(parseInt(YaRabbim.substr(n, 2), 16));
如何将其转换为 PHP?
答案是:$int = intval(substr($link,$n,2),16); $SenAffet .= chr($int);;
$int = intval(substr($link,$n,2),16); $SenAffet .= chr($int);;