5

我正在构建一个 React 前端,它允许用户从静态查询列表中选择一个“活动”查询,并将结果展平为要在表格中显示的结果。将 GraphQL 查询从高阶组件传递到嵌套子组件的最佳方法是什么?

我见过的大多数文档/解决方案都侧重于将静态查询与从组件状态到组件的动态条件绑定,这不适用于我的目的,因为不同的静态查询具有不同的字段并查询不同的节点类型。

这里的最佳实践/推荐方法是什么?我觉得这不是一个非常独特的用例,但我似乎找不到任何可以做类似事情的例子。

我使用 Apollo-Client/Redux 作为我的客户端商店。

下面是组件的大致轮廓:

class GridViewPage extends React.Component{
  constructor(props, context) {
    super(props, context);
    this.state = {
      activeQuery = ... Stores the selected query ...
    };
  }

  render() {
    return (
      <div className="gridContainer">
        ...Component here allows users to select a query from the active list and saves it/it's ID/Index to the state...

        <Panel collapsible>
        ...Some toolbar components...
        </Panel>
        ...Component here displays the result of the query (Ideally by receiving the query or the result of as a prop?)...
      </div>
    );
  }
}

GridViewPage.propTypes = {
  grids: PropTypes.array.isRequired,
  actions: PropTypes.object.isRequired
};

function mapStateToProps(state, ownProps) {
  return {
      // Receives list of available queries as a prop
      grids: state.grids
  };
}

4

1 回答 1

3

让我们以以下组件为例:

ProfileWithData.js

import React, { Component, PropTypes } from 'react';
import { graphql } from 'react-apollo';
import gql from 'graphql-tag';

class Profile extends Component { ... }
Profile.propTypes = {
  data: PropTypes.shape({
    loading: PropTypes.bool.isRequired,
    currentUser: PropTypes.object,
  }).isRequired,
};

// We use the gql tag to parse our query string into a query document
const CurrentUserForLayout = gql`
  query CurrentUserForLayout {
    currentUser {
      login
      avatar_url
    }
  }
`;

const ProfileWithData = graphql(CurrentUserForLayout)(Profile);

用更高阶的组件包装它会很容易:

Profile.js

import React, { Component, PropTypes } from 'react';

export class Profile extends Component { ... }
Profile.propTypes = {
  data: PropTypes.shape({
    loading: PropTypes.bool.isRequired,
    currentUser: PropTypes.object,
  }).isRequired,
};

createProfileWithData.js

import React, { Component, PropTypes } from 'react';
import { graphql } from 'react-apollo';
import { Profile } from './Profile'

export default function createProfileWithData(query) => {
  return graphql(query)(Profile);
}

然后你会像这样使用它:

页面.js

import React, { Component, PropTypes } from 'react';
import gql from 'graphql-tag';
import createProfileWithData from './createProfileWithData';

class Page extends Component {  

  renderProfileWithData() {

      const { textQuery } = this.props;
      // Simplest way, though you can call gql as a function too
      const graphQLQuery = gql`${textQuery}`;

      const profileWithDataType = createProfileWithData(graphQLQuery);

      return (
        <profileWithDataType />
      );
  }

  render() {

    return (<div>
                ..
                {this.renderProfileWithData()}
                ..
           </div>)
  }

}

Profile.propTypes = {
  textQuery: PropTypes.string.isRequired,
};

我认为你说对了。

当然,您的 Profile 不会收到props.data.currentUser,而是props.data.*取决于根查询,您将根据内容适当地处理它。

注意:这是直接在 Stack Overflow 中编写的,所以如果您遇到任何问题 - lmk 我会修复它。

于 2017-03-02T23:01:38.247 回答