嗨,我有一个 Job 1 被触发,每分钟触发一次, Job 2 每 5 分钟触发一次。因此,每隔五分钟,两个作业将同时运行,我想避免这种情况并强制第二个作业触发以等待另一个作业完成后再开始。我见过@DisallowConcurrentExecution 但这只会避免相同作业的两个实例的并行运行,而不是不同作业之间的并行运行。
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对于那些感兴趣的人,我设法将两个工作融合在一个工作中,但有两个不同的触发器指向同一个工作。每个触发器都有自己的触发时间,并且参数现在保存在每个触发器的数据映射中,而不是作业数据映射中。此外,误击策略已更改为 MisfireHandlingInstructionFireAndProceed
这是代码:
public class QuartzTest {
public static final String PROCESS_TRIGGER_MAP_KEY = "process";
public static void main( String[] args ) throws SchedulerException, InterruptedException {
SchedulerFactory schedulerFactory = new StdSchedulerFactory();
Scheduler scheduler = schedulerFactory.getScheduler();
scheduler.start();
JobDetail job1 = newJob( TestJob.class ).withIdentity( "job1", "group1" ).build();
CronTrigger trigger1 = newTrigger().withIdentity( "trigger1", "group1" ).startAt( new Date() ).withSchedule( cronSchedule( getCronExpression( 1 ) ).withMisfireHandlingInstructionFireAndProceed() ).build();
trigger1.getJobDataMap().put( PROCESS_TRIGGER_MAP_KEY, new MessagePrinter() {
@Override
public void print() {
System.out.println( new Timestamp( System.currentTimeMillis() ) + " This is process 1" );
}
} );
scheduler.scheduleJob( job1, trigger1 );
CronTrigger trigger2 = newTrigger().withIdentity( "trigger2", "group1" ).forJob( job1 ).startAt( new Date() ).withSchedule( cronSchedule( getCronExpression( 2 ) ).withMisfireHandlingInstructionFireAndProceed() ).build();
trigger2.getJobDataMap().put( PROCESS_TRIGGER_MAP_KEY, new MessagePrinter() {
@Override
public void print() {
System.out.println( new Timestamp( System.currentTimeMillis() ) + " This is process 2" );
}
} );
scheduler.scheduleJob( trigger2 );
Thread.sleep( 5 * 60 * 1000 );
}
private static String getCronExpression( int interval ) {
return "0 */" + interval + " * * * ?";
}
}
这是工作类
@DisallowConcurrentExecution
public class TestJob implements Job {
@Override
public void execute( JobExecutionContext context ) throws JobExecutionException {
MessagePrinter mp = (MessagePrinter) context.getTrigger().getJobDataMap().get( QuartzTest.PROCESS_TRIGGER_MAP_KEY );
if ( mp != null ) {
mp.print();
} else {
System.out.println( new Timestamp( System.currentTimeMillis() ) + " Job started" );
}
System.out.println( new Timestamp( System.currentTimeMillis() ) + " Job sleeping 10s..." );
try {
Thread.sleep( 10 * 1000 );
} catch ( InterruptedException e ) {
e.printStackTrace();
}
System.out.println( new Timestamp( System.currentTimeMillis() ) + " Job finished." );
}
}
和处理器类:
public abstract class MessagePrinter {
public MessagePrinter() {
}
public abstract void print();
}
于 2017-03-01T23:33:21.393 回答