3

我不确定如何发送 HTTP Auth 标头。

我有以下 HttpClient 来获取请求,但不确定如何发送请求?

public class RestClient extends AsyncTask<String, Void, JSONObject> {
        private String convertStreamToString(InputStream is) {
            /*
             * To convert the InputStream to String we use the
             * BufferedReader.readLine() method. We iterate until the
             * BufferedReader return null which means there's no more data to
             * read. Each line will appended to a StringBuilder and returned as
             * String.
             */
            BufferedReader reader = new BufferedReader(new InputStreamReader(is));
            StringBuilder sb = new StringBuilder();

            String line = null;
            try {
                while ((line = reader.readLine()) != null) {
                    sb.append(line + "\n");
                }
            } catch (IOException e) {
                e.printStackTrace();
            } finally {
                try {
                    is.close();
                } catch (IOException e) {
                    e.printStackTrace();
                }
            }

            return sb.toString();
        }

        /*
         * This is a test function which will connects to a given rest service
         * and prints it's response to Android Log with labels "Praeda".
         */
        public JSONObject connect(String url) {
            HttpClient httpclient = new DefaultHttpClient();

            // Prepare a request object
            HttpGet httpget = new HttpGet(url);

            // Execute the request
            HttpResponse response;
            try {
                response = httpclient.execute(httpget);
                // Examine the response status
                Log.i("Praeda", response.getStatusLine().toString());

                // Get hold of the response entity
                HttpEntity entity = response.getEntity();

                if (entity != null) {

                    // A Simple JSON Response Read
                    InputStream instream = entity.getContent();
                    String result = convertStreamToString(instream);

                    // A Simple JSONObject Creation
                    JSONObject json = new JSONObject(result);

                    // Closing the input stream will trigger connection release
                    instream.close();

                    return json;
                }

            } catch (ClientProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            } catch (JSONException e) {
                e.printStackTrace();
            }

            return null;
        }

        @Override
        protected JSONObject doInBackground(String... urls) {
            return connect(urls[0]);
        }

        @Override
        protected void onPostExecute(JSONObject json) {

        }
    }
4

3 回答 3

6

这在 HttpClient文档及其示例代码中有所介绍。

于 2010-11-22T22:49:10.877 回答
0

也许 HttpClient 的文档可以提供帮助:link

于 2010-11-22T22:49:58.060 回答
0

由于 Android 编译的是 HttpClient 4.0.x 而不是 3.x,下面的代码片段供您参考。

    if (authState.getAuthScheme() == null) {
        AuthScope authScope = new Au    HttpRequestInterceptor preemptiveAuth = new HttpRequestInterceptor() {
    public void process(final HttpRequest request, final HttpContext context) throws HttpException, IOException {
        AuthState authState = (AuthState) context.getAttribute(ClientContext.TARGET_AUTH_STATE);
        CredentialsProvider credsProvider = (CredentialsProvider) context.getAttribute(
                ClientContext.CREDS_PROVIDER);
        HttpHost targetHost = (HttpHost) context.getAttribute(ExecutionContext.HTTP_TARGET_HOST);thScope(targetHost.getHostName(), targetHost.getPort());
        Credentials creds = credsProvider.getCredentials(authScope);
        if (creds != null) {
            authState.setAuthScheme(new BasicScheme());
            authState.setCredentials(creds);
        }
    }
}    
};
DefaultHttpClient httpclient = new DefaultHttpClient();
httpclient.addRequestInterceptor(preemptiveAuth, 0);
于 2011-11-17T02:57:51.693 回答