我使用 JavaScript 创建了一个表,但它没有使用我的 css 呈现。那么我怎样才能让它工作呢?实际上我需要更多帮助,我的想法是创建一个具有一个按钮的屏幕,一旦您单击它,就会显示一个菜单,该菜单是从屏幕顶部开始并在屏幕末尾结束的一列表格. 该表格将是可滚动的,并且每一行都有文本(url 文本),文本下方没有 url 行,因此当您单击它时,页面会在表格和按钮后面的所有屏幕中打开。该按钮应始终显示(但当我单击它时它会消失)。main.js 文件是
function makeTableHTML() {
var x = document.createElement("TABLE");
x.setAttribute("id", "myTable");
var myArray = [ [ "Name, http://www.google.com" ],
[ "Name, http://www.google.com" ] ];
var result = '<table width = "300">';
for (var i = 0; i < myArray.length; i++) {
result += "<tr><td>";
if (i < 10) {
result += "0" + i + " ";
} else {
result += i + " ";
}
result += '<a href="' + myArray[i][0] + '">';
result += myArray[i][1] + "</a>";
result += "<td></tr>";
}
result += "</table>";
document.write(result);
document.getElementById("channelsmenu").classList.toggle(result);
}
function hideTableHTML() {
var x = document.getElementById('channelsmenu');
x.style.display = 'none';
}
我的html是
<!DOCTYPE html>
<html>
<head>
<title>5Star-IPTV</title>
<link rel="stylesheet" type="text/css" href="css/style.css" />
<script src="js/main.js"></script>
</head>
<body>
<div>
<table>
<tr>
<td>
<div id="channelsmenu" class="dropdown-content"></div>
</td>
<td class="buttons-col"><input type="image"
src="channels-menu.png" class="buttons" alt="channels menue"
onMouseOver="this.src='channels-menu-1.png'"
onMouseOut="this.src='channels-menu.png'" onclick="makeTableHTML()" /></td>
<td class="buttons-col"><input type="image"
src="return-button.png" alt="return button" class="buttons"
onMouseOver="this.src='return-button-1.png'"
onMouseOut="this.src='return-button.png'" onclick="hideTableHTML()" /></td>
</tr>
</table>
</div>
</body>
</html>
这是CSS
table {
width: 100%;
border: 1px solid black;
background-color: #808080;
}
tr {
width: 100%;
align: right;
}
th, td {
text-align: right;
} background-color: #808080;
}
.buttons-col {
text-align: center;
width: 90px;
padding-top: 5px;
}