24

如何创建 react-router v4 面包屑?我尝试通过问题单在 react-router V4 网站上提出这个问题。他们只是说要查看递归路径示例。我真的很想在语义-ui-react中创建它

4

7 回答 7

29

我也在追求同样的事情,你的问题为我指明了正确的方向。

这对我有用:

const Breadcrumbs = (props) => (
    <div className="breadcrumbs">
        <ul className='container'>
            <Route path='/:path' component={BreadcrumbsItem} />
        </ul>
    </div>
)

const BreadcrumbsItem = ({ match, ...rest }) => (
    <React.Fragment>
        <li className={match.isExact ? 'breadcrumb-active' : undefined}>
            <Link to={match.url || ''}>
                {match.url}
            </Link>
        </li>
        <Route path={`${match.url}/:path`} component={BreadcrumbsItem} />
    </React.Fragment>
)
于 2017-03-13T21:13:46.370 回答
7

我用于semantic-ui-react我自己的项目并这样做是为了创建基于的面包屑location.pathname

export default (props) => {
    const paths = props.pathname.split('/').map((p, i, arr) => {
        if (i === 0) return {
            key: i, 
            content: (<Link to={'/'}>home</Link>), 
            active: (i === arr.length - 1), 
            link: (i < arr.length - 1)
        };

        if (i === arr.length - 1) return {
            key: i, 
            content: p, 
            active: (i === arr.length - 1)
        };

        return {
            key: i, 
            content: (<Link to={`${arr.slice(0, i + 1).join('/')}`}>{p}</Link>), 
            active: (i === arr.length - 1), 
            link: (i < arr.length - 1)}
        };
    );
    return <Breadcrumb icon='chevron right' sections={paths}/>;
};
于 2017-04-30T01:55:54.087 回答
5

这可以使用解析pathname来自 react-router 并返回匹配的 HOC 来完成。虽然有点冗长,但我认为它提供了更大的灵活性和可读性好的面包屑配置对象数组。

Breadcrumbs.jsx

import React from 'react';
import { NavLink } from 'react-router-dom';
import { withBreadcrumbs } from 'withBreadcrumbs';

const UserBreadcrumb = ({ match }) =>
  <span>{match.params.userId}</span>; // use match param userId to fetch/display user name

const routes = [
  { path: 'users', breadcrumb: 'Users' },
  { path: 'users/:userId', breadcrumb: UserBreadcrumb},
  { path: 'something-else', breadcrumb: ':)' },
];

const Breadcrumbs = ({ breadcrumbs }) => (
  <div>
    {breadcrumbs.map(({ breadcrumb, path, match }) => (
      <span key={path}>
        <NavLink to={match.url}> // wrap breadcrumb with semantic-ui element
          {breadcrumb}
        </NavLink>
        <span>/</span>
      </span>
    ))}
  </div>
);

export default withBreadcrumbs(routes)(Breadcrumbs);

withBreadcrumbs.js

import React from 'react';
import { matchPath, withRouter } from 'react-router';

const renderer = ({ breadcrumb, match }) => {
  if (typeof breadcrumb === 'function') { return breadcrumb({ match }); }
  return breadcrumb;
};

export const getBreadcrumbs = ({ routes, pathname }) => {
  const matches = [];

  pathname
    .replace(/\/$/, '')
    .split('/')
    .reduce((previous, current) => {
      const pathSection = `${previous}/${current}`;

      let breadcrumbMatch;

      routes.some(({ breadcrumb, path }) => {
        const match = matchPath(pathSection, { exact: true, path });

        if (match) {
          breadcrumbMatch = {
            breadcrumb: renderer({ breadcrumb, match }),
            path,
            match,
          };
          return true;
        }

        return false;
      });

      if (breadcrumbMatch) {
        matches.push(breadcrumbMatch);
      }

      return pathSection;
    });

  return matches;
};

export const withBreadcrumbs = routes => Component => withRouter(props => (
  <Component
    {...props}
    breadcrumbs={
      getBreadcrumbs({
        pathname: props.location.pathname,
        routes,
      })
    }
  />
));

开源 HOC 也可在此处获得: https ://github.com/icd2k3/react-router-breadcrumbs-hoc

于 2017-11-02T17:54:22.583 回答
5

这两种方法的问题在于您只能在面包屑路径中使用路径名。也就是说,您必须将您的路由与您的路线的演示名称联系起来。

于 2017-05-04T14:41:45.617 回答
2

试试这个简单的解决方案:

const Breadcrumbs = ({ ...rest, match }) => (
  <span>
      <Link to={match.url || ''} className={match.isExact ? 'breadcrumb active' : 'breadcrumb'}>
          {match.url.substr(match.url.lastIndexOf('/')+1, match.url.length)}
      </Link>
      <Route path={`${match.url}/:path`} component={Breadcrumbs} />
  </span>
)

你的CSS:

.breadcrumbs {
  background: #fff;
  margin-bottom: 15px;
}
.breadcrumb {
  margin-bottom: 0;
  line-height: 2.5;
  display: inline-block; 
}
.breadcrumb::before {
  display: inline-block;
  padding-right: 5px;
  padding-left: 5px;
  color: #818a91;
  content: "/"; }
.breadcrumb.active {
  color: #818a91; }

然后像这样使用它:

<div className="container-fluid breadcrumbs">
  <Route path='/:path' component={Breadcrumbs} />
</div>

快乐编码!

于 2017-10-14T10:18:18.157 回答
2

来自react-router文档:<Route>当位置与路由的路径匹配时,组件正在渲染您的一些组件,如下所示:

<Route path={`${match.url}/:topicId`} component={Topic}/>

<Topic>在这种情况下,呈现的组件对信息的基本责任是可用的。它知道如何获取数据或者它已经绑定了 Redux 状态等等。所以<Topic>简单地实例化面包屑项目代理并将所需的数据传递给它,如下所示:

import {BreadcrumbsItem} from 'react-breadcrumbs-dynamic'

const Topic = ({ match, topic }) => (
  <div>
    <h3>
      {topic.title}
    </h3>

    <BreadcrumbsItem to={`${match.url}/${match.params.topicId}`}>
      {topic.title}
    </BreadcrumbsItem>

    ...
  </div>
)

就这样。这个答案中有一个更完整的例子。这是现场演示

于 2018-01-22T15:08:07.250 回答
1

这是为嵌套导航和面包屑提供单一事实来源的解决方案。

示例应用程序在 GitHub 上可用:https ://github.com/sneas/react-nested-routes-example

演示:https ://sneas.github.io/react-nested-routes-example/

导航配置:

export const navigation = [
  {
    path: "/",
    label: "All categories",
    content: () => <AllCategories />,
    routes: [
      {
        path: "/electronics",
        label: "Electronics",
        content: () => <Electronics />,
        routes: [
          {
            path: "/accessories",
            label: "Accessories",
            content: () => <Accessories />,
            routes: [
              {
                path: "/usb-cables",
                label: "USB cables",
                content: () => <UsbCables />
              }
            ]
          },
          {
            path: "/headphones",
            label: "Headphones",
            content: () => <Headphones />
          }
        ]
      }
    ]
  }
];

我们必须递归地展平导航并将其呈现为平面数组:

const routes = flattenRoutes(navigation);
return (<Router>
  {routes.map((route, index) => (
    <Route
      key={index}
      path={route.path}
      render={() => rouete.content}
    ></Route>
  ))}
</Router>);

然后用相同的导航结构构建面包屑。

于 2019-09-08T08:22:17.057 回答