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我正在通过 Appel 的“现代编译器在 ML 中实现”一书中生成 Tiger Parser 的 Ch3 编程练习。我的tiger.grm 文件在这里。我试图诊断的错误是由一元和二元减号运算符的规则引起的减少-减少冲突。这是 yacc 错误：

error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on OR
error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on AND
error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on GE
error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on GT
error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on LE
error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on LT
error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on NEQ
error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on EQ
error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on DIVIDE
error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on TIMES
error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on MINUS
error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on PLUS
error:  state 128: reduce/reduce conflict between rule 48 and rule 46 on RPAREN

state 128:

    boolean : exp . AND exp 
    boolean : exp . OR exp 
    arithmetic : MINUS exp .  (reduce by rule 46)
    arithmetic : exp . PLUS exp 
    arithmetic : exp . MINUS exp 
    arithmetic : exp MINUS exp .  (reduce by rule 48)
    arithmetic : exp . DIVIDE exp 
    arithmetic : exp . TIMES exp 
    comparison : exp . EQ exp 
    comparison : exp . NEQ exp 
    comparison : exp . GT exp 
    comparison : exp . LT exp 
    comparison : exp . LE exp 
    comparison : exp . GE exp

我已经定义了 UNARY 的优先级高于 MINUS，并在我的规则中使用%prec. 当然，当我删除任一规则时，冲突就会消失，但语法会错误地解析 MINUS 符号。

我无法诊断此错误 - 有什么想法吗？

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2 回答 2

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疯狂猜测：您的一条规则是否可能允许 anexp为空？如果是这样，那么这将在任何可选的地方产生歧义exp- 例如 before - exp。

于 2017-02-16T03:25:33.617 回答
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作为已接受答案的后续行动（他/她是对的） - 在生产允许exp进入的序列时出现错误epsilon。

这是有问题的代码（见最后一行）：

sequence : LPAREN exp_sequence RPAREN ()
exp_sequence : (*epsilon*) ()
         | exp seq     ()

seq : (*epsilon*)                () (*an exp sequence can be empty*)
    | SEMICOLON exp exp_sequence () (*exps separated by semicolon*)

这是更正后的代码：

sequence : LPAREN exp_sequence RPAREN ()
exp_sequence : (*epsilon*) ()
             | exp seq     ()

seq : (*epsilon*)                () (*an exp sequence can be empty*)
    | SEMICOLON exp seq () (*exps separated by semicolon*)
于 2017-02-16T03:25:48.103 回答