1

大家好,我是堆栈溢出的新手,我需要帮助来缩短我的代码和对我创建的 html 排队系统的响应时间。

我需要修复我的排队系统:

  1. 如何在我的代码页中一次性进行多项查询,因为下面的代码太长了。

  2. 在我上传的代码中,有什么方法可以通过删除我的一些隐藏内容来缩短代码。

  3. 任何人都可以检查是否有其他方法可以使我的排队系统更快,因为它滞后很多。

  4. 我在显示页面中的闹钟没有播放请检查我是否遗漏了什么。

非常感谢您查看我的代码并帮助我缩短它。*sql 数据库位于#FILE 部分中。*顺便说一下,我使用 xampp 来使用该程序。

这是文件:https ://drive.google.com/file/d/0B83JUE9Lc3VIMXJOVnpvcmJmdGc/view?usp=sharing

我的查询的问题是太长了如何缩短它或如何使用语法来查询所有这些:

 // sql to delete a record 1
$sql = "DELETE FROM ticket";
mysqli_query($con, $sql);

$sql2 = "DELETE FROM queue";
mysqli_query($con, $sql2);

$sql3 = "ALTER TABLE `queue` AUTO_INCREMENT=1";
mysqli_query($con, $sql3);

// sql to delete a record 2
$sql4 = "DELETE FROM ticket2";
mysqli_query($con, $sql4);

$sql5 = "DELETE FROM queue2";
mysqli_query($con, $sql5);

$sql6 = "ALTER TABLE `queue2` AUTO_INCREMENT=1";
mysqli_query($con, $sql6);

// sql to delete a record 3
$sql7 = "DELETE FROM ticket3";
mysqli_query($con, $sql7);

$sql8 = "DELETE FROM queue3";
mysqli_query($con, $sql8);

$sql9 = "ALTER TABLE `queue3` AUTO_INCREMENT=1";
mysqli_query($con, $sql9);

// sql to delete a counter
$sql10 = "DELETE FROM counter";
mysqli_query($con, $sql10);

$sql11 = "ALTER TABLE `counter` AUTO_INCREMENT=1";
mysqli_query($con, $sql11);

$sql12 = "INSERT INTO `counter`(`id`, `counternumber`, `counternumber2`, `count`) VALUES (null,1,1,0)";
mysqli_query($con, $sql12);

$sql13 = "INSERT INTO `counter`(`id`, `counternumber`, `counternumber2`, `count`) VALUES (null,1,2,0)";
mysqli_query($con, $sql13);

$sql14 = "INSERT INTO `counter`(`id`, `counternumber`, `counternumber2`, `count`) VALUES (null,1,3,0)";
mysqli_query($con, $sql14);

$sql15 = "INSERT INTO `counter`(`id`, `counternumber`, `counternumber2`, `count`) VALUES (null,2,1,0)";
mysqli_query($con, $sql15);

$sql16 = "INSERT INTO `counter`(`id`, `counternumber`, `counternumber2`, `count`) VALUES (null,2,2,0)";
mysqli_query($con, $sql16);

$sql17 = "INSERT INTO `counter`(`id`, `counternumber`, `counternumber2`, `count`) VALUES (null,2,3,0)";
mysqli_query($con, $sql17);

$sql18 = "INSERT INTO `counter`(`id`, `counternumber`, `counternumber2`, `count`) VALUES (null,3,1,0)";
mysqli_query($con, $sql18);

$sql19 = "INSERT INTO `counter`(`id`, `counternumber`, `counternumber2`, `count`) VALUES (null,3,2,0)";
mysqli_query($con, $sql19);

$sql20 = "INSERT INTO `counter`(`id`, `counternumber`, `counternumber2`, `count`) VALUES (null,3,3,0)";
mysqli_query($con, $sql20);
4

0 回答 0